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		<title>Excel question from Bob (i&#x27;m running out of private msg)</title>
		<link>https://www.lotterypost.com/thread/330922</link>
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		<description>Lottery Post Forum Topic: Excel question from Bob (i&#x27;m running out of private msg)</description>
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			<title>Reply #7</title>
			<link>https://www.lotterypost.com/thread/330922/6200988</link>
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			<pubDate>Sat, 15 Feb 2020 23:51:19 GMT</pubDate>
			<dc:creator>Bob</dc:creator>
			<description><![CDATA[<p>Hi ED,<br /><br />Thank you it is working super...It was my fault<br /><br />that it wasnt working right ...OK got it going<br /><br />thanks to you...<br /><br />bob</p>]]></description>
			<category>Bob</category>
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			<title>Reply #6</title>
			<link>https://www.lotterypost.com/thread/330922/6200951</link>
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			<pubDate>Sat, 15 Feb 2020 23:12:47 GMT</pubDate>
			<dc:creator>Bob</dc:creator>
			<description><![CDATA[<p>Hi ED,<br /><br />not working right...<br /><br />not listing right... anyway wanted it<br /><br />to work like<br /><br />all 389<br /><br />2398----2398<br /><br />3879----3879<br /><br />3890----3890<br /><br />thank you ....I know it is lots of work..<br /><br />butt Thank you ahead of time..<br /><br />bob</p>]]></description>
			<category>Bob</category>
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			<title>Reply #5</title>
			<link>https://www.lotterypost.com/thread/330922/6200886</link>
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			<pubDate>Sat, 15 Feb 2020 21:51:50 GMT</pubDate>
			<dc:creator>nibor200</dc:creator>
			<description><![CDATA[<p>Hey Bob,<br /><br />I didn&#x27;t know this was a rush item :)<br /><br />Here is what I&#x27;ve come up with (pick4 makes it more involved for a formula approach)<br /><br />put the 3 digit number in cell K1 and the following formula in cell B1 and copy and paste as far down in the B column as your data in the A column goes.<br /><br />=IF(LEFT(TEXT(A2, 0000 ),3)=TEXT($K$1, 000 ), TRUE TEXT(A2, 0000 ),IF(LEFT(TEXT(A2, 0000 ),1) RIGHT(TEXT(A2, 0000 ),2)=TEXT($K$1, 000 ), TRUE TEXT(A2, 0000 ),IF(LEFT(TEXT(A2, 0000 ),2) RIGHT(TEXT(A2, 000... &#x5b;&#xa0;<a href="https://www.lotterypost.com/thread/330922/6200886">More</a>&#xa0;&#x5d;</p>]]></description>
			<category>nibor200</category>
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			<title>Reply #4</title>
			<link>https://www.lotterypost.com/thread/330922/6200554</link>
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			<pubDate>Sat, 15 Feb 2020 17:21:33 GMT</pubDate>
			<dc:creator>Bob</dc:creator>
			<description><![CDATA[<p>anyone know how to change the EXCEL Formula????<br /><br />please do</p>]]></description>
			<category>Bob</category>
		</item>
		<item>
			<title>Reply #3</title>
			<link>https://www.lotterypost.com/thread/330922/6198843</link>
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			<pubDate>Thu, 13 Feb 2020 20:50:04 GMT</pubDate>
			<dc:creator>Bob</dc:creator>
			<description><![CDATA[<p>Yes PICK4 ...Sometimes it is a easy one to explain<br /><br />and than a hard one to explain the right way...<br /><br />so yes it is a Pick 4 looking for 3 digits....</p>]]></description>
			<category>Bob</category>
		</item>
		<item>
			<title>Reply #2</title>
			<link>https://www.lotterypost.com/thread/330922/6198787</link>
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			<pubDate>Thu, 13 Feb 2020 19:30:02 GMT</pubDate>
			<dc:creator>nibor200</dc:creator>
			<description><![CDATA[<p>Hey Bob,<br /><br />Could you reply with a specific numerical example of what you mean by find a 3 digits in a 4 number system?<br /><br />Do you mean Pick4?<br /><br />thanks,<br /><br />Ed S.</p>]]></description>
			<category>nibor200</category>
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			<title>Reply #1</title>
			<link>https://www.lotterypost.com/thread/330922/6198719</link>
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			<pubDate>Thu, 13 Feb 2020 18:33:48 GMT</pubDate>
			<dc:creator>Bob</dc:creator>
			<description><![CDATA[<p>Hi Ed,<br /><br />Bob -- You helped me out with excel<br /><br />a while back..Need help again if you have the time.<br /><br />.Right now the formula is<br /><br />for a 3 digit number finding 2 numbers.<br /><br />Butt we tried to change the formula to find 3 digits<br /><br />in a 4 number system...butt cant get it to work..<br /><br />was wondering if you could look at it and give us help??<br /><br />Hope we explained it right.<br /><br />the single formula below is expecting your data<br /><br />to be in column A and the digit<br /><br />you are looking for, to be in cell K1</p>]]></description>
			<category>Bob</category>
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		<item>
			<title>Excel question from Bob (i&#x27;m running out of private msg)</title>
			<link>https://www.lotterypost.com/thread/330922</link>
			<guid isPermaLink="true">https://www.lotterypost.com/thread/330922</guid>
			<pubDate>Thu, 13 Feb 2020 17:03:04 GMT</pubDate>
			<dc:creator>nibor200</dc:creator>
			<description><![CDATA[<p>Bob,<br /><br />1. We need to handle this request and any future others by open forum topics as I&#x27;m a Standard level member here so my private msg capability is limited and then I&#x27;ll not be able to read any more of them.<br /><br />2. Regarding your recent request ...<br /><br />Could you make<br /><br />a formula for the 4 digit that will<br /><br />match 3 numbers?<br /><br />We tried to change<br /><br />the 2 digit formula that you gave us<br /><br />for the 3 digit...<br /><br />=IF(LEFT(TEXT(A1, 000 ),2)=TEXT($K$1, 00 ), TRUE TEXT(A1, 000 ),IF(LEFT(TEXT(A1... &#x5b;&#xa0;<a href="https://www.lotterypost.com/thread/330922">More</a>&#xa0;&#x5d;</p>]]></description>
			<category>nibor200</category>
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