My new idea needs reality to win

Reply #5

garyo1954 — Sun, 12 Mar 2023 21:08:04 GMT

Good point.

I was looking at the back digit work I've done for the 435, charts I haven't spent any time on, and noticed different set type produce a different frequency throughout the matrix. This is something to look at undertaking this 5/1 plan.

For example in the 435 the four of a kind back digit sets 1111 to 5555 all show 1 hit. (6666 to 9999 are impossible in a 35 ball game)

Then you have the 3 of a kind plus 1, like 0001, 1112, 1222, 2223, 2333, ect. , that show from 3 to 16... [ More ]

Reply #4

ah1963 — Sat, 11 Mar 2023 17:30:55 GMT

No more than 2 numbers with common last digit appears in each draw, occasionally you will see 3.

Reply #3

garyo1954 — Sat, 11 Mar 2023 17:19:03 GMT

Sounds like a plan.

G

Reply #2

Hungus — Sat, 11 Mar 2023 12:26:08 GMT

So my idea is to make a wheel of 5/5 of 10 numbers and play with those last numbers. for example i have the numbers 2 4 5 8 9 i will play 02,12,22,32,42, 04, 14,24,34,44, 05,15,25,35,45,08,18,28, 38,48,09,19,29,39,49

Reply #1

garyo1954 — Fri, 10 Mar 2023 07:33:50 GMT

Breaking down the 6/49 by the total number of individual back digits in each combination.....

1 0

2 8316 0.06%

3 462000 3.30%

4 3696000 26.43%

5 6930000 49.56%

6 2887500 20.65%

So just shy of half of the 13983816 combinations contains 5 different back digits.

In larger sets, like 6/54 you'll start seeing combinations that contain one back digit:

1 11 21 31 41 51

2 12 22 32 42 52

3 13 23 33 43 53

4 14 24 34 44 54

G

My new idea needs reality to win

Hungus — Thu, 09 Mar 2023 08:25:46 GMT

Let's look at the following set of numbers 03, 25, 27, 31, 45, 49. pay attention only the last digits are 3,5,7,1,5,9, we see most of the time there will be 5/ 10 digits will be in 1 lottery result (0.1.2.3.4.5.6.7.8.9). my idea is how many combinations will guarantee 5/10