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		<title>super pi grid system</title>
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			<title>Reply #5</title>
			<link>https://www.lotterypost.com/thread/352742/7749773</link>
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			<pubDate>Sun, 29 Dec 2024 16:18:04 GMT</pubDate>
			<dc:creator>lakerben</dc:creator>
			<description><![CDATA[<p>I&#x27;m using this.</p>]]></description>
			<category>lakerben</category>
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			<title>Reply #4</title>
			<link>https://www.lotterypost.com/thread/352742/7728621</link>
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			<pubDate>Mon, 02 Dec 2024 20:35:34 GMT</pubDate>
			<dc:creator>Booyah B</dc:creator>
			<description><![CDATA[<p>Ok Mr.Lee thank I will give it a try.</p>]]></description>
			<category>Booyah B</category>
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			<title>Reply #3</title>
			<link>https://www.lotterypost.com/thread/352742/7727966</link>
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			<pubDate>Sun, 01 Dec 2024 23:18:19 GMT</pubDate>
			<dc:creator>lakerben</dc:creator>
			<description><![CDATA[<p>This would be good to put in excel. Good job brock.</p>]]></description>
			<category>lakerben</category>
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			<title>Reply #2</title>
			<link>https://www.lotterypost.com/thread/352742/7727862</link>
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			<pubDate>Sun, 01 Dec 2024 20:19:49 GMT</pubDate>
			<dc:creator>Brock Lee</dc:creator>
			<description><![CDATA[<p>no problem. so the first time i did the procedure i got 520.63083320433. what i did was calculate the value<br /><br />(520.63083320433 + pi) x sqrt2 = 740.72606824532<br /><br />and then i put the 72606824532 in my second line. then i calculated the value<br /><br />(740.72606824532 + pi) x sqrt2 = 1051.98773465398<br /><br />and i put the 98773465398 on the third line. and then i just kept going like that. any method that makes a 7 by 11 grid you can call a 7-11 method. the good thing about these big grids is you can fi... &#x5b;&#xa0;<a href="https://www.lotterypost.com/thread/352742/7727862">More</a>&#xa0;&#x5d;</p>]]></description>
			<category>Brock Lee</category>
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			<title>Reply #1</title>
			<link>https://www.lotterypost.com/thread/352742/7727811</link>
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			<pubDate>Sun, 01 Dec 2024 19:20:14 GMT</pubDate>
			<dc:creator>Booyah B</dc:creator>
			<description><![CDATA[<p>Hi Brock, you said keep doing this with each new #. How do you determine what the new # is? I&#x27;m unfamiliar with the 7-11 method.</p>]]></description>
			<category>Booyah B</category>
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			<title>super pi grid system</title>
			<link>https://www.lotterypost.com/thread/352742</link>
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			<pubDate>Sun, 01 Dec 2024 17:00:32 GMT</pubDate>
			<dc:creator>Brock Lee</dc:creator>
			<description><![CDATA[<p>this is a grid system that actually works. first take your starting number, let&#x27;s say 365. first you add pi, then multiply by the square root of 2, then take the first 11 digits after the decimal point as the first line of your grid.<br /><br />(365 + pi) x sqrt2 = 520.63083320433<br /><br />then you keep doing this procedure with each new number you get, until you get 7 lines of a grid. some people also call this the 7-11 method. like this:<br /><br />63083320433<br /><br />72606824532<br /><br />98773465398<br /><br />17820473596<br /><br />7015... &#x5b;&#xa0;<a href="https://www.lotterypost.com/thread/352742">More</a>&#xa0;&#x5d;</p>]]></description>
			<category>Brock Lee</category>
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