BIG GAME ODDS

Reply #8

JAP69 — Mon, 19 Nov 2001 22:22:16 GMT

Thank you for all your replies.HAVE A NICE DAY JAP69

Reply #7

RJOh — Mon, 19 Nov 2001 11:26:19 GMT

I was wrong. Since there are 2,118,760 combinations of 5 in 50 numbers, if JAP69 played all 36 bonus with the same combination of five, his chances of matching winning combination would be 1:2,118,760. Where I got confused was looking at the chart with the 36 bonus numbers on it. It calculates that 1 correct combination of 5 with the correct bonus number will win, while the other 35 correct combinations of 5 with the other bonus numbers will not win, making the odds of have 5 of 5 with wrong bon... [ More ]

Reply #6

Guest — Sun, 18 Nov 2001 22:13:42 GMT

Yeah, that's true.

Reply #5

JAP69 — Sun, 18 Nov 2001 14:36:33 GMT

If I were to wheel say 10 numbered white balls that would be a great idea.THANK YOU JAP69

Reply #4

RJOh — Sun, 18 Nov 2001 01:57:14 GMT

While it is true if you played the same combination of five with each of the 36 bonus ball you would reduce your odds of winning the jackpot to 1:2,179,296, you would reduce your odds to 1:2,118,760 if you play a different combination with each of those 36 bonus ball. Something to think about. Good luck to you.RJOh

Reply #3

JAP69 — Sat, 17 Nov 2001 20:57:07 GMT

Thank you Todd.Have a nice day JAP69

Reply #2

Todd — Sat, 17 Nov 2001 20:10:02 GMT

By buying each of the 36 possible Big Money Ball numbers, you'd effectively be removing the BMB from the odds calculation. Therefore, your odds of winning the jackpot would be 1 in 2,179,296. This assumes that the first 5 numbers are the same for each of the 36 tickets you buy. -Todd

Reply #1

Guest — Sat, 17 Nov 2001 17:12:09 GMT

You'd be playing $36 of tickets, since there are 36 gold balls. Your odds of winning the jackpot would be the lower figure you quoted. Right, Todd

BIG GAME ODDS

JAP69 — Sat, 17 Nov 2001 13:59:43 GMT

THE POSTED ODDS FOR THE BIG GAME ARE 76,275,360 TO 1IF I WERE TO PLAY THE EXACT SAME NUMBERS SAY 1-2-3-4-5 OF 5 WHITE BALLS ON 36 TICKETS WITH A DIFFERENT NUMBERED BIG MONEY BALL ON EACH TICKET WOULD NOT MY ODDS BE REDUCED TO 2,179,296 TO 1 OR 76,275,324 TO 1 ?IT SEEMS TO ME THAT IT WOULD COST ME 76,275,360 DOLLARS TO PLAY THE 2,179,296 COMBINATIONS OF WHITE BALLS.HAVE A NICE DAY,JAP69