Re: Formula for nobody winning is ((N-1)/N)^T where N is ...

Reply #2

Guest — Fri, 19 Apr 2002 20:16:27 GMT

Ok. Let's assume that 10 tickets are sold and the game is that you have to pick a number between 1 and 10 so that the odds for each ticket are 1 in 10. You're assuming that, say, somebody picks the number 5, then none of the other players can then pick that number. When you go in to buy lottery tickets, the computer doesn't spit back the ticket because that combination of numbers has already been selected.

Reply #1

CASH Only — Fri, 19 Apr 2002 19:16:30 GMT

and/or quick-picks are available.

Re: Formula for nobody winning is ((N-1)/N)^T where N is ...

Gamma Ray — Fri, 19 Apr 2002 17:08:09 GMT

Reply to Joe Schmoe's 4/17/2002 8:02:05 PM ET messageYour formula is creative, but I don't think it is correct!Assume there is a lottery with 1/10 odd of win (9/10 Odd of lose), and suppose 10 different tickets sold (all combinations). With your formula, chance of nobody win= ((N - 1)/N)^T= ((10 -1)/10^10= 0.347In simple logic, the winning ticket is sold. It is because all possible patterns sold. Therefore, the formula is false!Please participate and solve this math problem!Original Message:A fe... [ More ]