theory awaiting for a confirmation

Reply #23

crowdeg — Thu, 26 Feb 2004 07:29:24 GMT

did you notice on that list that theres always a number that will come out again

Reply #22

crowdeg — Thu, 26 Feb 2004 07:25:35 GMT

why not just play on 6/42? minus 7 numbers

Reply #21

PeaceMaker — Tue, 24 Feb 2004 14:43:06 GMT

Actually, that idea is in standby! I'm studying a new one! lol It consists in putting out of contest a large quantity of numbers (that won't come out)... Unfortunately, i've only managed to take out 11 numbers that didn't come out. It means that instead of playing with 49 numbers, i play with 38... it's the best i can do so far...I've been practicing this idea and, in theory, i can take out 34 numbers (actually my best attempt was 39 numbers)...Good luck to you all

Reply #20

OpenMinded — Mon, 23 Feb 2004 16:33:20 GMT

I tried Peacemaker's idea for Saturday's Powerball and I got one number right (26). Peacemaker, maybe this theory will work, but with a few more additions. Let us know if you come up with anything.

Reply #19

BobP — Mon, 26 Jan 2004 05:15:24 GMT

Quote: Originally posted by neorage on January 25, 2004 DreamLotto, just a thought:I always got the impression (at least from my local lottery) that numbers that were picked in the last drawing were not likely to reappear in the very next drawing. Also, choosing numbers that have been very hot (appearing a lot recently) and ones that are very cold (numbers that are due ) each makes sense in their own right... except that those criteria are on opposite extremes. The larger the game, the le... [ More ]

Reply #18

DreamLotto — Sun, 25 Jan 2004 15:08:54 GMT

Right NeoRage,But what I meant was MIX them with the numbers you got to mix the HOT numbers with the numbers you got got Numbers remaining: 2/7/10/16/18/22/31/32/35/42/47/48A situation would arise whereby the numbers will be favorable to play...for some decent win

Reply #17

neorage — Sun, 25 Jan 2004 07:42:46 GMT

DreamLotto, just a thought:I always got the impression (at least from my local lottery) that numbers that were picked in the last drawing were not likely to reappear in the very next drawing. Also, choosing numbers that have been very hot (appearing a lot recently) and ones that are very cold (numbers that are due ) each makes sense in their own right... except that those criteria are on opposite extremes.

Reply #16

DreamLotto — Sun, 25 Jan 2004 06:42:44 GMT

Sounds interestingHey let me pitch in and add something here:Numbers remaining: 2/7/10/16/18/22/31/32/35/42/47/48Now after this step, you should actually ADD back at least THREE numbers that are VERY HOT since the FIRST draw + Those that DID not appear for last 10 draws + a couple from the past draw!!Now you should AGAIN pass this new set through an ideal sieve to arrive at a playable set!! Some sort of addition/elimination should repeatedly continue for certain number of steps until you arr... [ More ]

Reply #15

BobP — Sun, 25 Jan 2004 05:42:33 GMT

I think he is trying to nbs

Reply #14

tdempsey — Sat, 24 Jan 2004 18:27:37 GMT

I'm confused - exactly what is being eliminated in the example?Tom

Reply #13

luckycat — Sat, 24 Jan 2004 13:27:31 GMT

peacemaker have u more info as to your method thanks

Reply #12

RJOh — Wed, 21 Jan 2004 13:49:11 GMT

PeaceMaker,If all six numbers are among the final 15 numbers, your odds of winning the jackpot is 1:5005. Good luck to you. When you win your theory will be confirmed.RJOh

Reply #11

PeaceMaker — Wed, 21 Jan 2004 06:58:02 GMT

Quote: O

Reply #10

BobP — Wed, 21 Jan 2004 05:03:44 GMT

Quote: Originally posted by PeaceMaker on January 20, 2004 Thanks reddog!lets focus only on the numbers:14,21,26,30,34,4120,24,27,30,38,411,8,13,23,41,4913,15,26,45,46,493,7,15,33,36,491,5,19,23,28,3910,20,26,30,38,447,9,20,28,29,3119,21,24,33,43,4912,27,34,41,43,49 19,21,42,43,44,456,21,28,29,30,363,6,20,37,39,406,11,16,32,34,395,12,17,28,34,4415,25,30,33,36,454,10,15,38,40,414,9,11,36,41,4913,39,42,44,45,48The combination we are about to study is: 7,10,32,42,47,48.What we must have is a progra... [ More ]

Reply #9

luckycat — Wed, 21 Jan 2004 04:12:46 GMT

peacemaker:

if this will help here is OHIO 6/49 last 10 draws I did not put bonus ball in there because it is derived from th original 49.

jan17-----3-6-11-15-16-49.............................................................................................................

jan 14.---1,18,29,32,37,41

jan 10----7,16,19,23,32,46

jan7------4,18,26,38,43,47

jan3------10,14,20,22,35,37

dec 31---13,22,35,36,41,46

dec27----6,10,28,30,40,43

dec24----16,22,32,34,37

dec 20

Reply #8

luckycat — Wed, 21 Jan 2004 03:39:20 GMT

PEACMAKER:you said you only needed 10 draws. I see where you did not use last draw to see if you could get it.u putt t hem in reverse.but and I think just deducted all the previouss drawn numbers,except the next to last draw. could u excplain better?thanks. sound very interesting thanks for shareing.

Reply #7

RJOh — Wed, 21 Jan 2004 02:10:19 GMT

Looks like you are backward engineering how you should have picked the winner after you know the winner, but most people want to know how to pick the winner before it is drawn. Good luck to you.RJOh

Reply #6

PeaceMaker — Tue, 20 Jan 2004 22:11:35 GMT

Thanks reddog!lets focus only on the numbers:14,21,26,30,34,4120,24,27,30,38,411,8,13,23,41,4913,15,26,45,46,493,7,15,33,36,491,5,19,23,28,3910,20,26,30,38,447,9,20,28,29,3119,21,24,33,43,4912,27,34,41,43,49 19,21,42,43,44,456,21,28,29,30,363,6,20,37,39,406,11,16,32,34,395,12,17,28,34,4415,25,30,33,36,454,10,15,38,40,414,9,11,36,41,4913,39,42,44,45,48The combination we are about to study is: 7,10,32,42,47,48.What we must have is a program that can eliminate the right combinations. The numbers in... [ More ]

Reply #5

reddog — Tue, 20 Jan 2004 21:27:26 GMT

This is Lotto South which is a 6/49 Lotto1/17/20047,10,32,42,47,48color=#800080 Detailscolor=#0000ff Broadband| color=#0000ff Dial-Up1/14/200413,39,42,44,45,48color=#0000ff Detailscolor=#0000ff Broadband| color=#0000ff Dial-Up1/10/20044,9,11,36,41,49color=#0000ff Detailscolor=#0000ff Broadband| color=#0000ff Dial-Up1/7/20044,10,15,38,40,41color=#0000ff Detailscolor=#0000ff Broadband| color=#0000ff Dial-Up1/3/200415,25,30,33,36,45color=#0000ff Detailscolor=#0000ff Broadband| color=#0000ff Dial-Up... [ More ]

Reply #4

PeaceMaker — Tue, 20 Jan 2004 21:05:00 GMT

reddog: 10 will do perfectly. it's only to explain my theory.

Reply #3

reddog — Tue, 20 Jan 2004 20:42:39 GMT

Peacemaker, do you mean you need 100 past draws from a 6/49 Lotto

Reply #2

PeaceMaker — Tue, 20 Jan 2004 19:38:30 GMT

luckycat: that link doesn t work.This is the deal:we've got 100 combinations (6/49);we will consider the most recent as the first;the numbers of the combination that will come out this week should have the numbers that 30 of the 100 previous combinations don't...If i get any feedback from you i'll explain more (if i can)...

Reply #1

luckycat — Tue, 20 Jan 2004 18:58:27 GMT

peace maker:any data you need can be got on web.example . www.usa lottery.com will have all usa games in all states. OHIO STATE has 6/49 game/ also pick5. at usa lottery you can find the big games like mega ball ect.being u are from another country, I think you will be able to get the data if not let me know. green bucks to you

theory awaiting for a confirmation

PeaceMaker — Tue, 20 Jan 2004 17:03:24 GMT

Can anyone send to me an excel workbook with 100 sets of 6/49 lotto numbers?I have this theory that I would like to share with all of you but I need some data...It envolves something that I've never seen in any site or book ...