* New MEMBER here - Discrete Math help *

Reply #17

mathNewbie — Tue, 25 May 2004 16:52:38 GMT

Yep. Thanks rdarmond

Reply #16

rdarmand — Tue, 25 May 2004 16:50:11 GMT

Hi, mathNewbie,That's the diagram I used.If you want to use Win D's approach, just assign the value x to subset g. Then: in d write 70-x ; in e write 50-x ; in f write 45-x.'Then ...You know that Circle 1 = 285 = a + d + f + g. So, a = 285 - (d + f + g). Since d = 70-x; f = 45-x; g = x, substituted these values for d, f g, then simplify: a = 285 - [(70-x) + (45-x) + x] = 170 + x. Use the same approach to get b = 75 + x c = 20 + x.Now, since you know that the sum of all seven subsets is... [ More ]

Reply #15

mathNewbie — Tue, 25 May 2004 12:37:03 GMT

Ok guys. A lot of co

Reply #14

rdarmand — Tue, 25 May 2004 04:29:36 GMT

Win D,The nice thing about your approach is that it only uses one unknown variable -- more direct. If I were teaching, I think I'd actually prefer it. I'd draw the circles on the blackboard, then fill them in with quantities, e.g. 70-x instead of assigning the variable d .Nice conceptualization.

Reply #13

WIN D — Tue, 25 May 2004 03:35:59 GMT

No. Actually what I did was not eat supper first. But now thats done and Ive looked at my formula, what I did was not take x out of 70, 45, and 50. I did not assume football hockey meant football hockey only (hard to do in a Venn diagram). Therefore, in my original message, the 285-70-45-x=170-x should have been285-(70-x)-(45-x)-x=170+x. 195-70-x-50 should have been 195-(70-x)-(50-x)-x=75+x. And 115-45-50-x should have been 115-(45-x)-(50-x)-x=20+x. Then adding all seven together, you ge... [ More ]

Reply #12

rdarmand — Tue, 25 May 2004 02:20:49 GMT

Win D,I'd prefer t

Reply #11

mathNewbie — Tue, 25 May 2004 02:03:18 GMT

Oh wow. Those are some very interesting responses. :D I will use rdarmand's approach and see if I can figure this thing out. The solution rdarmand presented seems to be it. Let me draw the venn diagram and see. Thanks for the help folks. Will let u know if I goof up somewhere. ;) mathNewbie

Reply #10

rdarmand — Tue, 25 May 2004 01:39:56 GMT

But he didn't say d = 70.

Reply #9

rdarmand — Tue, 25 May 2004 00:58:49 GMT

P.S. to MathNewbie

Reply #8

WIN D — Tue, 25 May 2004 00:49:11 GMT

OK, Kid, you've pissed me off now. LOL It's like one of those songs somebody in front of you starts whistling, then the song sticks with you all day. So, if by How many people watch exactly one of the three games? you mean how many watch one game, and one game only:180 watch only football; 85 watch only hockey; 30 watch only basketball.Use a Venn diagram ... it's the only way. Of the 285 watching F, subtract the 70 H+F, the 45 F+B, and the x where all three circles overlap (285-70-45-x=170-x... [ More ]

Reply #7

Colin F — Mon, 24 May 2004 21:53:04 GMT

mathnewbieThe newsgroup is alt.sci.math.probability. Be warned (to all) they don't manage to screen out the porn purveyors. On the other hand if you are accidently confronted with undesired images while pursuing your love of mathematics how can your partner blame you? (As a young man I only read Playboy for the serious articles it contained.)I haven't looked at it for a while but I did just now and who did I notice in the throng? Why none other than Ion Saliu throwing his weight about amongst th... [ More ]

Reply #6

OpenMinded — Mon, 24 May 2004 20:23:03 GMT

Yeah, Win D - just thought about it. It would be 450 that watch at least one.

Reply #5

WIN D — Mon, 24 May 2004 19:55:11 GMT

Wild guess .... A. 450 B. 450 The answers can't ever exceed 450.....so figure both are safe off the top of my head ....without doing the overlaps....and just cancel out.

Reply #4

datamatx — Mon, 24 May 2004 19:05:15 GMT

why do they call it discreet math

Reply #3

mathNewbie — Mon, 24 May 2004 18:57:44 GMT

I dont know the answer OpenMinded. Cud u please be kind enough to post the working of the solution as well? :( I am pretty bad at math and this is working proof. Waiting for ur response. mathNewbie

Reply #2

OpenMinded — Mon, 24 May 2004 18:10:48 GMT

Oops - let me change that to 500 watch exactly one of the three games. Whew! How did I do, mathNewbie?OpenMinded

Reply #1

OpenMinded — Mon, 24 May 2004 18:09:56 GMT

Shucks! I'll be the first to try my hand at this one. I'll say that 5 people watch all the games and 595 people watch exactly one of the three games. What's my score mathNewbie? Trying to keep the dust off my brain - OpenMinded

* New MEMBER here - Discrete Math help *

mathNewbie — Mon, 24 May 2004 17:05:05 GMT

Hello Math wizards, I am not even sure if this is the right place to post this question but I am gonna do it anyway. I am a first year bachelor''s student and we are currently doing DISCRETE MATHEMATICS. I need help with the following question and I wish you people will be kind enough to help me out OR guide me to the right place to ask it. Thanks! ------------------------------------------------------------------------------ A survey of 500 T. V. watchers produced th... [ More ]