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		<title>Texas 5/28 Midday China Method</title>
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		<description>Lottery Post Forum Topic: Texas 5/28 Midday China Method</description>
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			<title>Reply #3</title>
			<link>https://www.lotterypost.com/thread/88304/212514</link>
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			<pubDate>Fri, 28 May 2004 20:17:38 GMT</pubDate>
			<dc:creator>CalifDude</dc:creator>
			<description><![CDATA[<p>Texas Midday = 961 ... as txpolo pointed out, that is a BOX win for the modified chart.  I missed the Key # and it is still an EVEN sum, but hopefully some of you had the winning number. Modified 3829 (Row A) 5761 (Row B) 0346 (Row C</p>]]></description>
			<category>CalifDude</category>
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			<title>Reply #2</title>
			<link>https://www.lotterypost.com/thread/88304/212495</link>
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			<pubDate>Fri, 28 May 2004 19:02:45 GMT</pubDate>
			<dc:creator>txpolo</dc:creator>
			<description><![CDATA[<p>Your Modified Chart had the winning number 916.</p>]]></description>
			<category>txpolo</category>
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			<title>Reply #1</title>
			<link>https://www.lotterypost.com/thread/88304/212431</link>
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			<pubDate>Fri, 28 May 2004 15:41:00 GMT</pubDate>
			<dc:creator>joyjoy8</dc:creator>
			<description><![CDATA[<p>Thanks Dude................Good Luck today.........Joy</p>]]></description>
			<category>joyjoy8</category>
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			<title>Texas 5/28 Midday China Method</title>
			<link>https://www.lotterypost.com/thread/88304</link>
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			<pubDate>Fri, 28 May 2004 09:10:08 GMT</pubDate>
			<dc:creator>CalifDude</dc:creator>
			<description><![CDATA[<p>Key #: 7 0358 (Row A) 8427 (Row B) 7619 (Row C) Modified 3829 (Row A) 5761 (Row B) 0346 (Row C)Take one digit from each row to make up your 3-digit number.  If you do all of them, you will come up with 64 tickets (4X4X4 = 64). The  modified  rows are modified sequence for this state only and are designed to maximize your chance of a straight.Tip: Play an ODD sum.  To reduce the number of tickets, play only those numbers with the Key # 7 in them.</p>]]></description>
			<category>CalifDude</category>
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