Need a little help, I do.

Reply #14

LANTERN — Thu, 29 Jul 2004 15:51:03 GMT

BowlDogYou know you can use The Atrasoft to get the 6 to 8 digitsper position first, then use P34 Lotto to Wheel them and to do a little filtering and last but not least, use The Crunch by MikeK to filter the numbers (combos) real good.That would be the best thing to do (Maybe) You know I would like to know more about your gaps and how to use them, it's a new idea to me and sounds very interesting if you don't want too many people to know, there is always the private message(s).Good Luck.... [ More ]

Reply #13

bowldog — Wed, 28 Jul 2004 01:36:01 GMT

I think I'm going to go with Attrasoft Predictor for the time being. I've got about an hour before I have to get my tickets. If I have time to post the plays I will.

Reply #12

LANTERN — Mon, 26 Jul 2004 15:38:04 GMT

I might be wrong, but it seems to me, that it would be best for you to get both the old and the new CRUNCH from MikeK and use them to reduce your picks to whatever ammount that you want, first use P34 Lotto to learn about using filters and then use the NEW CRUNCH 2to get your winning number with.To tell you about the New Crunch is the best help that I can give to you right now.You can still finish explaining your system if you want.If so, do it step by step with samples, it would be easier to un... [ More ]

Reply #11

LANTERN — Mon, 26 Jul 2004 00:45:26 GMT

BowlDogThank you, now I understand how you get all the gap numbers from gap 1 to gap 6 also 195 was the last day draw that came out and 550 is the oldest draw of the ten listed, but now I think that I was wrong when I said that the gap numbers are numbers that you eliminate from the 1000 pick 3 numbers, it seems like you want to apply the filters and or combo reduction system to all the combined gap numbers, you say that you want to eliminate about 450 to 500 gap numbers.But the following does n... [ More ]

Reply #10

bowldog — Sun, 25 Jul 2004 20:46:44 GMT

If you look at the draw(456) you take each position digit and subtract from each position digit 1 draw back to get the gap1 column. Position 1(4 - 4 = 0); Position 2(5 - 1 = 4); Position 3(6 - 6 =0) thus 040 for Gap1. To get the gap2 column draw(456) you take each position digit and subtract from each position digit 2 draws back for the gap2 column. Position 1(4 - 7 = 7); Position 2(5 -5 = 0); Position 3(6 - 5 = 1) thus 701 for gap2. I hope this helps!755416 Gap1 Gap2 456 040 701

Reply #9

CalifDude — Sun, 25 Jul 2004 09:16:42 GMT

Bowldog,If I understand you correctly, you want a list of 500 numbers that you can play and hit a straight 85% of the time. Well, if that is correct, here are the money figures:500 tickets @ 1 each = $500 per play100 plays = 100 X $500 = $50,000 invested85% winners = 85 winning tickets @ $500 = $42,500Your system would be 85% accurate (better than most of us would even claim!) and would lose $7,500.What am I missing

Reply #8

LANTERN — Sun, 25 Jul 2004 08:34:53 GMT

No it does not, it does not make any sense or means any thing to me just pick 3 numbers, how did you get them or from where did they come from, is this a sort of elimination matrix? and if yes, how do you get the numbersthat you are going to eliminate?Since you don't explain, you are the only one that understand this, that only thing that I think, is that the so called numbers under the gap must be numbers that you are going to eliminate from the 1000 pick3 straight numbers, but how you got them... [ More ]

Reply #7

bowldog — Sun, 25 Jul 2004 06:39:59 GMT

I hope this helps. Previous 10 draws Texas day.draws550907321166755416 Gap1 Gap2 Gap3 Gap4 Gap5 Gap6456 040 701 390 135 559 906920 574 514 275 864 609 023480 560 034 074 735 324 169195 715 275 749 789 440 039

Reply #6

LANTERN — Sat, 24 Jul 2004 23:57:37 GMT

BowlDogLong time no see, do you remember me?I told you about the Atrasoft predictor some time ago, I used to be Excalibur, but changed my handle.I want to know and understand about your gap thing or system, but so far I don't, maybe if you explained in more detail and if also gave some detailed step by step examples. If you do this maybe we can find a way to help you, or maybe I can find a way to help you once I know exactly whtat's going on, that is what you want and what you are doing and abou... [ More ]

Reply #5

bowldog — Sat, 24 Jul 2004 22:18:08 GMT

Using standard filters to reduce the numbers to play will not get the desired result of 500-550 numbers to play that could hit 85% of the time. It has to be an outside-the-box filter/system to produce the desired results. With some players on this forum claiming to make a living/profit on their own systems I would think they have something that could get us the desired results.Let me try and explain what I want to do with the system(if we can get one!). All systems should be back tested a minimu... [ More ]

Reply #4

BobP — Sat, 24 Jul 2004 08:13:51 GMT

Quote: Originally posted by bowldog on July 24, 2004I have several Pick3 software programs which all involve guesswork to achieve the results I'm looking for(500-550 numbers hit 85% of the time). I need to take the guesswork out by using a system/theory that is consistent at picking that many numbers. It would seem like it should be easy because you will lose money by playing that many numbers. So some member of this forum should have a system that works somewhere close to those numbers/percenta... [ More ]

Reply #3

bowldog — Sat, 24 Jul 2004 06:16:20 GMT

I have several Pick3 software programs which all involve guesswork to achieve the results I'm looking for(500-550 numbers hit 85% of the time). I need to take the guesswork out by using a system/theory that is consistent at picking that many numbers. It would seem like it should be easy because you will lose money by playing that many numbers. So some member of this forum should have a system that works somewhere close to those numbers/percentages requested.

Reply #2

BobP — Sat, 24 Jul 2004 05:50:04 GMT

Quote: Originally posted by bowldog on July 24, 2004Is there a system/theory(Pick-3) that can do the following:Produce a list of 500-550 numbers that would hit at least 85% of the time you play.Not exactly, but this might help. Visit the Lottery Software Directoryhttp://www.lotto-logix.com/lottosoft.htmland scroll down to P3/4 Lotto, click that and download the free demo.With a little bit of luck and work you sould be able to find the 500-550 or so draws that won more often in the last 1,000 dr... [ More ]

Reply #1

RJOh — Sat, 24 Jul 2004 05:25:03 GMT

The odds of having a straight hit in pick3 are 1:1000 which pays $500 on a $1 bet in most State lotteries, so there's no advantage to playing 500 numbers or more to win. If you are interested in a box hit, you can cover every outcome with less than 250 combinations which pays less than $100 on a $1 bet. You need to know the odds and payout amounts to decide the amount of lines that are worth playing.RJOh

Need a little help, I do.

bowldog — Sat, 24 Jul 2004 05:01:41 GMT

Is there a system/theory(Pick-3) that can do the following:Produce a list of 500-550 numbers that would hit at least 85% of the time you play.