Well, im a lotto player from Brazil, and have been playing the MEGASENA game, most popular game here in Brasil. Its a pick 6 60 numbers with 4, 5 and 6 match win. The 6 match usually pays out around 1 to 25 million US dollars. So, after many tries, i have only hit a 5match win ONCE. and it was good for around 13K dollars.
What do I do? well.. firstoffall , i not a believer of cracking the lotto code or predicting numbers and things like that. I take the game to a absolute mathematical approach. I use my own wheels , i develop them using covermaster and sometimes i use Wheel generator because of the nice filter section it has.
So how can we actually increase our chance of winning the lottery?
To me there is only one way. ( but i would love to hear more from you guys)
I take a look for things that happens a lot in the lottery of my choice. Well, that seems pretty easy, but im not talking about betting on the number that hit the most.
Lets go for a math approach.
COLD NUMBERS ( numbers that have not been drawn in the past 10 drawings.)
ODD enough 1/3 of the time none of the 6 winning number drawn is from this category. In other words, all 6 numbers drawn for that particular week had hit at least once in the last 10 drawings.
But what does this means? Well. The COLD number category on a typical 6 /60 lottery usually represents 22 to 28 numbers, sometimes even more. This means that 1/3 of the time you play the lottery, you could simply not play any number from this category.
So if im able to discard completely 25 numbers from the 60 possible , i turn a
1 in 50,063,860 chance into a
1 in 1,623,160
ok, so to me this is a HUGE advantage. but 1 in 1.5 million still a lighting strike chance. So thats where a nice wheel system take place. I always AIM to 5 guaranteed win if 6 corrected (5 if 6)
But i know, 5 if 6 wheels are too expensive and few people can actually afford to spend money on lotteries nowadays.
So what i do is try to to play 80% guarantee wheels 5 if 6.
so lets see an example
To play a ( 18,6,5,6) requires 484 tickets
but to play a (18,6,5,6) with 80 % chance of having 5 win if 6 numbers are correct requires only 254 tickets ( maybe a little less with perfect optimization)
So , what are my chances of having the 6 winning numbers if i play 18 numbers in 35 total ? 1 in 87 . Which to me seens like extremally good odds as far as lottery goes.
Lets say you are willing to invest a tiny more an play 20 out of 35, now you have 1 in 41 chance of guessing the 6 winning numbers, And will have a guaranteed 5 if 6 prize 80% of the time.
If you do guess the 6 numbers correctly, then you have a 1.1% chance of hitting that monster prize that will turn you into a Millionaire. Well, 1% chance doesnt seem like much, but hey? who said winning the lottery jackpot is easy? so if you want to wheel you numbers to a 5 if 6, this table should give you an ideia of how many tickets you need to play "X" with 80 to 100% guaranteed.
But hey, 200, 400 tickets seems like a lot of money, i cant afford. Well, me neither. Thats why we play the lottery with a group of 20 people each one sharing 5% of the total pool. And we dont play every draw, but just the ones more likely to not have any cold number in it. I usually happens after 3 or 4 drawing tha contains a cold number. This year (2009) for example in 80 drawing the longest i ve seen a drawing with no COLD number hit was after 8 drawings . but usually happens after around 3 to 5 drawings.
Any thoughts,
|
100% |
95% |
90% |
85% |
80% |
18 |
484 |
398 |
333 |
288 |
254 |
19 |
683 |
552 |
462 |
401 |
353 |
20 |
850 |
748 |
625 |
541 |
476 |
21 |
1129 |
995 |
830 |
719 |
633 |
22 |
1513 |
1302 |
1084 |
937 |
823 |