I wouldn't call myself an expert at this stuff- just looking into wheeling a little. This is for Cash 5 game - or I guess it'd work with Mega/Powerball if you picked a 6th ball.
It's a key wheel where you pick 2 key numbers, 2 more pairs, and a set of 6 numbers. You pick 12 total numbers, it takes 36 combinations.
Key numbers - [A-B]
Pairs/Wheel 1 - {(C-D)(E-F)}
Wheel 2 - {G-H-I-J-K-L}
ABCDE
ABCDF
ABCDG
ABCDH
ABCDI
ABCDJ
ABCDK
ABCDL
ABCEF
ABDEF
ABEFG
ABEFH
ABEFI
ABEFJ
ABEFK
ABEFL
ABGHI
ABGHJ
ABGHK
ABGHL
ABGIJ
ABGIK
ABGIL
ABGJK
ABGJL
ABGKL
ABHIJ
ABHIK
ABHIL
ABHJK
ABHJL
ABHKL
ABIJK
ABIJL
ABIKL
ABJKL
I'm just trying to get the basics of wheeling down, did I forget any guarantees, or are any of them wrong?
A and B weren't drawn (You can only get 3 of 5 wins in this case)
-- If the winning numbers are within/have at least 3 of (CDEF) or (GHIJKL), you will have at least one 3 of 5 winner.
-- If 3 numbers are within (GHIJKL) or (CDEF), one 3 of 5.
-- If 4 numbers are within (GHIJKL) or (CDEF), four 3 of 5s.
-- If 5 numbers are within (GHIJKL), ten 3 of 5s.
-- If (CD) or (EF) are drawn, with any of (GHIJKL), the number of (GHIJKL) drawn determines amount of 3 of 5s.
A or B was drawn
-- With (CD) or (EF), then at least 7 3 of 5 wins.
-- With (CD) or (EF) and at least one of (GHIJKL), then at least one 4 of 5 win and several 3 of 5 wins.
-- With at least 2 of (CDEF), ? 3 of 5 wins... with 3 of (CDEF) at least one 4 of 5 win.
-- with at least 2 of (GHIJKL), several 3 of 5 wins... 3 or 4 of (GHIJKL) at least one win of 4 of 5.
A and B were both drawn
-- with (CD) or (EF), at least seven 4 of 5s.
-- with (CD) or (EF) and one of (GHIJKL), Jackpot and several 4 of 5s.
-- with at least 2 of (CDEF) several 4 of 5s.
-- with 3 of (CDEF), Jackpot, several 4 of 5s.
-- with at least 2 of (GHIJKL) several 4 of 5 wins.
-- with 3 of (GHIJKL) Jackpot, several 4 of 5s.
-- with 1 of (CDEF) and at least 1 one of (GHIJKL) at least 2 4 of 5s.
-- with at least one of (CDEF) and 1 of (GHIJKL) at least two wins of 4 of 5.