Offset9 System

Reply #10

sfilippo — Wed, 15 Mar 2006 00:27:35 GMT

Okay, I've come up with a simple way to do all of this in my head without all of the pencil work.

Below, is the final result which can be graphed on a numberline ranging between -10 and +10.

It's the final result which is what I'm looking for to create points on a graph to see what numbers are trending hotter and what numbers are trending colder.

0 = +2

1 = +1

2 = +6

3 = +1

4 = +3

5 = +3

6 = +3

7 = 0

8 = +3

9 = +4

In order to get to this result without having to do all... [ More ]

Reply #9

sfilippo — Tue, 14 Mar 2006 23:52:12 GMT

I agree, it's a difficult task to do this method. I'll try to come up with a quick way to get the final result.

Reply #8

calabs — Tue, 14 Mar 2006 18:24:48 GMT

Thank you sfilippo - Now that's some detailed workout you've developed there. It would be very helpful if a spreadsheet was developed that does the workout just by inputing the new draw and working from there (Anyone up for the challenge?). Paper and pencil is very time consuming!!! Tried a couple of draws in NJ, but was unsuccessful. Would like to do more.

Reply #7

sfilippo — Tue, 14 Mar 2006 11:15:16 GMT

- Previous Private Message -

Sent By : CWILSON

Hi CWILSON,

The intent of the Offset9 system is to isolate 5 of the possible 10 digits and to play those 5 digits in all combinations, giving the player 10 picks.

Example: List the last 9 winning draws for the Pick 3 game you wish to test it on.

730

250

003

446

781

349

261

315

117

Now, figure the offsets for each pick by listing the digits (plus 1 and minus 1) for each individual digit.

Example: Offsets for 73... [ More ]

Reply #6

sfilippo — Sun, 12 Mar 2006 17:53:51 GMT

Well, 349 didn't bring 261. 349 was just 1/9th of the calculation. The other 8 picks and 349 together help to give a set of picks.

Just write down the last 9 winning draws of the state you want to test it on and leave room around the numbers to figure out what the offsets are.

If one of the numbers is 757 then the offsets would be...

6 and 8 for the first 7

4 and 6 for the 5

6 and 8 for the last seven

You do that for the last 9 draws and then make a list 0 thru 9 and add up the of... [ More ]

Reply #5

pacattack05 — Sun, 12 Mar 2006 17:43:11 GMT

I understand the first dark bold on the left, but can you please explain in a simple step by step from the beginning, what to do in layman's terms?

Thanx.

Reply #4

diamondjaxs — Sun, 12 Mar 2006 17:14:19 GMT

how did 349 bring 261, i understand the one up one down approach but it's kind of confusing,if the number is 757 how would i count that

Reply #3

sfilippo — Sun, 12 Mar 2006 17:03:28 GMT

it was the next draw from Oklahoma's Pick 3

and the next draw after 2 6 1 was 3 1 5 (last night) which brings us to the current time.

The system uses the last 9 draws, so each day the player would delete one draw from the top of the list as he adds the most current draw to the botton of the list, then make a new calculation.

BTW, the system did not produce the winner 3-1-5. But I don't think it will bat above .500 anyway.

If it bats at .350 or so, I would call it a system worth u... [ More ]

Reply #2

diamondjaxs — Sun, 12 Mar 2006 16:58:23 GMT

where did the 261 come from s

Reply #1

MADDOG10 — Sun, 12 Mar 2006 16:22:02 GMT

Impressive, keep up the good work...

Offset9 System

sfilippo — Sun, 12 Mar 2006 16:13:37 GMT

Hi,

I believe I've come up with an original system idea.

Instead of analyzing the previous 10 draws with the concept of each of the three hoppers having the chance to get at least one hit for each of the ten balls, then trying to figure out what the eleventh draw might be, how about a system that analyzes the last 9 draws, then trying to figure out what the 10th or next draw will be. That would complete a set of 10 draws and give a chance for each ball to show up.

I have made a graphic... [ More ]