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		<title>Probability of a Canadian 6/49 rollover</title>
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			<title>Reply #1</title>
			<link>https://www.lotterypost.com/thread/137882/642267</link>
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			<pubDate>Sat, 08 Jul 2006 16:01:44 GMT</pubDate>
			<dc:creator>Just6ntlc</dc:creator>
			<description><![CDATA[<p>I think the probability of winning the jackpot is around 50% dvidva by my estimate.</p>]]></description>
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			<title>Probability of a Canadian 6/49 rollover</title>
			<link>https://www.lotterypost.com/thread/137882</link>
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			<pubDate>Sat, 08 Jul 2006 04:07:38 GMT</pubDate>
			<dc:creator>dvdiva</dc:creator>
			<description><![CDATA[<p>Need help figuring out what the probability of a rollover on the Canadian 6/49 game is at the 20 million level. I&#x27;m guessing that it won&#x27;t roll over anyways and they won&#x27;t bother doing a bonus draw if someone wins.<br /><br />Its a 6/49 game. Odds are 1:13,983,816. Cost per ticket is $2 for one line of play so the sales would have to be halved to give the cost as $1/play as in most US games.<br /><br />I figure the most likely  sales for this Saturday (prize is $21 Million) is $29 Million. Since this is over... &#x5b;&#xa0;<a href="https://www.lotterypost.com/thread/137882">More</a>&#xa0;&#x5d;</p>]]></description>
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