|Posted: July 8, 2006, 12:07 am - IP Logged|
Need help figuring out what the probability of a rollover on the Canadian 6/49 game is at the 20 million level. I'm guessing that it won't roll over anyways and they won't bother doing a bonus draw if someone wins.
Its a 6/49 game. Odds are 1:13,983,816. Cost per ticket is $2 for one line of play so the sales would have to be halved to give the cost as $1/play as in most US games.
I figure the most likely sales for this Saturday (prize is $21 Million) is $29 Million. Since this is over what double the odds are I'm curious what the possibility of a rollover is since it's not zero but has to be very low.
Further stats can be found at www.lotterycanada.com since they list the jackpot and the sales numbers.
6/7/2006 Sales: $35.7 Million Prize: $28 Million
6/3/2006 Sales: $24.4 Million Prize: $19.7 Million
4/8/2006 Sales: $28.5 Million Prize: $21.8 Million
1/21/2006 Sales: $29 Million Prize: $22.2 Million