need a help for probability

Reply #4

sysp34 — Tue, 19 Jun 2007 13:58:50 GMT

Bob, Fibonacci and johnph77

thank for responding

so the expectation hit remain the same according to xx number chosen.

for example if we choose

1579 = 35 boxed numbers (35/715 = 4.8951%) and 256 straight numbers (256/10000 = 2.56%)

1579

1157, 1159, 1179, 5517, 5519, 5579, 7715, 7719, 7759, 9915, 9917, 9957

1115, 1117, 1119, 5551, 5557, 5559, 7771, 7775, 7779, 9991, 9995, 9997

1155, 1177, 1199, 5577, 5599, 7799

1111, 5555, 7777, 9999

023468 = 126 boxed numbers (126/715

Reply #3

johnph77 — Tue, 19 Jun 2007 04:21:58 GMT

Using the numbers 023468, there will be 1296 combinations in a Pick 4 game which will contain those numbers and those numbers only. The range can be anywhere from 0000 to 8888.

With regard to the remaining numbers (1579) there are 256 combinations containing those numbers and those numbers only. Only those combinations will exclude the numbers 023468.

The other 8448 possible combinations will contain numbers from both groups.

gl

j

Reply #2

Fibonacci — Mon, 18 Jun 2007 10:52:44 GMT

I would suggest that you simply reprase the request, saying what you would like to do in simple English. Pls avoid the use of the words probablity probabilities etc.

The way to throw off a mathematician is to use his language when you may not be actually referencing the ideas behind the language.

Reply #1

CARBOB — Fri, 01 Jun 2007 15:51:21 GMT

Ragwi, PM Thoth or JadeLottery, both are very good with probabilities. There's probably many more on this forum, but I'm sure they will give you an answer.

need a help for probability

sysp34 — Fri, 01 Jun 2007 11:48:53 GMT

hello LP expert member,

i need a help to count probabilities of six numbers as one key numbers, because from default six numbers groups (210) we can track the consecutive hit.

for example this numbers 023468 have 268 consecutive hit in SG 4D as one key numbers (either in P1-P2-P3-P4) i though the probabilites would be 0.6 x 300 = 180 times is it?

just might be if we know the maximum hit (based on probabilities) i think we can use 1579 as next winning numbers with ABCD, AABC, ABAC, ABCA,... [ More ]