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# need a help for probability

Topic closed. 4 replies. Last post 10 years ago by sysp34.

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Heroic City
Indonesia
Member #31689
February 2, 2006
1153 Posts
Offline
 Posted: June 1, 2007, 7:48 am - IP Logged

hello LP expert member,

i need a help to count probabilities of six numbers as one key numbers, because from default six numbers groups (210) we can track the consecutive hit.

for example this numbers 023468 have 268 consecutive hit in SG 4D as one key numbers (either in P1-P2-P3-P4) i though the probabilites would be 0.6 x 300 = 180 times is it?

just might be if we know the maximum hit (based on probabilities) i think we can use 1579 as next winning numbers with ABCD, AABC, ABAC, ABCA, ABCB, ABCC, ABBC or we can twisted those number into straight position using hit and skip just might be we can catch pick 4 with one tickets and play for xx draws due to maximum hit

well anyone could help me to count the probabilities?

thank for any enlightenment

Et erunt signa in sole.......Et luna et stellis.......Et presura gentium
Prae confusione sonitus maris.

ORLANDO, FLORIDA
United States
Member #4924
June 3, 2004
5959 Posts
Online
 Posted: June 1, 2007, 11:51 am - IP Logged

hello LP expert member,

i need a help to count probabilities of six numbers as one key numbers, because from default six numbers groups (210) we can track the consecutive hit.

for example this numbers 023468 have 268 consecutive hit in SG 4D as one key numbers (either in P1-P2-P3-P4) i though the probabilites would be 0.6 x 300 = 180 times is it?

just might be if we know the maximum hit (based on probabilities) i think we can use 1579 as next winning numbers with ABCD, AABC, ABAC, ABCA, ABCB, ABCC, ABBC or we can twisted those number into straight position using hit and skip just might be we can catch pick 4 with one tickets and play for xx draws due to maximum hit

well anyone could help me to count the probabilities?

thank for any enlightenment

Ragwi, PM Thoth or JadeLottery, both are very good with probabilities. There's probably many more on this forum, but I'm sure they will give you an answer.

New York, NY
United States
Member #39471
May 16, 2006
2696 Posts
Offline
 Posted: June 18, 2007, 6:52 am - IP Logged

hello LP expert member,

i need a help to count probabilities of six numbers as one key numbers, because from default six numbers groups (210) we can track the consecutive hit.

for example this numbers 023468 have 268 consecutive hit in SG 4D as one key numbers (either in P1-P2-P3-P4) i though the probabilites would be 0.6 x 300 = 180 times is it?

just might be if we know the maximum hit (based on probabilities) i think we can use 1579 as next winning numbers with ABCD, AABC, ABAC, ABCA, ABCB, ABCC, ABBC or we can twisted those number into straight position using hit and skip just might be we can catch pick 4 with one tickets and play for xx draws due to maximum hit

well anyone could help me to count the probabilities?

thank for any enlightenment

I would suggest that you simply reprase the request, saying what you would like to do in simple English. Pls avoid the use of the words "probablity" "probabilities" etc.

The way to throw off a mathematician is to use his language when you may not be actually referencing the ideas behind the language.

\$\$\$

CA
United States
Member #2987
December 10, 2003
832 Posts
Offline
 Posted: June 19, 2007, 12:21 am - IP Logged

Using the numbers 023468, there will be 1296 combinations in a Pick 4 game which will contain those numbers and those numbers only. The range can be anywhere from 0000 to 8888.

With regard to the remaining numbers (1579) there are 256 combinations containing those numbers and those numbers only. Only those combinations will exclude the numbers 023468.

The other 8448 possible combinations will contain numbers from both groups.

gl

j

Blessed Saint Leibowitz, keep 'em dreamin' down there.....

Next week's convention for Psychics and Prognosticators has been cancelled due to unforeseen circumstances.

=^.^=

Heroic City
Indonesia
Member #31689
February 2, 2006
1153 Posts
Offline
 Posted: June 19, 2007, 9:58 am - IP Logged

Using the numbers 023468, there will be 1296 combinations in a Pick 4 game which will contain those numbers and those numbers only. The range can be anywhere from 0000 to 8888.

With regard to the remaining numbers (1579) there are 256 combinations containing those numbers and those numbers only. Only those combinations will exclude the numbers 023468.

The other 8448 possible combinations will contain numbers from both groups.

gl

j

Bob, Fibonacci and johnph77

thank for responding

so the expectation hit remain the same according to xx number chosen.

for example if we choose

1579 = 35 boxed numbers (35/715 = 4.8951%) and 256 straight numbers (256/10000 = 2.56%)

1579
1157, 1159, 1179, 5517, 5519, 5579, 7715, 7719, 7759, 9915, 9917, 9957
1115, 1117, 1119, 5551, 5557, 5559, 7771, 7775, 7779, 9991, 9995, 9997
1155, 1177, 1199, 5577, 5599, 7799
1111, 5555, 7777, 9999

023468 = 126 boxed numbers (126/715 = 17.6224%) and 1296 straight numbers (1296/10000 = 12.56%)

and digest all odd (1579) just show the trend after xxxx draws.

"critical hit" using SG 4D draws the trends shown it would be appear on Wed 06/20, 06/27, (after 56 times skip, 63 times skip) with 35 / 256 numbers to play :((

well thank agains for the info n good luck

Et erunt signa in sole.......Et luna et stellis.......Et presura gentium
Prae confusione sonitus maris.

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