The Pick 4 - 3 out of 4 system

Reply #13

CowboysFan — Mon, 23 Feb 2009 16:53:07 GMT

Ok thanks jayemmar for clearing that up for me.

Reply #12

jayemmar — Mon, 23 Feb 2009 16:49:55 GMT

Hi CowboysFan:

By consecutive pair we mean a pair whose digits differ by one.

jayemmar

Reply #11

jayemmar — Mon, 23 Feb 2009 16:45:54 GMT

Hi CARBOB:

The two pairs 12 and 67 are each consecutive pairs, as are (45-67) and (01-67). The idea is to find two pairs from the list:(01, 12, 23, 34, 45, 56, 67, 78, 89) such that no three numbers with in the two pairs occur in any of the past 20 draws.

From our tests it seems that at least three of the 4 numbers, in the pairs you select, will show up in one of the next 10 draws.

jayemmar

Reply #10

CowboysFan — Mon, 23 Feb 2009 16:43:12 GMT

Now that I read it again I think you're right. Thanks for your reply.

Reply #9

CARBOB — Mon, 23 Feb 2009 16:37:34 GMT

Not the way I read it.

If you look at the frequency statistics of consecutive pairs(01, 12, 23, 45, 56, 67, 78, 89)

He omitted 09 for some reason.

I read it as any 2 of consecutive pairs.

Reply #8

CowboysFan — Mon, 23 Feb 2009 16:33:56 GMT

Maybe I'm not understanding this correctly but if you use 12 then wouldn't you have to use 34 since that is consecutive? And if you also use 01 wouldn't you have to use 23

Reply #7

CARBOB — Mon, 23 Feb 2009 16:29:24 GMT

(12-67), (45-67), and (01-67). Two of these three aren't consecutive pairs .

Which pairs aren't consecutive

Reply #6

CowboysFan — Mon, 23 Feb 2009 16:20:49 GMT

You say to use two consecutive pairs for this system but in your Conn. example you use the pairs (12-67), (45-67), and (01-67). Two of these three aren't consecutive pairs so I was just wondering if you could explain. Thanks

Reply #5

CowboysFan — Mon, 23 Feb 2009 15:46:23 GMT

Thanks for sharing. I'm going to follow this in California to see how it works.

Reply #4

jayemmar — Mon, 23 Feb 2009 15:33:46 GMT

Hi Kimber:

If we pick the pairs 01-89, no three of these four numbers appear in any of the past 20 draws for this test set.

On Dec 23,'08 the number 8310 was drawn.

Again, sorry for this error.

jayemmar

Reply #3

jayemmar — Mon, 23 Feb 2009 15:27:12 GMT

Hi Kimber:

You are absolutely correct. This is a mistake, and we should have noticed that. Let me go back to this set of data and see if we could come up with another set of pairs that work.

Thanks for noticing this.

jayemmar

Reply #2

kimber528 — Sun, 22 Feb 2009 06:09:33 GMT

Thanks for sharing..I'm not sure if I'm getting this right, though..or, reading it right...you say where no three out of the 4 numbers, in those pairs, appear... In the Ga example, though, I see three of the 4 numbers (6-7-8) appear (i've bolded).

...2. Find 2 consectuive pairs from the list (preferably all different digits, for example don't choose 1223), where no three out of the 4 numbers, in those pairs, appear in any of the any of the last 20 draws.

Georgia

The past 20 draws... [ More ]

Reply #1

LAVERNE MALONEY — Sun, 22 Feb 2009 01:18:04 GMT

Thanks for sharing your system. I look for 3 out of 4 digits as well it can be profitable

The Pick 4 - 3 out of 4 system

jayemmar — Mon, 16 Feb 2009 16:17:22 GMT

Hello:

Here's a very consistent system that will often identify at least 3 out of the 4 numbers in at least one of the next 10 upcoming draws.

If you look at the frequency statistics of consecutive pairs(01, 12, 23, 45, 56, 67, 78, 89) for the P4, you'll find that they appear somewhere between 60% - 80% of the time within a draw. This system is based on that statistic.

Here are the rules:

1. Consider the last 20 draws of the P4 you are playing.

2. Find 2 consectuive pairs from the... [ More ]