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# The Pick 4 - 3 out of 4 system

Topic closed. 13 replies. Last post 8 years ago by CowboysFan.

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United States
Member #7437
October 3, 2004
383 Posts
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 Posted: February 16, 2009, 11:17 am - IP Logged

Hello:

Here's a very consistent system that will often identify at least 3 out of the 4 numbers in at least one of the next 10 upcoming draws.

If you look at the frequency statistics of consecutive pairs(01, 12, 23, 45, 56, 67, 78, 89) for the P4, you'll find that they appear somewhere between 60% - 80% of the time within a draw. This system is based on that statistic.

Here are the rules:

1. Consider the last 20 draws of the P4 you are playing.

2. Find 2 consectuive pairs from the list (preferably all different digits, for example don't choose 1223), where  no three out of the 4 numbers, in those pairs,  appear in any of the any of the last 20 draws.

3.  In the next 10 draws, there's a good chance that at least three of the four numbers you chose will appear in at least one of the 10 future draws.

Examples:

For the test, we chose the P4 in Massachusetts, Georgia, and Connecticut. For the 20 day period we chose

Nov. 29, '08  to Dec. 18, '08.

The past 20 draws for Mass. were:

2148
9693
2613
5622
4715
7559
4083
7565
5458
9185
0858
1962
7588
1810
9094
7329
4286
2130
9006
0099

For the two consecutive pairs we chose 67 and 89, since no three numbers belonging to these pairs showed up in the last 20 draws. Eight days later(Dec. 26,'08), the number 7688 was drawn.

Georgia

The past 20 draws for the test period were:

7824
2168
2340
7813
2459
3133
7490
7379
6219
7648
6836
3731
9564
6167
9221
5159
2290
0594
4976
6106

We chose the same pair sets 67 and 89 as in the Mass. case, and on Dec.25,' the number 8729 was drawn.

Ct.

This one is very interesting. The past draws for the test period were:

7053
0462
6803
0289
1958
6997
2011
7808
5152
4279
1042
9779
7400
4470
7753
0142
2101
1902
3397
8057

In this scenario we noticed that were 3 sets of pairs that could be chosen to satisfy the rules:

(12-67), (45-67), and (01-67). On Dec. 19, 21, 23, and 24 the following numbers were drawn: 0546, 6410, 4456, and 2796.

The question that begs to be answered now is: How do we get the fourth digit to play? One way is to consider  for the fourth digit the other 6 that are left(for non-double box). This would result in 24 numbers for each set of pairs selected. Another strategy would be to limit the plays to doubles. Notice that in two of the three tests a double was drawn. In this scenario, there would be 12 boxed plays per pair set chosen. Since doubles usually pay more at the local candy store, this might be a profitable strategy.

jayemmar

United States
Member #1987
August 5, 2003
8968 Posts
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 Posted: February 21, 2009, 8:18 pm - IP Logged

Thanks for sharing your system. I look for 3 out of 4 digits as well & it can be profitable!

United States
Member #66928
November 11, 2008
174 Posts
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 Posted: February 22, 2009, 1:09 am - IP Logged

Thanks for sharing..I'm not sure if I'm getting this right, though..or, reading it right...you say "where no three out of the 4 numbers, in those pairs, appear..."  In the Ga example, though, I see three of the 4 numbers (6-7-8) appear (i've bolded).

"...2. Find 2 consectuive pairs from the list (preferably all different digits, for example don't choose 1223), where  no three out of the 4 numbers, in those pairs,  appear in any of the any of the last 20 draws.

Georgia

The past 20 draws for the test period were:

7824
2168
2340
7813
2459
3133
7490
7379
6219
7648
6836
3731
9564
6167
9221
5159
2290
0594
4976
6106

We chose the same pair sets 67 and 89 as in the Mass. case, and on Dec.25,' the number 8729 was drawn..."

am I not understanding this correctcly?

United States
Member #7437
October 3, 2004
383 Posts
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 Posted: February 23, 2009, 10:27 am - IP Logged

Hi Kimber:

You are absolutely correct. This is a mistake, and we should have noticed that. Let me go back to this set of data and see if we could come up with another set of pairs that work.

Thanks for noticing this.

jayemmar

United States
Member #7437
October 3, 2004
383 Posts
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 Posted: February 23, 2009, 10:33 am - IP Logged

Hi Kimber:

If we pick the pairs 01-89, no three of these four numbers appear in any of the past 20 draws for this test set.

On Dec 23,'08 the number 8310 was drawn.

Again, sorry for this error.

jayemmar

Sunny California
United States
Member #63790
August 8, 2008
220 Posts
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 Posted: February 23, 2009, 10:46 am - IP Logged

Thanks for sharing. I'm going to follow this in California to see how it works.

Sunny California
United States
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August 8, 2008
220 Posts
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 Posted: February 23, 2009, 11:20 am - IP Logged

You say to use two consecutive pairs for this system but in your Conn. example you use the pairs (12-67), (45-67), and (01-67). Two of these three aren't consecutive pairs so I was just wondering if you could explain. Thanks!

ORLANDO, FLORIDA
United States
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June 3, 2004
5896 Posts
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 Posted: February 23, 2009, 11:29 am - IP Logged

You say to use two consecutive pairs for this system but in your Conn. example you use the pairs (12-67), (45-67), and (01-67). Two of these three aren't consecutive pairs so I was just wondering if you could explain. Thanks!

(12-67), (45-67), and (01-67). "Two of these three aren't consecutive pairs".

Which pairs aren't consecutive??

Sunny California
United States
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August 8, 2008
220 Posts
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 Posted: February 23, 2009, 11:33 am - IP Logged

Maybe I'm not understanding this correctly but if you use 12 then wouldn't you have to use 34 since that is consecutive? And if you also use 01 wouldn't you have to use 23?

ORLANDO, FLORIDA
United States
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June 3, 2004
5896 Posts
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 Posted: February 23, 2009, 11:37 am - IP Logged

Maybe I'm not understanding this correctly but if you use 12 then wouldn't you have to use 34 since that is consecutive? And if you also use 01 wouldn't you have to use 23?

Not the way I read it.

"If you look at the frequency statistics of consecutive pairs(01, 12, 23, 45, 56, 67, 78, 89)"

He omitted 09 for some reason.

I read it as any 2 of consecutive pairs.

Sunny California
United States
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August 8, 2008
220 Posts
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 Posted: February 23, 2009, 11:43 am - IP Logged

United States
Member #7437
October 3, 2004
383 Posts
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 Posted: February 23, 2009, 11:45 am - IP Logged

Hi CARBOB:

The two pairs 12 and 67 are each consecutive pairs, as are (45-67) and (01-67). The idea is to find two pairs from the list:(01, 12, 23, 34, 45, 56, 67, 78, 89)  such that no three numbers with in the two pairs occur in any of the past 20 draws.

From our tests it seems that at least three of the 4 numbers, in the pairs you select, will show up in one of the next 10 draws.

jayemmar

United States
Member #7437
October 3, 2004
383 Posts
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 Posted: February 23, 2009, 11:49 am - IP Logged

Hi CowboysFan:

By consecutive pair we mean a pair whose digits differ by one.

jayemmar

Sunny California
United States
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August 8, 2008
220 Posts
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 Posted: February 23, 2009, 11:53 am - IP Logged

Ok thanks jayemmar for clearing that up for me.

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