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		<title>Does anyone have the complete list of all the ABC combinations for Mega Millions?</title>
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		<description>Lottery Post Forum Topic: Does anyone have the complete list of all the ABC combinations for Mega Millions?</description>
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			<title>Reply #10</title>
			<link>https://www.lotterypost.com/thread/192630/1286714</link>
			<guid isPermaLink="true">https://www.lotterypost.com/thread/192630/1286714</guid>
			<pubDate>Thu, 23 Apr 2009 13:11:09 GMT</pubDate>
			<dc:creator>johnph77</dc:creator>
			<description><![CDATA[<p>No reason it can&#x27;t be done, except the files would be rather large. In what format would you prefer the listings? Do you want line numbers? Lexographic numbers? PM me with needs/preferences/requirements.<br /><br />I&#x27;m on the road right now so don&#x27;t expect any response until Thursday or Friday of next week.<br /><br />gl<br /><br />j</p>]]></description>
			<category>johnph77</category>
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			<title>Reply #9</title>
			<link>https://www.lotterypost.com/thread/192630/1286511</link>
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			<pubDate>Thu, 23 Apr 2009 02:55:49 GMT</pubDate>
			<dc:creator>steve33825</dc:creator>
			<description><![CDATA[<p>So is there anyone here who can generate the combinations? Once again, I&#x27;m not looking for the bonus numbers, i&#x27;m only looking for:<br /><br />A group (1-14)<br /><br />B group (15-28)<br /><br />C group (29-42)<br /><br />Only the possible combinations involving those groups of numbers, no bonus/mega ball numbers.</p>]]></description>
			<category>steve33825</category>
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			<title>Reply #8</title>
			<link>https://www.lotterypost.com/thread/192630/1285777</link>
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			<pubDate>Wed, 22 Apr 2009 13:27:38 GMT</pubDate>
			<dc:creator>time*treat</dc:creator>
			<description><![CDATA[<p>The A, B, C are the labels steve33825 was using to identify the 3 groups he was pulling numbers from.<br /><br />The numbers in those columns are how many out of 14 are being used at one time; each group has 14 numbers<br /><br />The A(n), B(n), C(n) represent the number of ways to take 1, 2, or 3 objects from 14.<br /><br />14 choose 1 = 14. 14 choose 2 = 91. 14 choose 3 = 364<br /><br />Those numbers are then multiplied to get the totals (last column)<br /><br />He has six different arrangements he wants to try, so there are six row... &#x5b;&#xa0;<a href="https://www.lotterypost.com/thread/192630/1285777">More</a>&#xa0;&#x5d;</p>]]></description>
			<category>time*treat</category>
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			<title>Reply #7</title>
			<link>https://www.lotterypost.com/thread/192630/1285765</link>
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			<pubDate>Wed, 22 Apr 2009 13:07:36 GMT</pubDate>
			<dc:creator>DixieJoe</dc:creator>
			<description><![CDATA[<p>Unfortunately not</p>]]></description>
			<category>DixieJoe</category>
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			<title>Reply #6</title>
			<link>https://www.lotterypost.com/thread/192630/1285709</link>
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			<pubDate>Wed, 22 Apr 2009 12:14:49 GMT</pubDate>
			<dc:creator>azares</dc:creator>
			<description><![CDATA[<p>What are A, B, C, A(n), B(n), C(n)? How did you arrive with totals. Thanks.<br /><br />fred</p>]]></description>
			<category>azares</category>
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			<title>Reply #5</title>
			<link>https://www.lotterypost.com/thread/192630/1285676</link>
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			<pubDate>Wed, 22 Apr 2009 10:49:35 GMT</pubDate>
			<dc:creator>time*treat</dc:creator>
			<description><![CDATA[<p>The good news is that someone may be able to code it, depending on which programming language you use.<br /><br />The bad news is that the 71,344 takes into account only using the first 42 numbers and not incluing the bonus ball. That is only for the first group.<br /><br />A B C A(n) B(n) C(n) Totals<br /><br />1 1 3 14 14 364 71,344<br /><br />1 2 2 14 91 91 115,934<br /><br />1 3 1 14 364 14 71,344<br /><br />2 2 1 91 91 14 115,934<br /><br />2 1 2 91 14 91 115,934<br /><br />3 1 1 364 14 14 71,344<br /><br />total -- 561,834</p>]]></description>
			<category>time*treat</category>
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			<title>Reply #4</title>
			<link>https://www.lotterypost.com/thread/192630/1285628</link>
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			<pubDate>Wed, 22 Apr 2009 06:37:47 GMT</pubDate>
			<dc:creator>RJOh</dc:creator>
			<description><![CDATA[<p>Last night&#x27;s winning numbers 05 24 37 47 52 +06 is ABCDD or 1A 1B 1C 2D. All the letters in my chart just represent the 5 core numbers. If you have the last 400 MM combinations in a text file then you can replace the numbers with letters using a text editor in a program like NotePad which would make this:<br /><br />02/06/09 - 02 12 18 28 31 +03<br /><br />02/10/09 - 18 29 38 43 47 +07<br /><br />02/13/09 - 25 36 37 40 51 +20<br /><br />02/17/09 - 01 09 23 27 33 +24<br /><br />02/20/09 - 21 28 41 45 55 +24<br /><br />02/24/09 - 01 27 28 35 4... &#x5b;&#xa0;<a href="https://www.lotterypost.com/thread/192630/1285628">More</a>&#xa0;&#x5d;</p>]]></description>
			<category>RJOh</category>
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			<title>Reply #3</title>
			<link>https://www.lotterypost.com/thread/192630/1285626</link>
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			<pubDate>Wed, 22 Apr 2009 06:22:57 GMT</pubDate>
			<dc:creator>steve33825</dc:creator>
			<description><![CDATA[<p>oops im sorry I actually meant the ABC combos WITHOUT the mega/sixth number. Only combos with the 5 regular numbers, not the extra sixth/mega one. No D group, just ABC. Is there anyone on here that can generate it? Because I&#x27;m unable to find a free number generator that can do that.</p>]]></description>
			<category>steve33825</category>
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			<title>Reply #2</title>
			<link>https://www.lotterypost.com/thread/192630/1284606</link>
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			<pubDate>Tue, 21 Apr 2009 11:22:27 GMT</pubDate>
			<dc:creator>RJOh</dc:creator>
			<description><![CDATA[<p>Several members have done something similiar. Early in my thread Developing a winning MegaMillions system I came up with this:<br /><br />THERE WERE 46 DIFFERENT STRINGS IN THE 399 DRAWINGS<br /><br />A = 1-14 B = 15-28 C = 29-42 D = 43-56<br /><br />1. AABCD = 32 32<br /><br />2. ABBCD = 27 59<br /><br />3. ABCDD = 27 86<br /><br />4. ABCCD = 19 105<br /><br />5. BCCDD = 16 121<br /><br />6. BBCDD = 15 136<br /><br />7. AABCC = 14 150<br /><br />8. AABDD = 14 164<br /><br />9. ABDDD = 14 178<br /><br />10. AAABC = 13 191<br /><br />11. AACDD = 12 203<br /><br />12. ACCDD = 12 215<br /><br />13. BBCCD = 12 227</p>]]></description>
			<category>RJOh</category>
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			<title>Reply #1</title>
			<link>https://www.lotterypost.com/thread/192630/1284588</link>
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			<pubDate>Tue, 21 Apr 2009 10:31:04 GMT</pubDate>
			<dc:creator>time*treat</dc:creator>
			<description><![CDATA[<p>Well, there&#x27;s no shortage of insanity around here.<br /><br />To your main point, such lists could be generated but probably not posted in a usable manner.<br /><br />Your first group 1A 1B 3C alone would have 14c1 * 14c1 * 14c3 combos. That&#x27;s 14 * 14 * 364, or 71,344 combos.<br /><br />That&#x27;s a lot of screen lines.</p>]]></description>
			<category>time*treat</category>
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			<title>Does anyone have the complete list of all the ABC combinations for Mega Millions?</title>
			<link>https://www.lotterypost.com/thread/192630</link>
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			<pubDate>Tue, 21 Apr 2009 06:17:54 GMT</pubDate>
			<dc:creator>steve33825</dc:creator>
			<description><![CDATA[<p>There was someone on here who kept posting updated charts of some kind of ABCD combinations for the mega millions (i.e. A consists of 1-14, B consists of 15-28, C consists of 29-42, D consists of 43-56). I can&#x27;t find the person or the thread it was in, i remember it was huge thread too. However, i was wondering if anyone had an already created list of all the possible A-B-C combos only which has all the numbers that fall into these categories:<br /><br />1A 1B 3C<br /><br />1A 2B 2C<br /><br />1A 3B 1C<br /><br />2A 2B 1C<br /><br />2... &#x5b;&#xa0;<a href="https://www.lotterypost.com/thread/192630">More</a>&#xa0;&#x5d;</p>]]></description>
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