Pick 3 digit elimination

Reply #6

LANTERN — Thu, 10 Dec 2009 09:45:36 GMT

Skips sample, last 30 skips, but not for numbers on above chart.

Reply #5

LANTERN — Thu, 10 Dec 2009 09:23:53 GMT

Stats of this kind might help

Also skips stats might help.

I might be wrong, but maybe every digit in the long run should hit an average of about 33% (Boxed), Is that right or not

Reply #4

Str8master — Thu, 10 Dec 2009 04:47:55 GMT

Anything better than random play is beating the odds in my opinion. Eliminate 2 digits and the 50% house edge is gone. It may just come down to good timing like Win D pointed out, but I'm looking through hit patterns, digit relationships, trailing numbers, etc to see if I can find some formula that even slightly beats picking two random digits out of thin air.

Reply #3

LANTERN — Thu, 10 Dec 2009 03:10:47 GMT

That you filter out almost half of the total numbers when you filter out 2 digits, that by itself shows that it is easier said than done.

That is because there are 3 positions on a pick 3 game.

Of course, it is not impossible to do.

The thing is, How often can it be done O.K.

Reply #2

WIN D — Wed, 09 Dec 2009 22:11:32 GMT

Why not subtract all 3 digits from the last draw each time you think the timing is right ?

Subtract all 3 digits and you filter out 657 numbers of the 1000.

You will be in the right side of the swimming pool ...... 1 out of every 3 draws.

Timing is the key..... but you won't have to worry with 657 numbers each time you do play.

34% of the time you will only have to play with the right 343 straight numbers .

.........and look

Thats only 35 single b... [ More ]

Reply #1

joker17 — Wed, 09 Dec 2009 20:51:02 GMT

Why not reduce your odds from 1000 down to 100?

If I like the number 38 in the back pair, then just do the following:

038

138

238

338

438

538

638

738

838

938

The first number is taken care of. The back pair is only 00-99, so only a hundred possibilities left.

You can further reduce the odds down to 50. If the back pairs are showing below 50 for 4 or 5 days in a row, play a number above 50, and vice versa. The 50 reduction is better not only because there is... [ More ]

Pick 3 digit elimination

Str8master — Wed, 09 Dec 2009 20:15:37 GMT

Has anyone come up with a good method for consistently eliminating one or two losing digits from your plays? I was looking at the numbers and tossing out just one bad digit reduces 1,000 straight combos down to 729. Throw out two digits and you're down to 512 combos.

There's only a max of 3 unique digits drawn from a field of 10 in any given draw, so that's at least 7 losing digits for each and every game. Statisically the odds are about 1 in 2 of successfully knocking out two digits so any m... [ More ]