Note that C(50,5,3,5)=C(26,5,3,3)+C(24,5,3,3)

because if you divide 50 numbers into 2 groups, then at least 3 of 5

numbers must be either in one or in another group. You can find

C(26,5,3,3) =260 and C(24,5,3,3) =231 Taking 2*C(25,5,3,3) =2*256=512 would be bigger, because 26 has a nice

symmetry.

So, obviously 17296 is far too much. But let s take a look at your

idea to take one number from [2..18], one from [6..36] and one from

[34..49]. This gives you 17*31*16... [ More ]]]>

Divided into two groups of 10

For the 3/3 that takes (10,3,3,3)=120

For the 2/3 that takes (10,3,2,3)=8

To make our Pick-6 combinations we'd have to pair up each of the 120 lines with each of the 8 for a total of 8 x 120 = 960 which is darn close to our 1154 lines, but not exactly and I'll tell you why.

Our new wheel is no... [ More ]]]>

But if I understand what you are sayingis that you'd split the field in half, and then play 2 seperate wheels, one 2 if 3 wheel and one 3 if 3 with it, I'm not a big fan of splittin the field of numbers you chose in half, but if you meant you were just playing two seperate wheels, the]]>

let s say the first 30 numbers in the Pick6/49 were going to play...

you use 2 wheels 1 from 1-15 pick3 abbreviated wheel the other from: 16-30 abbreviated wheel...

you could get a: 2/3 abbreviated wheel from: 1-15 and a 2/3 or 3/3 abbreviated wheel from: 16-30...

lets say the, 1-15 came out to: 20 tickets and the 16-30 came out to, 30 tickets...YOU THEN... [ More ]]]>