<?xml version="1.0" encoding="utf-8"?>
<rss version="2.0" xmlns:atom="http://www.w3.org/2005/Atom" xmlns:dc="http://purl.org/dc/elements/1.1/" xmlns:slash="http://purl.org/rss/1.0/modules/slash/" xmlns:wfw="http://wellformedweb.org/CommentAPI/">
	<channel>
		<title>A Different type of Wheel, Call it: Groups wheel or Sets wheel...</title>
		<link>https://www.lotterypost.com/thread/228067</link>
		<atom:link href="https://www.lotterypost.com/rss/topic/228067" rel="self" type="application/rss+xml" />
		<description>Lottery Post Forum Topic: A Different type of Wheel, Call it: Groups wheel or Sets wheel...</description>
		<dc:language>en-us</dc:language>
		<generator>Lottery Post RSS Generator</generator>
		<item>
			<title>Reply #3</title>
			<link>https://www.lotterypost.com/thread/228067/1966226</link>
			<guid isPermaLink="true">https://www.lotterypost.com/thread/228067/1966226</guid>
			<pubDate>Thu, 24 Feb 2011 16:32:39 GMT</pubDate>
			<dc:creator>dr san</dc:creator>
			<description><![CDATA[<p>pumpi 76=<br /><br />Note that C(50,5,3,5)=C(26,5,3,3)+C(24,5,3,3)<br /><br />because if you divide 50 numbers into 2 groups, then at least 3 of 5<br /><br />numbers must be either in one or in another group. You can find<br /><br />C(26,5,3,3) =260 and C(24,5,3,3) =231 Taking 2*C(25,5,3,3) =2*256=512 would be bigger, because 26 has a nice<br /><br />symmetry.<br /><br />So, obviously 17296 is far too much. But let s take a look at your<br /><br />idea to take one number from [2..18], one from [6..36] and one from<br /><br />[34..49]. This gives you 17*31*16... &#x5b;&#xa0;<a href="https://www.lotterypost.com/thread/228067/1966226">More</a>&#xa0;&#x5d;</p>]]></description>
			<category>dr san</category>
		</item>
		<item>
			<title>Reply #2</title>
			<link>https://www.lotterypost.com/thread/228067/1965996</link>
			<guid isPermaLink="true">https://www.lotterypost.com/thread/228067/1965996</guid>
			<pubDate>Thu, 24 Feb 2011 09:31:54 GMT</pubDate>
			<dc:creator>BobP</dc:creator>
			<description><![CDATA[<p>Let&#x27;s make it a little easier to discuss by working with 20 numbers for that 5/6 guarantee. That wheel would require 1,154 lines. (20,6,5,6)=1154<br /><br />Divided into two groups of 10<br /><br />For the 3/3 that takes (10,3,3,3)=120<br /><br />For the 2/3 that takes (10,3,2,3)=8<br /><br />To make our Pick-6 combinations we&#x27;d have to pair up each of the 120 lines with each of the 8 for a total of 8 x 120 = 960 which is darn close to our 1154 lines, but not exactly and I&#x27;ll tell you why.<br /><br />Our new wheel is no... &#x5b;&#xa0;<a href="https://www.lotterypost.com/thread/228067/1965996">More</a>&#xa0;&#x5d;</p>]]></description>
			<category>BobP</category>
		</item>
		<item>
			<title>Reply #1</title>
			<link>https://www.lotterypost.com/thread/228067/1965951</link>
			<guid isPermaLink="true">https://www.lotterypost.com/thread/228067/1965951</guid>
			<pubDate>Thu, 24 Feb 2011 05:37:22 GMT</pubDate>
			<dc:creator>Boney526</dc:creator>
			<description><![CDATA[<p>I&#x27;m sorry you&#x27;re going to have to explain this more clearly if you want anybody to understand it. There&#x27;s literally no possible way to have the same wheel that would regularly cost 4000 dollars for 600 dollars.<br /><br />But if I understand what you are sayingis that you&#x27;d split the field in half, and then play 2 seperate wheels, one 2 if 3 wheel and one 3 if 3 with it, I&#x27;m not a big fan of splittin the field of numbers you chose in half, but if you meant you were just playing two seperate wheels, the... &#x5b;&#xa0;<a href="https://www.lotterypost.com/thread/228067/1965951">More</a>&#xa0;&#x5d;</p>]]></description>
			<category>Boney526</category>
		</item>
		<item>
			<title>A Different type of Wheel, Call it: Groups wheel or Sets wheel...</title>
			<link>https://www.lotterypost.com/thread/228067</link>
			<guid isPermaLink="true">https://www.lotterypost.com/thread/228067</guid>
			<pubDate>Thu, 24 Feb 2011 04:55:37 GMT</pubDate>
			<dc:creator>pumpi76</dc:creator>
			<description><![CDATA[<p>lets use Pick6, let say you want to wheel, 30 numbers for a 5/6....It might costs you like, $4,000 i dont know i am just saying....<br /><br />let s say the first 30 numbers in the Pick6/49 were going to play...<br /><br />you use 2 wheels 1 from 1-15 pick3 abbreviated wheel the other from: 16-30 abbreviated wheel...<br /><br />you could get a: 2/3 abbreviated wheel from: 1-15 and a 2/3 or 3/3 abbreviated wheel from: 16-30...<br /><br />lets say the, 1-15 came out to: 20 tickets and the 16-30 came out to, 30 tickets...YOU THEN... &#x5b;&#xa0;<a href="https://www.lotterypost.com/thread/228067">More</a>&#xa0;&#x5d;</p>]]></description>
			<category>pumpi76</category>
		</item>
	</channel>
</rss>

