Repetition and skips explained

Reply #13

SergeM — Sat, 02 Jun 2012 15:08:58 GMT

Euromillions

Numbers:

3 skips 3 hits in x drawings?

Relative

frequency Frequency Count of

games

needed

0,02 48 3 to 7

0,09 206 8 to 12

0,13 296 13 to 17

0,15 357 18 to 22

0,14 333 23 to 27

0,11 262 28 to 32

0,10 245 33 to 37

0,08 185 38 to 42

0,05 112 43 to 47

0,03 81 48 to 52

0,02 41 53 to 57

0,03 64 58 to 62

0,01 35 63 to 67

0,01 19 68 to 72

0,01 20 73 to 77

0,00 10 78 to 82

0,00 7 83 to... [ More ]

Reply #12

SergeM — Tue, 22 May 2012 17:06:03 GMT

Pick 3 BE

History of 2963 drawings,

last 1000 drawings.

Skips before hit:

NOT = was not drawn before

NOT 92

0 1

-1 2

-2 1

-3 1

-6 2

-7 2

-8 2

-9 2

-11 1

-14 1

-18 1

-19 1

-21 2

-22 2

-23 1

-24 1

-25 2

-27 2

-29 1

-30 1

-31 1

-32 2

-33 2

-34 1

-35 4

-38 1

-39 1

-40 1

-41 1

-42 1

-43 1

-45 1

-48 1

-51 1

-53 1

Reply #11

jeankedemetser — Tue, 22 May 2012 10:15:36 GMT

Thanks for the interesting topic SergeM, I will have a look at it...

Reply #10

jeankedemetser — Tue, 22 May 2012 10:13:51 GMT

Lol, nice reply...

Reply #9

SergeM — Tue, 22 May 2012 00:15:36 GMT

This is different to the model. Third digit for 100 drawings.

Skips count

-55 1

-36 1

-32 1

-26 1

-23 2

-22 3

-20 1

-19 2

-18 2

-17 5

-15 1

-14 4

-13 3

-12 6

-11 2

-10 7

-9 3

-8 2

-7 5

-6 5

-5 7

-4 9

-3 4

-2 3

-1 9

0 11

Reply #8

SergeM — Mon, 21 May 2012 23:26:36 GMT

Pick 3

For 1 digit, p = 1/10

Skip 0: 0.1 1 in 10

Skip 1: 0.01 1 in 100

Skip 2: 0.001 1 in 1000

Skip 3: 0.0001 1 in 10000

...

For 2 digits, p = 1/100

Skip 0: 0.01 1 in 100

Skip 1: 0.0001 1 in 10 000

...

For 3 digits, p = 1/1000

Skip 0: 0.001 1 in 1000

Skip 1: 0.000 001 ...

Reply #7

SergeM — Thu, 17 May 2012 14:55:57 GMT

For repetitions, you might go further into probabilities.

For Keno 20/70, I calculated in Excel the odds for the count of numbers repeating.

Repetitions Odds

0 0,000291128440738996

1 0,003756496009535440

2 0,021188985303785800

3 0,069345770085117200

4 0,147359761430874000

5 0,215566279578879000

6 0,224548207894665000

7 0,169928373541909000

8 0,094466760291390200

9 0,038755593965698500

10 0,011723567174623800

11 0,0025994605708700... [ More ]

Reply #6

SergeM — Thu, 17 May 2012 10:48:57 GMT

If you wonder, how many repetitions do I expect? The average can be 1.2 for example, so you might expect one repetition.

With integers, you wouldn't talk about an average, but you would sum up the amount of repetitions by their count. Repetitions: 0:*1, 1:*10, 2:*2, 3:*0 ... . By calculating the weighted average, you should find a value close to the probability.

Reply #5

LottoBoner — Wed, 16 May 2012 01:12:27 GMT

2/7=0.28

Skip 0: average 20*(2/7)1 numbers. 20*0.28=5.6

Skip 1: average 20*(2/7)2 numbers. 20*0.28=5.6 (5.6)^2= 31.36

Skip 2: average 20*(2/7)3 numbers. (5.6)^3= 175.61

Skip 3: average 20*(2/7)4 numbers. (5.6)^4= 983.41

is this the correct calculation

Reply #4

SergeM — Mon, 14 May 2012 14:41:54 GMT

I am sure that a man with a doctor title can calculate this with paper and pencil.

Reply #3

dr san — Sun, 13 May 2012 22:37:33 GMT

Hello sergem on this lottery 50/5 eurominlhao If we divide the trio in a position to have 10 positions 1,2,3 1,2,4 1,2,5 2,3,4 2,3,5 ...... = 3,4,5 up the total are 10 position Sergem, how you could make or assemble a formula of probability Or within 10 positions of the suit, suit or have greater likelihood of left in a certain position, ie its frequency in repeats determicada position. example Suit 02,08,45 = the best position to place this suit? Sergem if we use certain fixed positions within

Reply #2

SergeM — Sun, 13 May 2012 21:10:50 GMT

That's a hard nut!

Picking the system to play and mixing the numbers is related to the payouts.

I pick my numbers using my own software . I will send you a few suggestions how you could play.

Reply #1

frenchie — Sun, 13 May 2012 19:21:43 GMT

Hi SergeM,

Talking about Keno 20/70 do you have a system for it ? I would be interrested.

Regards,

Serge.

Repetition and skips explained

SergeM — Fri, 11 May 2012 23:02:40 GMT

A repetition is a skip of 0 games.

For keno 20/70, 20 numbers are drawn, 50 numbers are not drawn. The chance is 20.

The chance for a repetition is 20/70 or 2/7. You can expect average 2/7*20 numbers to repeat.

Skip 0: average 20*(2/7)1 numbers.

Skip 1: average 20*(2/7)2 numbers.

Skip 2: average 20*(2/7)3 numbers.

Skip 3: average 20*(2/7)4 numbers.

...

With p = 20, n = 70: avg skip x = p*(p/n)1+x

Repetitions can vary from 0 to maximum 20 of 20 drawn numbers.

The ave... [ More ]