pick 3 separete, position

Reply #50

dr san — Fri, 21 Aug 2015 12:35:48 GMT

Hello, this matrix of 12 lines always 100%

LHello, this matrix of 12 lines always 100%

Less the digit zero in 1,2,3,4,5,6,7,8,9

9 digits always 100% in any US state

Will have a double digit

267

348

159

157

168

249

147

258

369

123

456

789

You can take the test in your state always 100% minus the digit zero

You have a double digit

Example 478 = this in 147

Another 464 = this in 456

Then the pair of digits that in all three positions. 1... [ More ]

Reply #49

RL-RANDOMLOGIC — Mon, 17 Aug 2015 22:50:16 GMT

And which IDE

Reply #48

CARBOB — Mon, 17 Aug 2015 10:23:01 GMT

What virus? Be more specific.

Reply #47

SergeM — Mon, 17 Aug 2015 09:48:33 GMT

Virus in the ide

Reply #46

RL-RANDOMLOGIC — Sun, 16 Aug 2015 19:36:07 GMT

Just when I thought I understood. I will reread the topic and take another shot at it.

I take it that it's for box hits only.

RL

Reply #45

RL-RANDOMLOGIC — Sun, 16 Aug 2015 19:14:35 GMT

SergeM

WHAT! I don't have a clue what your saying.

RL

Reply #44

dr san — Sat, 15 Aug 2015 23:54:44 GMT

hello, RL the 2nd option seems to be more affordable, ie

get a couple of digits in the remaining 7 of pick3

how can not repeat in position

21x2 = 42 and has three digits and knew not what, so soubemmos that any one of the three, then 42 times3 = 126

100%, just to repeat one of three digits not in the position accuracy is 100% without even a double filter of the remaining 7., and put without repeating the three is 7 conbinado 3 = 36 = 36 = 162 126 more taking the two conditions.

we... [ More ]

Reply #43

dr san — Sat, 15 Aug 2015 23:41:37 GMT

Hello, in the example 478

The digit 8 Paode not appear in 3rd because it is not for reptir the position in the vertical

The digit 8 this can only 1st and 2nd position for this is = 2 49 = 98

The digit 7 may not be so in the 2nd position, 1st and 3rd 49x2 = 49

The digit 4 can not be on the 1st vertically, can only aprecer in 2nd and 3rd position = 49x2 = 98

49x49x49 = 294

Reply #42

dr san — Sat, 15 Aug 2015 23:24:15 GMT

hello carbob. As things stand, there are 294 combinations, .

In the coding, I have not allowed more than one digit to be present from the previous draw, even if it is in a different position.

So e.g. starting with 137, all combinations with the '1' in the middle (n1n) do not contain 3 or 7 either, so that has filtered out quite a few formations.

In terms of further filtering, one possibility would be not to allow repeating digits (e.g. 010).

I've not done any analysis with P... [ More ]

Reply #41

SergeM — Sat, 15 Aug 2015 20:51:18 GMT

Boxed with digit 0 scoring 1 or 2 or 3: 271 combinations

000, 001, 002, 003, 004, 005, 006, 007, 008, 009, 010, 011, 012, 013, 014, 015, 016, 017, 018, 019, 020, 021, 022, 023, 024, 025, 026, 027, 028, 029, 030, 031, 032, 033, 034, 035, 036, 037, 038, 039, 040, 041, 042, 043, 044, 045, 046, 047, 048, 049, 050, 051, 052, 053, 054, 055, 056, 057, 058, 059, 060, 061, 062, 063, 064, 065, 066, 067, 068, 069, 070, 071, 072, 073, 074, 075, 076, 077, 078, 079, 080, 081, 082, 083, 084, 085, 086, 087,

Reply #40

dr san — Sat, 15 Aug 2015 19:07:53 GMT

Reply #39

CARBOB — Sat, 15 Aug 2015 19:00:14 GMT

Those were all the combos involving a single digit, straight.

The boxed combos for a single digit, 55 combos.

012, 013, 014, 015, 016, 017, 018, 019, 023, 024, 025, 026, 027, 028, 029, 034, 035, 036, 037, 038, 039, 045, 046, 047, 048, 049, 056, 057, 058, 059, 067, 068, 069, 078, 079, 089

001, 002, 003, 004, 005, 006, 007, 008, 009, 011, 022, 033, 044, 055, 066, 077, 088, 099

000

Reply #38

dr san — Sat, 15 Aug 2015 18:57:42 GMT

sergem 271 = = because the right is 294

where the condition or padroa is to repeat a digit out of position example 478 last draw 860 the digit 8 repeated in the 1st or 3rd out of position

here with 294 stakes and 100% acertava still lacked filters

Reply #37

SergeM — Sat, 15 Aug 2015 17:52:14 GMT

The moon shines or does not shine. You can always look out of the window.

Reply #36

SergeM — Sat, 15 Aug 2015 17:48:21 GMT

You may find an English dictionary at Barnes Noble.

Reply #35

SergeM — Sat, 15 Aug 2015 17:45:05 GMT

Acredjus!

All digits, boxed, containing at least one specified digit say d, can generate 271 unique, distinct boxed combinations.

Reference:

http://emuis.be/syst#h2_Pick3_positional

Reply #34

SergeM — Sat, 15 Aug 2015 17:35:31 GMT

@random logic

Since I had a Facebook chat downloader in a jar or exe, I wouldn't install any of those programs. Bite me once, I screw you until the end of times.

Reply #33

dr san — Sat, 15 Aug 2015 14:10:21 GMT

rl and Winsum, you guys have permission, to improve as you wish

the link planilia

objective to generate pick3 without repeating the position with some filters

Reply #32

dr san — Sat, 15 Aug 2015 13:35:21 GMT

hello RL e CARBOB

I've signed up to that site and uploaded a file you can work with. It has the code and all of the required formatting, so you can just replace the numbers there with yours (remember to select at least 13 rows).

You can also run the macro immediately by typing [CTRL]+[SHIFT]+[A]

Here's the link to it.

https://copy.com/wmHwdpjaMDNo24Vg

Reply #31

dr san — Sat, 15 Aug 2015 12:42:30 GMT

Ok, carbob, the 7 digits remaining closed or to find matching pairs have 21

The 3rd digit, comes from the last draw, and do not know has times3

21x3 = 63 bets hit Condition = just to give the pattern repeat of the last three digits of the sweepstakes on That 63 bet hits 100

Reply #30

CARBOB — Sat, 15 Aug 2015 12:29:23 GMT

Each digit creates 271 single combos, see image.

Reply #29

dr san — Sat, 15 Aug 2015 12:19:00 GMT

hello RL, can ask pro friends Winsum, to enable and improve macro to be able to use filters.

ie you type in a field excel in the last draw

macro is separate and assemble the filters of repetition for position! please.

Reply #28

dr san — Sat, 15 Aug 2015 12:12:31 GMT

In the meantime, you can experiment a bit because at the start, you are prompted to choose which filters you want to run and which you want to leave out.

Here's the latest version so far...

----------------------------------

Sub mFilterData()

Const DIALOG_BOX_TITLE = Pick 3 Filtering

'

Dim arrCurrPerm(2) As Byte

Dim arrMedDigits(9, 2) As Boolean

Dim arrPrevDraw(2) As Byte

Dim b As Byte

Dim b1 As Byte

Dim b2 As Byte

Dim b3 As Byte

Dim b10 As Byte... [ More ]

Reply #27

dr san — Sat, 15 Aug 2015 12:09:06 GMT

ok RL google translate poorly and inverts data, but calmly

It is to take the concept is quite easy.

7 digits conbinando by 2 = '21

Reply #26

dr san — Sat, 15 Aug 2015 11:16:41 GMT

Hello RL, compared to the last draw of pick3 we have 4 conditions

1. Repeats a digit

2- Repeat zero digit

3 Repeat two digits

4- digit Repete3 well here just play the same result

So let's focus on item 1 and 2 ok to be peers of 87% of the time the condition 1 and 2

Reply #25

RL-RANDOMLOGIC — Sat, 15 Aug 2015 11:14:45 GMT

dr san

The translation you are using is really bad so if you can give number examples as you did a couple post

back then it would be very useful. Many times the text is not readable in a logical order.

I started coding the project and should have it done in a week or so our as time permits.

RL

Reply #24

dr san — Sat, 15 Aug 2015 11:10:31 GMT

In the last 30 games for my noon there were 14 drawings without digit previous repeat

game. Well, this then we have 7 digits to close the pick3

Total is 35

example

= 123 retantes 0,4,5,6,7,8,9 7 = 3 = 35 times bets

Rl, we can do both options = not to repeat or one digit = 35apostas

And the other repeat a 63-digit = bets

We can do both conditions, and still see each filter

Reply #23

dr san — Sat, 15 Aug 2015 10:57:18 GMT

Hello, rl to get the double or couples remaining 7 digits the last

Example last =

123 =

7 remaining digits = is = 0,4,5,6,7,8,9

So closed seven digits to get doubles in 100% is 21 pairs =

So as we have three digits that any of the three will repeat

It has to do 21 times 3 = total 63 betting

The third digit, is one of three, for that is 21 times 3 = 63

Hit condition, has repeat a digit in the last

Not to hit = not repeat or repeat one or two

If repeat three just play... [ More ]

Reply #22

dr san — Sat, 15 Aug 2015 10:46:51 GMT

Hello, RL, ok any questions you can ask me, ok let's see the 2nd option

example

Last draw = 478 =

The remaining digits = 7 = 0,2,3,5,6,9,1

7 digit for digit conseguirduplas is 7 times 2 = 21

The third digit is the condition of repeating the last one digit

So 21vezes = 63, and you have bet 63 betting

Hit just 100% condition that the pattern repeat a digit in the last =

Example last gave = 478

The next draw gave 194

repeated 4

7 digits = 0,1,2,3,5,6,9 the remaining... [ More ]

Reply #21

RL-RANDOMLOGIC — Sat, 15 Aug 2015 09:23:28 GMT

dr san

The second option

As I see it we would need to take each of the 3 digits from the last game and pair up the other 9 digits

to cover a possible double.

There are 36 pairings of 9 digits.

Example last game = 2-5-8

1st sets = 2 + pairing digits (0-1-3-4-5-6-7-8-9) = 36 lines

2nd sets = 5 + pairing digits (0-1-2-3-4-6-7-8-9) = 36 lines

3rd sets = 8 + pairing digits (0-1-2-3-4-5-6-7-9) = 36 lines

Total lines = 108 ticket cost = $108.00 and a box hit pays $1... [ More ]

Reply #20

RL-RANDOMLOGIC — Sat, 15 Aug 2015 09:04:49 GMT

dr san

Not sure I understand the entire concept but I think I will attempt to code it and see what I come up with.

RL

Reply #19

dr san — Thu, 13 Aug 2015 11:39:30 GMT

hello rl, the Winsum could build excel in it? to pick3,4,

the digits and standards and their reps, so I type the last draw in a field, macro and shows conbina ao. condition of success = repeating one digit out of position the setting is 100% in 294 without filters

Reply #18

dr san — Thu, 13 Aug 2015 11:01:57 GMT

Hello,RL we have rl we have four basic conditions for the last draw of the pick 3 = repeat every three digits = ie play the same

* Repeats two digits = have a couple, not repeats or a digit

* And repeat the digit (our study) then repeat the digit in 68% to 100% giving this standard profit tremor

500-296 = we are spending a euro = 296 and we will win 500 = 204 profit

In stats you can see the reps in columns 5, or 10 or 20 draws

Where transiting the repetitions and its sweepstakes i... [ More ]

Reply #17

RL-RANDOMLOGIC — Thu, 13 Aug 2015 10:07:30 GMT

dr san

Do you have a copy of the DMP-DG that Winsum posted. I have another very old P3 program that may

help in what your doing, below is a pic. It might be adaptable to what your working on but not sure.

Looks interesting but I need to study it a little more.

RL

I converted this to qb64 a few years back but never got around to using it.

Reply #16

dr san — Thu, 13 Aug 2015 01:14:55 GMT

Hello river, problem with google translator

But the goal is not to repeat in the last position to the next

So we have a 96 digit times 3 digits not known what will repeat

96x = 3 = 294 at 100% here goes filters

Reply #15

river26 — Thu, 13 Aug 2015 00:14:07 GMT

the instructions are dificult to follow

Reply #14

dr san — Wed, 12 Aug 2015 20:46:13 GMT

Hello, we have 4 = theconcept conditions

HE HO LE LO Numbers

HE Numbers are (HighEven) - 6, 8 = 1

Numbers are HO (HighOdd) - 5, 7, 9 = 2

Numbers are CO (LowEven) - 0, 2, 4 = 3

Numbers are LO (LowOdd) - 1, 3 = 4

Always a standard of 1,2,3,4 will be out at 100%

1 = 6,8,5,7,9,0,2,4

2 = 5,7,9,0,2,4,1,3

5,7,9,1,3,6,8 = 3

6,8,0,2,4,1,3 4 =

In one of the four lines will be near 100% any sweepstakes draw =

Example = 478 = line 1 (6,8,5,7,9,0,2,4)

Always one of the

Reply #13

dr san — Wed, 12 Aug 2015 20:43:38 GMT

RL, also we can see the pattern repeats instead of the digit position

standards

Pairs / odd inside / outside high / low

example

456

182 in 3rd position repeated the standard pair = 0,2,4,6,8

Ie the repeti a of small patterns can ride it in a program?

Digits itself and also the repetition of patterns

Reply #12

dr san — Wed, 12 Aug 2015 20:36:09 GMT

He gave in 1837

These were the 4 previous to 1837

4896

5623

1530

9787

1837

Reply #11

dr san — Wed, 12 Aug 2015 20:35:02 GMT

Hello RL can build a small aplicatico the please pick3

Where, can not repeat the position.

So we have 7x7 = 49 x2 = 96

Times = 294 are bets

Where any of the digits repeat the example last given position

187 last

458 repeated the digit 8 but 3rd place that is given to standard

Acertava on 294 on 100%

RL

Can colocaar a filter to decrease 296 by 20% of it

Get 30 to 60 bets.

So I type the last draw and macro or application makes conbin oes

You can do to pick3 and

Reply #10

dr san — Wed, 12 Aug 2015 20:26:38 GMT

Hellom RLRAMDONLOGIC conglatulations, very vom work. Did you notice

What's that last for the next one can work the position

And also ... 10.20 sweepstakes analysis by position and its repetitions,

Then we have a seed within the last draw can make

Make Search pick3. Well we are looking for these patterns 68-75% already good

You can catch the last 4 Sweepstakes pick3 and see in the example vertical

4896

5623

1530

9787

We have in each vertical column in 4 digits

The... [ More ]

Reply #9

RL-RANDOMLOGIC — Wed, 12 Aug 2015 17:25:15 GMT

dr san

My P-4 has many repeats looking at midday to evening. Only 6 out of 18 games did not have a repeating digit/s

RL

Reply #8

dr san — Wed, 05 Aug 2015 21:14:02 GMT

Hello. Lildary have a mistake here

1x7x7 = 49

7x7x1 = 49

Times three conditions = 98x = 294

It's not 81 but 49 is correct, because the three digits of the base (last draw is out)

It is a repeated and fixed for that each of the two positions is 49 plus 49 as the 3rd position is not equal

example

478

189

The digit 8 not repeat the 3rd since the 1st and 2nd must have 7:07 digit

Reply #7

SergeM — Tue, 28 Jul 2015 22:33:05 GMT

https://www.lotterypost.com/thread/290507

Reply #6

SergeM — Tue, 28 Jul 2015 22:31:53 GMT

https://www.lotterypost.com/thread/290278

Reply #5

dr san — Tue, 28 Jul 2015 20:46:43 GMT

Hello lidary, good or not repeating a last digit we

For the next seven digits, 35 times x6 = 210 grants

So we have 243 = repeating a digit but not possible

Or pattern of not repeating or left 7 210

+ 210 = 243 = total 253 =

From a small profit here

The condition not to hit is that it can not give two repeated last digit

But if you can think of a couple here,

It is very filter it

Reply #4

dr san — Tue, 28 Jul 2015 20:35:11 GMT

Hello. Ok perfect good job daryl, so if 68% of the time a digit simply repeats what not repeated in the position we have 243 in 1000 (one thousand) would make a profit here ??

Now could reduce 243 via surveys or positional standards

Reply #3

Lildarryl — Tue, 28 Jul 2015 19:15:58 GMT

1x9x9 equal 81

81x3 equal 243

Reply #2

dr san — Tue, 28 Jul 2015 19:06:32 GMT

Sergem Hello, I want to take advantage of the 68% repeat repeat pattern of at least

One digit off from the last position, but are three-digit to repeat

I need all possible combinations 000-999

Without repeating in a position to choose to pla

Reply #1

SergeM — Tue, 28 Jul 2015 18:54:50 GMT

Qu los resultos

pick 3 separete, position

dr san — Tue, 28 Jul 2015 13:09:09 GMT

hello someone has the total possible combinations of the following criteria =

the last draw of pick3 the condition is to repeat a digit, but not in the same position next example 159 481 repeated the digit 1, need all the CIM conbina oes digit 1 in the 2nd and 3rd positions may not have the 1st position and so with digit 5:09 the conbina oes with the digit 5 can not be the 2nd position

and the total of all the digit 9 not pose be the 3rd position, anyone know how to calculate in excel? ple... [ More ]