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pick 3 separete, position

Topic closed. 50 replies. Last post 1 year ago by dr san.

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bgonÃ§alves
Brasil
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June 9, 2010
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 Posted: July 28, 2015, 9:09 am - IP Logged

hello someone has the total possible combinations of the following criteria =
the last draw of pick3 the condition is to repeat a digit, but not in the same position next example 159 481 repeated the digit 1, need all the CIM conbinaçoes digit 1 in the 2nd and 3rd positions may not have the 1st position and so with digit 5:09 the conbinaçoes with the digit 5 can not be the 2nd position
and the total of all the digit 9 not pose be the 3rd position, anyone know how to calculate in excel? please

Economy class
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 Posted: July 28, 2015, 2:54 pm - IP Logged

Qué los resultos?

bgonÃ§alves
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 Posted: July 28, 2015, 3:06 pm - IP Logged

Sergem Hello, I want to take advantage of the 68% repeat repeat pattern of at least
One digit off from the last position, but are three-digit to repeat
I need all possible combinations 000-999
Without repeating in a position to choose to pla

Winner
South Carolina
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 Posted: July 28, 2015, 3:15 pm - IP Logged

1x9x9 equal 81

81x3 equal 243

my name Lil Darryl   you got some Milk

bgonÃ§alves
Brasil
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 Posted: July 28, 2015, 4:35 pm - IP Logged

1x9x9 equal 81

81x3 equal 243

Hello. Ok perfect good job daryl, so if 68% of the time a digit simply repeats what not repeated in the position we have 243 in 1000 (one thousand) would make a profit here ??
Now could reduce 243 via surveys or positional standards

bgonÃ§alves
Brasil
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 Posted: July 28, 2015, 4:46 pm - IP Logged

Hello lidary, good or not repeating a last digit we
For the next seven digits, 35 times x6 = 210 grants
So we have 243 = repeating a digit but not possible
Or pattern of not repeating or left 7 210
+ 210 = 243 = total 253 =
From a small profit here
The condition not to hit is that it can not give two repeated last digit
But if you can think of a couple here,
It is very filter it !!

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 Posted: July 28, 2015, 6:31 pm - IP Logged
Economy class
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 Posted: July 28, 2015, 6:33 pm - IP Logged
bgonÃ§alves
Brasil
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 Posted: August 5, 2015, 5:14 pm - IP Logged

Hello. Lildary have a mistake here
1x7x7 = 49
7x7x1 = 49
Times three conditions = 98x = 294
It's not 81 but 49 is correct, because the three digits of the base (last draw is out)
It is a repeated and fixed for that each of the two positions is 49 plus 49 as the 3rd position is not equal
example
478
189
The digit 8 not repeat the 3rd since the 1st and 2nd must have 7:07 digit

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 Posted: August 12, 2015, 1:25 pm - IP Logged

dr san

My P-4 has many repeats looking at midday to evening.   Only 6 out of 18 games did not have a repeating digit/s

RL

Working on my Ph.D.  "University of hard Knocks"

I will consider the opinion that my winnings are a product of chance if you are willing to consider

they are not.  Many great discoveries come while searching for something else

Trump / 2016 & 2020

bgonÃ§alves
Brasil
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 Posted: August 12, 2015, 4:26 pm - IP Logged

Hellom RLRAMDONLOGIC conglatulations, very vom work. Did you notice
What's that last for the next one can work the position
And also ... 10.20 sweepstakes analysis by position and its repetitions,
Then we have a seed within the last draw can make
Make Search pick3. Well we are looking for these patterns 68-75% already good
You can catch the last 4 Sweepstakes pick3 and see in the example vertical
4896
5623
1530
9787
We have in each vertical column in 4 digits
Then 4x4x4x4 = 256
Hit condition just to repeat a digit of the last to hit 256 in 100%
Example in the last pick4
He gave in 1837
These were the 4 previous to 1837
4896
5623
1530
9787
Hits condition simply a column that will hit

- Any where a digit is in the same position (1st, 2nd or 3rd) as in the previous draw (this was part of what you originally asked for)
- If all three even or all three odd
- If all three in the range 0-4 or in the range 5-9
- Any that have not appeared in that position in the previous seven draws (the median is 7, so I'm working on the basis that in other lotteries, numbers that last appeared within the median number of draws repeat more often)
- The sum of all three digits in the range 10 - 17 inclusive (the limits 10 and 17 are the lower and upper quartiles for all the possible sums, and their frequency, so I'm working on the basis that the sum of the three digits are more likely to appear within the interquartile range (middle 50% of the data))
- If none, or more than one digit was in the previous draw (the second part of what you originally asked for.

The number of arrangements is coming down to about 30, but so far, no matches. I need to experiment a bit, e.g. disabling some filters to see which numbers get through. I'm working with the Arkansas Cash 3 lottery data.

http://myarkansaslottery.com/games/cash-3

In terms of the spreadsheet, I've set up a sheet called 'Filtering'.
Columns A, B, C have the draw data, Column D the date (I'm only using the evening draw as there is always an evening draw), Column E an ID for the draw (for now, just a number that is increased by one for each draw).

Column F is used to select (x) the draws to include, which makes it easier to compare the output with the numbers in the next draw. I also use it to help locate the last draw, necessary for two of the filters.

Columns H, I and J will have the arrangements that pass all the filters.

I'll upload some code when I've tidied it up a bit.

Example:

1 2 3 Date ID Select
0 9 2 01/07/2015 1 x
5 1 4 02/07/2015 2 x
5 6 2 03/07/2015 3 x
1 5 9 04/07/2015 4 x
5 8 1 05/07/2015 5 x
1 4 6 06/07/2015 6 x
3 0 4 07/07/2015 7 x
4 3 4 08/07/2015 8 x
4 1 7 09/07/2015 9 x
7 5 9 10/07/2015 10 x
bgonÃ§alves
Brasil
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 Posted: August 12, 2015, 4:35 pm - IP Logged

Hello RL can build a small aplicatico the please pick3
Where, can not repeat the position.
So we have 7x7 = 49 x2 = 96
Times = 294 are bets
Where any of the digits repeat the example last given position
187 last
458 repeated the digit 8 but 3rd place that is given to standard
Acertava on 294 on 100%
RL
Can colocaar a filter to decrease 296 by 20% of it
Get 30 to 60 bets.
So I type the last draw and macro or application makes conbinçoes
You can do to pick3 and pick4?

bgonÃ§alves
Brasil
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 Posted: August 12, 2015, 4:36 pm - IP Logged

He gave in 1837
These were the 4 previous to 1837
4896
5623
1530
9787

1837

bgonÃ§alves
Brasil
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June 9, 2010
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 Posted: August 12, 2015, 4:43 pm - IP Logged

RL, also we can see the pattern repeats instead of the digit position
standards
Pairs / odd inside / outside high / low
example
456
182 in 3rd position repeated the standard pair = 0,2,4,6,8
Ie the repetiça of small patterns can ride it in a program?
Digits itself and also the repetition of patterns

bgonÃ§alves
Brasil
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June 9, 2010
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 Posted: August 12, 2015, 4:46 pm - IP Logged
Hello, we have 4 = theconcept conditions
HE HO LE LO Numbers
HE Numbers are (HighEven) - 6, 8 = 1
Numbers are HO (HighOdd) - 5, 7, 9 = 2
Numbers are CO (LowEven) - 0, 2, 4 = 3
Numbers are LO (LowOdd) - 1, 3 = 4
Always a standard of 1,2,3,4 will be out at 100%
1 = 6,8,5,7,9,0,2,4
2 = 5,7,9,0,2,4,1,3
5,7,9,1,3,6,8 = 3
6,8,0,2,4,1,3 4 =
In one of the four lines will be near 100% any sweepstakes draw =
Example = 478 = line 1 (6,8,5,7,9,0,2,4)
Always one of the lines will have three digits in 100%

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