How would you determine the minimum x maximum width of each lottery filter?

Reply #25

garyo1954 — Thu, 01 Feb 2024 00:11:53 GMT

I should have kept my mouth shut and let ol' doc get worked up.

But I get worked up reading canned hype/truth by omission.

G

Reply #24

MartyMcNuts — Wed, 31 Jan 2024 21:57:00 GMT

G, none of my quote is real!!

Since the good doc thought AI could help, I thought I'd appease him and asked an AI to write me a paragraph (real or not) on how to determine the min max width of each lottery filter and that is what it came up with.

In the end, lotteries are random. Nothing is gonna change that. All we can do is come up with and apply filters to assist in picking numbers or reducing combinations but in the end, it is always gonna be guesswork.

Reply #23

garyo1954 — Wed, 31 Jan 2024 01:44:29 GMT

Yes Just maybe. Correct. Congratulations. Thank you

Reply #22

JustMaybe — Wed, 31 Jan 2024 01:35:52 GMT

Am not sure how to get the width of the 1st filter.

However, I think a good place to start would be with a measuring tape

Reply #21

garyo1954 — Wed, 31 Jan 2024 00:47:40 GMT

Expectations aren't guarantees. And when you're dealing with a range it means you aren't identifying a singular. With even/odd you have 1 to 5 even and 1 to 5 odd. Say you can get your 95%, you still have to identify the actual numbers as well as too many other variables

Then even if you could pinpoint everything to 95%, you still need the actual numbers, or you end up playing an enormous number of sets. Not many people have that much cash to throw around

And when you do you are relying... [ More ]

Reply #20

dr san — Tue, 30 Jan 2024 07:30:43 GMT

helo marty, correct conglatulations thank you

Reply #19

MartyMcNuts — Tue, 30 Jan 2024 06:55:06 GMT

To address this problem, we used a linear regression model to analyze the historical data of the filter performance, which included variables such as filter width, lottery type, number of tickets, and prize amount. We then calculated the confidence intervals for the estimated coefficients of the model at a 95% significance level, which gave us the range of values that contain the true effect of each variable on the filter performance with a high degree of certainty. Based on these results, we we... [ More ]

Reply #18

garyo1954 — Mon, 29 Jan 2024 17:37:41 GMT

He had a hard day's night working like a dog counting poppy seeds. Or testing them.

Has to be something like that when he starts a thread about regression and flips it to if we take a group of combinations we can use filters.

Par for the course though. Every single post he writes gets flipped to filters. He's obsessed with filters.

But his English took a leap in this thread. Night and day difference. Normal thread: how to break my leg.

This thread: if you wanted to break your leg... [ More ]

Reply #17

Stack47 — Mon, 29 Jan 2024 04:51:38 GMT

if you get the 1st digit of pick3 right you're in

The problem is the odds against getting the 1st digit right are always 9:1. At the minimum, we must bet $5 to win $20 and only IF WE GET THE 1ST DIGIT RIGHT

if you get the 1st number of a pick5 right you're in

Even if you get the 1st or any of the five numbers right, each of the 39 numbers are in 73,815 combinations. If you can get three of the numbers right, you can hit he jackpot using 630 combos.

Reply #16

garyo1954 — Sun, 28 Jan 2024 23:53:27 GMT

Your argument is questionable by the worn out rectumfrier discombobulating the medalanumium processor in the iqnium section.

Please feel free to post sufficient verifiable data points to back up your claims.

Show your work, necessary formulas and source code.

For faster verification we may require a credit card.

Thanks in advance

G

Ps my skunk monkey needs a new windshield wiper and harmonica balance.

Reply #15

dr san — Sun, 28 Jan 2024 23:11:12 GMT

garyo, if you get the 1st digit of pick3 right you're in, if you get the 1st number of a pick5 right you're in, if you get the 1st filter configuration right in doubles you're in, the objective is to get the 1st filter setting right for the other party of the filter duo is a consequence.

Reply #14

Stack47 — Sun, 28 Jan 2024 22:57:50 GMT

Nothing you posted has anything to do with filters. Not a thing.

About the same as asking us to look for trends without ever defining which trend to look for.

Reply #13

dr san — Sun, 28 Jan 2024 21:48:15 GMT

ok garyo correct conglatulations thank you

Reply #12

garyo1954 — Sun, 28 Jan 2024 20:14:05 GMT

I'm leaning to the crowd opinion. You're making it up. And that's okay. It gives me something to think about while I take my 2021 camel to the carwash for his weekly oil change.

But to get back to the real issue. Nothing you posted has anything to do with filters. Not a thing.

Prove it to yourself.

The first choice you make in any lottery limits all the subsequent choices you have.

The first number you choose sets a low and high sum range, it limits the choices you have of e/o... [ More ]

Reply #11

dr san — Sun, 28 Jan 2024 09:48:54 GMT

hello garyo you are correct in relation to the post, an example of filter configuration for 49/6

ex, let's assume this configuration even = minimum 1 maximum 4 odd = minimum 1 maximum 4, the same for LOW / HIGH, ETC. THE FILTERS MUST BE DOUBLE

but if you know through study that there will be 2 evens, the odd ones will be 4 because in 49/6 we have 6

numbers in the draw, this greatly reduces the playable group, by adjusting the configuration of one of the filters

of the pair the other... [ More ]

Reply #10

MartyMcNuts — Sun, 28 Jan 2024 05:53:08 GMT

Lol!

It still sounds like you are just making stuff up! If you think AI can help, then ask AI for help.

Reply #9

garyo1954 — Sun, 28 Jan 2024 05:43:33 GMT

If you're talking about regressive analysis you are trying to relate dependencies to independent variables

And that is just my wildest guess on what you've said.

In any case, that should be a given variables often are dependent on others as you say the even is dependent on the value of the odd, high dependent on value of low, and so forth. Actually that's confusing too. It would be more correct to say they complement each other in a manner to be the total of both values in the set. The... [ More ]

Reply #8

AllenB — Sun, 28 Jan 2024 05:02:48 GMT

https://www.youtube.com/watch?v=zE7PKRjrid4 pp=ygUcbW9ycGhldXMgZXhwbGFpbnMgdGhlIG1hdHJpeA%3D%3D

What ever you do Don't Take the Black Pill.

Reply #7

dr san — Sun, 28 Jan 2024 02:08:55 GMT

hello garyo, being one step ahead or playing catch-up doesn't work in the lottery, you have to think about regression

Reply #6

garyo1954 — Sun, 28 Jan 2024 01:28:07 GMT

Ask AI then. ChatGPT is ready and waiting.

G

Reply #5

dr san — Sun, 28 Jan 2024 00:38:43 GMT

hello marty, think one step ahead

It doesn't work in lotteries, you have to think about it

in return and what can help with this is A.I.

Ai doesn't stay in the comfort zone, she goes looking for

new paths every day to evolve, in return for the lottery, call i.a

Reply #4

MartyMcNuts — Sun, 28 Jan 2024 00:29:24 GMT

C'mon doc! Now you're just making stuff up...

Reply #3

garyo1954 — Sun, 28 Jan 2024 00:26:37 GMT

I think what he's saying is if you have 2 even number in a six ball game then you have to have 4 odd numbers or if you have 3 lows you have to have 3 highs.

He's throwing words around that don't mean what he thinks they do. Even/odd, high low complement each other. They only time they would mirror is when both are equal.

I'm baffled on how you get the width of a number though.

G

Reply #2

rcbbuckeye — Sat, 27 Jan 2024 23:01:39 GMT

Glad I'm not the only one confused by that question...

Reply #1

garyo1954 — Sat, 27 Jan 2024 19:18:28 GMT

I give up.

How?

G

How would you determine the minimum x maximum width of each lottery filter?

dr san — Sat, 27 Jan 2024 13:23:43 GMT

How would you determine the minimum x maximum width of each lottery filter?

example of 49/6=if you first determine

minimum 2 and maximum 4 evens, the odd ones become a mirror of the 1st configuration, so double filters

type even/odd high/low, left aldo right side etc... when the filters are planned in pairs

getting the configuration of the 1st filter right, the other is a mirror or consequence, now the question is how

find out the width of the 1st filter