How Astronomical Is It To Get The Number Right In Each Column?

Reply #22

Elizabeth03 — Mon, 29 Dec 2025 20:29:06 GMT

I play the Atlantic 49 . It is challenging.

Reply #21

Ney1 — Mon, 29 Dec 2025 20:15:45 GMT

Column 1 and 5 (or 6 if it's a P6) are the most important columns, IMO.

Once those two columns are locked in, its puts a cap on the middling numbers and help reduce the odds to pin the right number down from the 2 to 4 columns (or 5, if a P6 game).

I want to add further details here but that would be giving away valuable info of my system. Kudos for getting this much info out of me though.

Reply #20

dr san — Mon, 29 Dec 2025 20:13:15 GMT

hello hyper=

The idea below is a **layered positional filter system**, focused on **intelligent reduction**, without promising total accuracy, but **playing in favor of chance**.

---

## 1 Fixed base: ascending order

Every game must respect:

``` P1 P2 P3 P4 P5 P6

```

---

## 2 Main positional filter (your frame)

This is the **mother filter** of the system:

| Position | Allowed range |

| ------- | ------------------- |

| P1 | 01 34 |

| P2 | 02 38

Reply #19

Ney1 — Mon, 29 Dec 2025 20:04:11 GMT

.......whoever is selling that EPR; I'd charge them $1,500 for mine with a guarantee to outperform theirs.

I have no issues knowing the range for each columns. I just can't pin 1 number down for each column. My system can pin it down to 5 to 7 numbers and I'd manually reduce it to 2 or 3 numbers with some additional side filters.

Reply #18

dr san — Mon, 29 Dec 2025 19:59:09 GMT

You said:

ok, but if you put a limit when in ascending positional order, e.g., 1st position In the 49th/6th row, from 01 to 34, and in the 6th row, from 25 to 49, and so on in the other positions.

ChatGPT said:

Perfect, Julceu now you've hit the nail on the head

There is a real reduction here because you are imposing positional limits in ascending order.

I'll explain with mathematical logic, without guesswork.

1. What changes when you impose limits by position?

Before... [ More ]

Reply #17

AllenB — Mon, 29 Dec 2025 19:42:13 GMT

Answering your original question, This would be awesome. The Percentage of all possible Sets of numbers suggested would make you rich, .

GAME FANTASY 5 SUPER LOTTO +

BALLS 39 47

DRAW 5 5

COMBINATIONS 575,757 1,533,939

BALLS PER COLUMN COMBINATIONS % COMBINATIONS %

5 3125 0.54% 3125 0.20%

7 16807 2.92% 16807 1.10%

The problem is there are only 2 columns (the first and last) That have Drawn the narrowest range of Balls. The second thru next to... [ More ]

Reply #16

hypersoniq — Mon, 29 Dec 2025 18:39:37 GMT

That was a very good post demonstrating that all combos have the same probability

Reply #15

JADELottery — Mon, 29 Dec 2025 18:22:57 GMT

By the data, that makes 1, 10, 20, 30, 40, 49 the most likely combo in any 6/49.

This is a common misperception.

That combo and any other combo has exactly the same probability of occurrence.

Using our posts about Combinatorial Fractalization and Combinatorial Distribution , the moment we fix a column to a number changes the way we calculate the probabilities of the remaining numbers in each column successively.

Properly calculated for each successive fixed number in each column... [ More ]

Reply #14

hypersoniq — Mon, 29 Dec 2025 18:19:35 GMT

With draw order data that would be 49^6 or 13.84 billion, so still an advantage to have sorted order data.

Reply #13

str8ca$hhomie — Mon, 29 Dec 2025 13:03:04 GMT

Several years ago there was a Cash 5 / Pick 6 system advertised that it would reduce the range the range of numbers in any 5/6 game. I think it was called the EPR System and it cost around $ 500 dollars.

Reply #12

Tucker Black — Sun, 28 Dec 2025 22:39:08 GMT

44 numbers in six columns but they all have to be in the right column is a different game with far worse odds. It's not 44 choose 6, it would be 44^6, which is 7.25 billion.

Reply #11

Ney1 — Sun, 28 Dec 2025 18:24:07 GMT

Yeah, I know the range for each columns. Thats easy to figure out but still a challenge to pin it down to one number for each column and get it right. Thats why someone told me the chance of getting it right is astronomical, the guess.

However, I can pin it down to 5 to 7 numbers in each columns but it still becomes challenging to get the right combination without playing all the combinations which is too much money to pay.

Reply #10

Ney1 — Sun, 28 Dec 2025 18:18:37 GMT

Lotto Texas.

Reply #9

Ney1 — Sun, 28 Dec 2025 18:15:15 GMT

I do have a method to compute number-frequency in my system but it doesn't involved math calculation and percentages. More of symbols and repetition of those symbols.

Reply #8

Ney1 — Sun, 28 Dec 2025 18:06:55 GMT

The P6 games is Lotto Texas...1-54.

Reply #7

dr san — Sun, 28 Dec 2025 16:38:57 GMT

hello! HY PER ! In 95% of cases, but 80% already knew that the 6th position of the 49/6 starts with 16 to 49, while the 1st position starts with 01 to 35, and so on in the other positions when it's ascending.

Reply #6

hypersoniq — Sun, 28 Dec 2025 16:10:05 GMT

So what your post shows is that in a 6/49 game, where the data per column is sorted ascending, each column has 44 possible numbers instead of 49. So on a per column basis, each number, in a fairly drawn game has a modified expectancy... 1/44 (0.0227) rather than 1/49 (0.0204) when considering sorted over drawn order. Since 5 numbers are not possible in each column, it looks to reduce the odds as C(49/6) has 13,983,816 combinations, while C(44/6) has 7,059,052 combinations. Interesting observatio... [ More ]

Reply #5

dr san — Sun, 28 Dec 2025 05:44:24 GMT

Hello, if the positions are in ascending order, in the 49/6 order the first position will range from 1 to 30 at most. However, if we're not looking at ascending order, the first position will range from 1 to 49. Therefore, ascending order is better.

Reply #4

Stack47 — Sun, 28 Dec 2025 02:30:32 GMT

Which pick 6 game draws and pays permutations

Reply #3

Player649 — Sun, 28 Dec 2025 01:34:55 GMT

Someone actually told me, 'its astronomical to get the right number in the right column'

Regarding the astronomical odds claim for 649.

Total combinations = 13983816

Number positions = 13983816 x 6 = 83902896

Each number = 83902896 / 49 = 1712304 appearances (not astronomical by any means)

Below is the number split for each of 6-number line positions (columns as you call it).

Nothing astronomical in there, either.

Frequencies are different for each number in each positio... [ More ]

Reply #2

Ney1 — Fri, 26 Dec 2025 22:08:39 GMT

P6, of course.

Reply #1

Tucker Black — Fri, 26 Dec 2025 21:50:43 GMT

What game are you playing

How Astronomical Is It To Get The Number Right In Each Column?

Ney1 — Fri, 26 Dec 2025 18:52:47 GMT

Someone actually told me, 'its astronomical to get the right number in the right column' or something along that line. And I never gave it much thought how difficult it is to get a number right in each column.

When I design systems; the focus is always on why each number come out the way it does? I then do a deep analysis or have a critical look how those numbers move, number to number, and why. Then I develope filters that match the outcome of the numbers.

There's always a re... [ More ]