I do understand that I don't know much at all about odds for lottery games.

But it seems to me that if a tombola lottery container has or holds inside of it 10 lottery balls and they draw out one ball out of the ten, that each of the ten balls had odds of 1/10 and that it will ALWAYS be like so when they only draw one of ten balls out regardless of anything else.

And if a tombola lottery container has 24 balls in it and they draw one of the 24 balls out that each of the 24 balls had and has a 1/24 odds chance of having being drawn out and that it will ALWAYS be like so, always regardless of anything else.

Now if a tombola lottery container has 27 balls and they draw out 2 balls out of it, I might be wrong, but maybe the odds would be:

2 of 2 in 2 from 27  -> 1 in 351 and that whatever the odds are that they would always be like so regardless of anything.

And if a tombola lottery container has 38 lottery balls inside of it and that if they draw 3 of those balls that that the odds might be:

1/8436

3 of 3 in 3 from 38  -> 1 in 8436 and that it will ALWAYS be those odds regardless of anything.

A tombola is a type of lottery container, but a container is a container regardless, it could be any lottery container that main thing is that all the balls be inside that container.

Now we have a lottery container with 61 balls in  it and they ALWAYS draw 5 lottery balls out of that container so the odds might be:

1/5,949,147

5 of 5 in 5 from 61  -> 1 in 5,949,147 And the odds should Always be those regardless of anything else.

Each container is independent from any other container and the odds in each container should always be the same and should not have anything to do at all with the odds in any other container, or so I think, I see no reason as to why the odds in one container should affect or have anything to do with the odds in any other container.

Now we have 2 containers, one has 57 balls in it and the other has 12 balls in it, it is 2 separate containers and it can be taken as being 1 game or 2 games.

If 2 games one game is:

5/57 = 4,187,106

5 of 5 in 5 from 57  -> 1 in 4,187,106

And the other game is:

1/12 =  of 1 in 1 from 12  -> 1 in 12

And the odds should always be those as far as I can tell, because the odds in 1 container should not have anything at all to do with the odds in any other container.

Now if it was 1 game:

5/57 + 1/12

I don't know what the combined odds might be, but there are 2 containers and each of the 2 containers should have its very own odds and odds from 1 container should not have anything to do nor affect the odds of the other container so:

5/57 Should still always be 5 of 5 in 5 from 57  -> 1 in 4,187,106

And:

1/12 Should still always be 1/12, because each container holds or has its own lottery balls that don't have anything at all to do with the balls in any other container, each container is independent and separate(d) from any other container.

So maybe the combined odds are:

4,187,106 X 12 = ? Google says = 50,245,272

I don't know what is right, but it seems to me that the odds in each container stay the same as if it was 2 games instead of 1.

After all 5/57 always makes 4,187,106 total combinations regardless of any other container

And 1/12 always makes 12 numbers from 1 to 12 regardless of any other container

Each container always has its own independent odds regardless of any other container.

5/57 Always has to make a total of 4,187,106 regardless of any other container.

And 1/12 always has to make 12 numbers - combinations regardless of any other containers.

Am I wrong? How?

Odds from one container should never affect the odds of any other container.

On the pick 3 game there are 3 containers of 1/10 each and the odds in each container are always 1/10 and are never affected by the odds in any other container, it might be 1 game, but it can also be 3 games of 1/10 each.

Well, good luck!

And I don't know anything.