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The time is now 12:03 am
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June 3, 2026, 5:36 pm
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Next up, pick 3 permutation counter.
Published:
Going to create a counter for permutations of the pick 3 combos.
It stands to reason that the combo that won the most times straight is not necessarily the one with the most appearances boxed as well.
This one will count all of the combos for straight hits, but then also for hits on any permutations. Of course the triples will be kept out, so that is going to count the rest of the possible combos, all 900 from 001 to 998.
This time I am aiming to generate a report rather than just save to a csv file for further processing. (Though that will also be done).
Output format will be sorted by historic winnings...
NNN. # straight hits. # permutation hits (boxed) $calculated winnings based on history
There are libraries in Python that make dealing with permutations orders of magnitude easier than the long and complex spreadsheet formulas.
Why all the extra work? Because this process gets a great deal more difficult when scaling up to the pick 5!
Pick 3, 3 unique digits has 1 combo with 5 additional permutations... pick 5, 5 unique digits has 1 combo with 119 additional permutations!
Plus, leaving out the 5 of a kind combos, there remain 99,990 combos to sift through.
Same work flow as prior attempts, perfect the design on the pick 3 then just scale up...
Should be relatively easy, right?

Comments
I have yet to work on the overall count logic where it adds up the straight and box hits, but it is ouputting the count results and they look reasonable.
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