What is in blue is extremly important also..

COMMENT BY PUMPI76:

right now i am experimenting with middle lines, you will have to read my blog to understand what i mean..I am also experimenting with deducing, you will have to read my blog to know what it is but i'll explain one example in here...

it occurred to me this why not use 9 numbers [i am debating whether to use the 10 numbers but 9 will do it  for now...]

and do the following

1-2-3

4-5-6

7-8-9

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And then 1, 4 and 7 are 1,

2, 5 and 8 are 2

3, 6 and 9 are 3

And beging to write the previous draws like that....This is what i got...but i warn you, you are screwed when 0 plays...This is a sample from geogia from 2007...Sorry for the sample been that old...Everytime you the the "X" is because 0 played...

3's numbers                   Actual numbers

1. X

2. X

3. X

4. 3-2-3-2

5. 1-3-2-2

6. 1-1-3-2

7. 3-3-2-2

8. X

9. 3-3-3-3

10. X

11. 1-3-2-1

12. 2-1-2-1

13. 2-3-2-3

14. 3-3-3-1

15. 1-1-3-1

16. 2-1-1-1

17. X

18. X

19. 2-3-1-1

20. X

21. X

22. 3-2-1-2

23. 1-3-3-3

24. 3-1-2-3

25. 2-1-2-2

26. X

27. 2-3-3-1

28. 2-3-3-3

29. 3-1-3-2

Now tell me, how easy it is to predict 3 numbers from 1 to 3 taken 4 at a time with 99% of the time at least 1 number repeating at least twice....

I don't know i notice that "0" played several times so you may want to do a

1-2-3

4-5-6

7-8-9

0

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Now here is the trick, for this system you need to be able to deduce in 3 lines...Most of my deducing is in 2 lines, meaning that 1 number represents 2 numbers...I'll show you an example of deducing in 2 lines but i am not trying to throw you off...Again i am not trying to throw you off here this is just to show you what it is deducing in 2 lines...

suppose 1,6=1 and 2,7=2, and 3, 8 = 3 and 4,9=4 and 5,0=5 and lets say that you had the number 1-1-3-5 and you was sure it was going to play...You will then deduce the following way:

1-1-3-5

1-6-3-5

1-1-8-5

1-1-8-0

1-6-3-0

1-6-8-0

1-6-8-5

1-1-3-0

6-6-3-0

6-6-8-0

6-6-3-5

6-6-8-5

This deduction came out to 12 tickets...that is deducing in 2 lines because each number has a double twin....Now how would you deduce if each number had a 3 triple twin, i don't know i am still working on it...But something tells me it will not exceed 40 tickets or 50 tickets....

Going back to the 3's system, it doesn't matter if you get the numbers box or straight because once you deduce you will get it box is up to you to arrange them in the straight option....Now tell me isn't this closer to a 5,000 dollar straight option.....Let me try and attempt to see if i can deduce in 3 lines....

supposed i got 3's numbers of 1-3-3-3 and i want to deduce in 3 lines...

1-6-3-3

1-6-9-3

4-6-3-3

7-6-3-3

4-6-9-3

7-6-9-3

1-6-6-6

1-9-9-9

1-6-6-3

1-6-6-9

1-9-9-3

1-9-9-6

4-6-6-6

4-9-9-9

4-6-6-3

4-6-6-9

7-6-6-6

7-9-9-9

7-6-6-3

7-6-6-9

this deducing with 3 lines came out to 20 tickets...But you got something on your favor 3 numbers repeating 3 times is so rare to play in pick4 so you can filter it, i bet you filter the numbers that repeat 3 times and it leaves  you with 10 tickets...Same thing with the 3's numbers, you can filter them for Even/odd....if you want to add more filtering to the tickets after you deduce in 3 lines is up to you you can if you like...

The only problem is the 0 when it shows up....

guys correct me where i need correction and opinions welcomed....

COMMENT BY PUMPI76: 

the deducing that i did with 3 lines came out to 20 tickets because 3 of the digits repeated, but if only 2 digits repeat for example if you have: 1-2-3-2 i did it and it comes out to 29 tickets...[the spaces because i had some repetions]

                       4-5-3-5

                       4-5-6-5

                       4-5-9-5

1-2-3-2            4-2-3-5

1-2-6-2            4-2-6-5

1-2-9-2            4-2-9-5

1-5-3-5            7-5-3-2

1-5-6-5            7-5-6-2   

1-5-9-5            7-5-9-2

1-2-3-5            7-2-3-2

1-2-6-5            7-2-6-2

1-2-9-5            7-2-9-2

4-5-3-2            7-5-3-5

4-5-6-2            7-5-6-5

                        7-5-9-5

4-2-3-2           

4-2-6-2           

4-2-9-2

you can always filter for even/odd, high low or digits that repeat or don't repeat...I think i if i added zero to the 3's it will have come out to 40 tickets...but even so i miss the digit 8.....

COMMENT BY PUMPI76: Some may say why when i deduce/wheel the numbers the 9 numbers they don't come out to be 126 or something around that since that's the number of tickets a 9 wheel for pick4 will run about...The answer is because i am not wheeling 1 with 4 and 7, i am not wheeling 2 with 5 and 8 i am also not wheeling 3 with 6 and 9...

COMMENT BY PUMPI76: 

basically i am wheeling horizontally only i am not wheeling vertically, horizontally and diagonal...

you know you can apply this system to pick3...

you do the following:

1-2-3

4-5-6

7-8-9

 you eliminate zero but you can add zero below the 7 if you like...Remember 1,4 and 7 are 1;

2, 5 and 8 are 2

and 3, 6 and 9 are 3....

then suppose you get 1-2-3

you deduce/wheel

123

126

129

153

156

159

183

186

189

423

426

429

453

456

459

483

486

489

723

726

729

753

756

759

783

786

789

it comes out to 27 tickets...What you can do next is filter....

all you have to do is becareful when 0 appears make sure 0 doesn't appear on the next drawing...and guess between the 3's system numbers...

i think they are 6 of them [and remember it doesn't matter if they are boxed] and once you get it all you have to do is arrange the number into straight... 

3-3-2

3-2-2

3-1-2

2-1-2

1-1-2

3-3-1

COMMENT BY PUMPI76:  If you could only apply horizontal wheeling only to pick5 or Pick6 or Powerball or find a system that uses this method to Pick5 and others or further research this horizontal wheeling only....This is where lottery softwares should be drilling...This is where they should be working...

The thing is that i don't know anything about wheeling....

maybe we could mix this horizontal wheeling only with deducing for Pick5 or use the ending digits...

or maybe we could apply horizontal wheeling to the ending digits and then deduce....

COMMENT BY STACK47: What is "horizontal wheeling"?

COMMENT BY STACK47: 

It looks like for a '123' combo you're using (1,4,7) with (2,5,8) with (3,6,9) and creating 27 straight combinations. I think I understand what you're doing, but I just never heard it called "horizontal wheeling" before.

COMMENT BY PUMPI76:

that's correct...

1-2-3

4-5-6

7-8-9

this is what i am doing...

I am wheeling 1 with 2 and 3, 1 with 2 and 6, 1 with 2 and 9, then 1 with 5 and 3, 1 with 5 and 6, 1 with 5 and 9, then 1 with 8 and 3, 1 with 8 and 6, 1 with 8 and 9, well that was with 1; then i begin back again with 4 and then with 7...[THAT IS FOR PICK3],

you do the same with pick4...

COMMENT BY PUMPI76: 

i forgot to add this:

after you finish horizontally wheeling only you then apply filters like even/odd, high/low....maybe hot/cold...