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Dec. Stocking StuffersReply
12/1 019 bx12/2 742 bx12/3m 319 bx 826 bx eve12/4 855 bx12/5 022 bx12/11 381 bx12/12 062 bx12/13m 713 bx 120 bx eve12/15 395 bx12/16m 317 bx12/18 821 st12/20m 433 bx12/21 458 st12/22 201 bx12/23 091 st12/25 120 bx12/26m 693 bx12/27m 193 bx 539 bx eve12/28m 746 bx12/29m 855 bx total midday 8total evening 15sorry for error this should clear it up
Dec 30, 2005, 12:21 pm - bubber58 - Pick 3 Forum

Having a lottery machine: Now that's the ticketReply
That's what I'm talking about.Because of this practice I am very careful where I purchase scratch offs.If they scan too many without punching in the 3 digit code, they can get in trouble, but they can always claim computer error ....
Dec 27, 2005, 11:07 am - DoubleDown - Lottery News

Computerized lottery drawing glitch picks same numbers for 3 daysReply
I'm betting some online LP members playing the 'forbidden' site cleaned up on this. Guess it wouldn't show on the official records.Wonder if they'll pay off now that it's established there was an error.-----------------------------Incidently, interesting to note there was evidently no mechanism for detecting the problem other than watching the draws...... hmmm two days, just a coincidence. Three days in a row and someone starts looking at things.If they're going to use computers I suppose that
Dec 23, 2005, 8:14 am - Rip Snorter - Lottery News

The combinatorics of a permutationReply
I have added an 'UPDATED ->' tag and date to the spreadsheets in the upper left cells, A1 and B1.One of the fucntions in the calculation of the Combinatorial Set Item Number had a finger check error.Also, if there are any additional ideas or concepts I'd like to add, you'll know right away by the 'UPDATED ->' tag.PICK 3 sample ExcelPICK 4 sample Excel
Dec 22, 2005, 10:19 am - JADELottery - Mathematics Forum

Macros in excelReply
matrices and their inverse are used, among other things, to solve simultaneous equations like6x + 3y = 66 while 7x - 2y = 11. These two equations each form a line, but intersect at one point ~ the solution.this one is easy enough to do on paper but things get tough with, say 5 variables. If all of the equations in the set don't 'fit' then the error message is a way of saying one or more of the 'lines' don't intersect with the others. for those of you playing at home, x = 5 y = 12
Dec 18, 2005, 7:37 pm - time*treat - Lottery Discussion Forum

Macros in excelReply
These syntax errors can be really subtle to the human eye. Logic errors are even worse. I once spent the better part of 24hrs trying to figure out why I was getting an error in (previously perfectly working) macro B after I made a change in macro A. Answer; I had misspelled the argument name by one letter, so the value being picked up was 0, the default, not the value I was trying to pass.Get used to making intermediate printouts as these things get more complex.Heh, after awhile the homepage
Dec 18, 2005, 7:51 am - time*treat - Lottery Discussion Forum

Macros in excelReply
It seemed to me that when I tried that way earlier, I got some sort of error code had to remove that--but I will try again. Thanks
Dec 17, 2005, 9:52 pm - lottaloot - Lottery Discussion Forum

Macros in excelReply
the problem is it doesn't automatically update when you make changes, you have to re-enter the data... and copy/paste brings up a runtime error.here's a variation that highlights v-trac numbers in the A1:A10 rangePrivate Sub Worksheet_Change(ByVal Target As Range)Dim icolor As Integer If Not Intersect(Target, Range( A1:A10 )) Is Nothing Then Select Case Target Case 0 icolor = 2 Case 1 icolor = 3 Case 2 icol
Dec 17, 2005, 4:25 pm - hypersoniq - Lottery Discussion Forum

Editor data transmission modificationReply
Thanks Todd,Worked very well, however, for very large tables I have a problem.I will get a timeout error when trying to send very large tables.I don't have this problem when I just send plain text in the format I've created on my end.The overall problem is, when I spend alot of my time creating something that will add value to the Lottery Post and see that work get ruined, I get a little disappointed.I hope we can work this problem and find a solution that makes everyone happier.
Dec 17, 2005, 1:45 pm - JADELottery - Suggestions Forum

The combinatorics of a permutationReply
...Now, the tricky math part.Using the values of MIN, MAX, SUM, and PRODUCT we can find the values of X_LOW and X_HIGH.Taking the SUM of W, X, Y, and Z, if we subtract the values of MIN and MAX we are left with the sum of the two middle numbers X_LOW and X_HIGH. Sum of X_LOW and X_HIGH: n = SUM - MIN - MAXTaking the PRODUCT of W, X, Y, and Z, if we divide out the values of MIN and MAX we are left with the product of the two middle numbers X_LOW and X_HIGH. Product of X_LOW and X_HIG
Dec 16, 2005, 6:58 pm - JADELottery - Mathematics Forum