|Posted: December 18, 2004, 10:16 pm - IP Logged|
Here's perhaps a bit more than what you wanted but here goes...
Suppose you have say 11 of the inter-arrival times(skips) of these 471 hits. These are times between hits for a particular pair. Say you have the hit times: 7, 23, 8, 16, 2, 54, 13, 75, 11, 9, and 93. Ordered these times are 2,7,8,9,11,(13),16,23,54,75,93. The middle value (or the time) where roughly 50% of the values are above and roughly 50% below is the median.
Suppose the 13 was not there, then the median would be (11+16)/2 = 13.5., the arithmetic mean of the middle two values. It's a robust measure of the center or average of the distribution of values.
Hit times generally follow an exponential distribution in which case the distribution is skewed toward higher values (shorter hit times are more prominent), in which case the median will always be at most (smaller than or equal to) the mean.
PS. No software is worth buying unless you understand what it's telling you. So ask questions.....