Welcome Guest
Log In | Register )
You last visited January 16, 2017, 7:47 pm
All times shown are
Eastern Time (GMT-5:00)

Standard deviation of lotto sets

Topic closed. 17 replies. Last post 12 years ago by Nick Koutras.

Page 2 of 2
PrintE-mailLink
Avatar

Canada
Member #6394
August 21, 2004
97 Posts
Offline
Posted: December 27, 2004, 3:12 am - IP Logged

Really can't find any importance in this matter. If points around any curve represent draws, for the very next draw all 14 million points in the field hold the same mathematical probability 1 : 14 millions. 

    Hyperdimension's avatar - latest trace_171.gif

    United States
    Member #9059
    November 26, 2004
    128 Posts
    Offline
    Posted: December 27, 2004, 10:25 am - IP Logged

    Hi Johnph77,

     I understand your first explanation very well (excellent information), also the second one..

     The reason I put continuing with the problem was not refering to your explanation Johnph77, it was  because Bertil said in a previous post "Hi, your comment is unrelated to the problem we were trying to solve",

     The problem of Bertil is Standard deviation of lotto sets, but when I start analyzing the numbers my computer crash..

     If someone could help with this problem..

    Regards

    El pensamiento ordena el caos..

    http://1x2quinielas.blogspot.com

      Avatar

      Canada
      Member #2192
      August 29, 2003
      27 Posts
      Offline
      Posted: December 30, 2004, 12:10 am - IP Logged
      Quote: Originally posted by Hyperdimension on December 26, 2004

      Hi,



      Ion Saliu has a program call FORMULA.exe and Superformula, both programs calculate the Standard deviation for an dvent of probability p in N of binomial dvents,



      I'll use Superformula for the next example,



      The program calculates p as a fraction of 2 values, 6 in 49 in this case,



      1st element of the fraction p = 6

      2nd element of the fraction p = 49

      Enter the number of trials, N =2000



      Results:



      The standard deviation for an dvent of probability

      p = .12244898

      in 2000 binomial experiments is:

                         BSD = 14.66

      The expected (theoretical) number of successes is: 245

      Based on the Normal Probability Rule:



      ù 68.2% of the successes will fall within 1 Standard Deviation

      from 245 - i.e., between 230 - 260

      ùù 95.4% of the successes will fall within 2 Standard Deviations

      from 245 - i.e., between 215 - 275

      ùùù 99.7% of the successes will fall within 3 Standard Deviations

      from 245 - i.e., between 200 - 290

      Regards






      A uniform distribution, sometimes also known as a rectangular distribution, is a distribution that has constant probability.

      See here:



      http://mathworld.wolfram.com/UniformDistribution.html