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Free Pick 3, 4 System - Need Help

Topic closed. 7 replies. Last post 11 years ago by cariborder.

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Anguilla
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Posted: August 24, 2005, 6:42 pm - IP Logged

If 2 numbers is drawn in these 4 numbers 2-9-8-7 they will be in the correct order 100%. To play pick 3 find the other drawn number. To play pick 4 find the other number that is drawing twice or the other two numbers that is drawn.

2-9-8-7

2-9-8-2-9-8-7-9-8-7-7-2
9-2-2-8-8-9-9-7-7-8-2-7

Can any one provide the two sets of mumbers like the one above using the formula above for the following 10 numbers?: Instead of 4 mumbers use 10 numbers.

0-1-2-3-4-5-6-7-8-9


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    Posted: August 24, 2005, 6:59 pm - IP Logged

    This looks like something i saw a few weeks ago on Permutations.

    Is this what that is or am I totally off?

     

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      Anguilla
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      Posted: August 25, 2005, 8:10 am - IP Logged

      Yes - Permutations .. Where did you see that info.

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        brownsville
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        Posted: August 25, 2005, 8:21 am - IP Logged

        could u take anumber and please show me an example?

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          Anguilla
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          Posted: August 25, 2005, 9:00 am - IP Logged

          Example: For pick 3 if you choose 0, then you play the following numbers:

          2-9-8-7

          2-9-8-2-9-8-7-9-8-7-7-2
          9-2-2-8-8-9-9-7-7-8-2-7

          0-0-0-0-0-0-0-0-0-0-0-0

          Play straight/ box

            BobP's avatar - bobp avatar.png
            Dump Water Florida
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            Posted: August 25, 2005, 11:47 pm - IP Logged

            I think it's one of those things that work backwards, but not forwards.  You can find the past winning numbers, but it isn't predictive.  A variant on the word search squares.  BobP
               

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              Anguilla
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              Posted: August 26, 2005, 9:02 am - IP Logged

              This has nothing to do with past numbers......

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                Anguilla
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                Posted: August 29, 2005, 5:48 pm - IP Logged

                Formula solved