Free Pick 3, 4 System - Need HelpPrev TopicNext Topic

• cariborder

  

  Anguilla
  Member #16,468
  May 31, 2005
  15 Posts
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  Aug 24, 2005, 6:42 pm

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  If 2 numbers is drawn in these 4 numbers 2-9-8-7 they will be in the correct order 100%. To play pick 3 find the other drawn number. To play pick 4 find the other number that is drawing twice or the other two numbers that is drawn.

  2-9-8-7

  2-9-8-2-9-8-7-9-8-7-7-2
  9-2-2-8-8-9-9-7-7-8-2-7

  Can any one provide the two sets of mumbers like the one above using the formula above for the following 10 numbers?: Instead of 4 mumbers use 10 numbers.

  0-1-2-3-4-5-6-7-8-9
• pacattack05

  United States
  Member #17,554
  June 22, 2005
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  Aug 24, 2005, 6:59 pm

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  This looks like something i saw a few weeks ago on Permutations.

  Is this what that is or am I totally off?

   
• cariborder

  

  Anguilla
  Member #16,468
  May 31, 2005
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  Aug 25, 2005, 8:10 am

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  Yes - Permutations .. Where did you see that info.
• diamondjaxs

  

  brownsville
  United States
  Member #18,764
  July 19, 2005
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  Aug 25, 2005, 8:21 am

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  could u take anumber and please show me an example?
• cariborder

  

  Anguilla
  Member #16,468
  May 31, 2005
  15 Posts
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  Aug 25, 2005, 9:00 am

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  Example: For pick 3 if you choose 0, then you play the following numbers:

  2-9-8-7

  2-9-8-2-9-8-7-9-8-7-7-2
  9-2-2-8-8-9-9-7-7-8-2-7

  0-0-0-0-0-0-0-0-0-0-0-0

  Play straight/ box
• BobP

  

  Dump Water Florida
  United States
  Member #380
  June 5, 2002
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  Aug 25, 2005, 11:47 pm

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  I think it's one of those things that work backwards, but not forwards.  You can find the past winning numbers, but it isn't predictive.  A variant on the word search squares.  BobP
     
• cariborder

  

  Anguilla
  Member #16,468
  May 31, 2005
  15 Posts
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  Aug 26, 2005, 9:02 am

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  This has nothing to do with past numbers......
• cariborder

  

  Anguilla
  Member #16,468
  May 31, 2005
  15 Posts
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  Aug 29, 2005, 5:48 pm

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  Formula solved