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Buy every ticket?

Topic closed. 29 replies. Last post 11 years ago by anonymous77.

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Herndon, VA
United States
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September 23, 2005
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Posted: October 16, 2005, 1:34 pm - IP Logged

Do they have a rule saying that you can't purchase every possible ticket combination?  Because right now the odds of winning are 1 in 146,107,962, so if you bought all 146,107,962 tickets for 1 dollar each, you would win $164,400,000, which is a profit of $18,292,038.

    bellyache's avatar - 64x64a9wg

    United States
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    Posted: October 16, 2005, 1:37 pm - IP Logged

    But it would probably be impossible to have the time to print out every combination. I'm not sure, but I swear I read that somewhere.

    Dance like no one is watching.

      JAP69's avatar - alas
      South Carolina
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      Posted: October 16, 2005, 2:05 pm - IP Logged

      If my calculations are correct.

      To do one combination per minute it would take you 278 years to have all the combinations filled out give or take a few days.

      WHATT

        RJOh's avatar - chipmunk
        mid-Ohio
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        March 24, 2001
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        Posted: October 16, 2005, 3:20 pm - IP Logged

        That was tried successfully a few years ago by a group in Virgina.  The group preprinted their tickets, tied up 3 terminals for 3-4 days and only managed to buy 80% of 10M or so combinations.  After that Virgina and other state changed the rules so no one person/group can control a terminal more than 15 minutes as a time. With that many combination, you would need more 4000 hrs of terminal time to play 2 cards per seconds with 5 combinations per cards.  Some states even have a rule that the cards have to be made out by hand.  Good luck on finding that many cards to fill out.

         * you don't need to buy more tickets, just buy a winning ticket * 
           
                     Evil Looking       

          hypersoniq's avatar - 8ball
          Pennsylvania
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          Posted: October 16, 2005, 3:31 pm - IP Logged

          that will be the time that 2 or more winners come forward, thus negating the advantage.

          Playing more than one ticket per game is betting against yourself.

            RJOh's avatar - chipmunk
            mid-Ohio
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            Posted: October 16, 2005, 3:58 pm - IP Logged

            A few years ago, there was a company in Canada that had a proprietary system they claimed could cover all the mostly likely combinations with only 3% of the possible combinations.  They didn't offer the system for sale but offered expensive memberships in one of their lottery pools for a series of Canadian 649 drawings .  I haven't  read anything about them lately so either they went out of business or they were so successful they aren't seeking new members.

            When I looked at the last PB winning numbers 01-07-08-34-45 +15, that was the first time 08 had not been the lowest or second lowest number in 316 drawings and I have to wonder if their system would have included that combination.

            I'm going to try to pick 30 of those combinations for Wednesday drawing.

             * you don't need to buy more tickets, just buy a winning ticket * 
               
                         Evil Looking       

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              Fantasy Land
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              Posted: October 16, 2005, 4:00 pm - IP Logged

              Taxes already negate any advantage. The jackpot would need to really grow before the scheme payed off. And with the cap on jackpots when a new record is hit it would have to roll quite a few times to get there. By then ticket sales should surpass the number of possible combinations of numbers drawn which would mean the chances of a split jackpot would be quite high.

                RJOh's avatar - chipmunk
                mid-Ohio
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                Posted: October 16, 2005, 4:08 pm - IP Logged

                If the scheme worked, the cost of the tickets can be deducted from their winnings.  That's true for all lottery winnings, it's just that most people spend a lot more than they ever win and can only deduct up to the amount of their winnings.  If those loses don't amount to more than the standard deductions for lost then they can't deduct anything.

                 * you don't need to buy more tickets, just buy a winning ticket * 
                   
                             Evil Looking       

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                  Morrison, IL
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                  Posted: October 16, 2005, 4:32 pm - IP Logged

                    Yeah, trying to buy every possible combination is not a good idea, simply because of the possibility of PB selling another winning ticket.

                    hypersoniq's avatar - 8ball
                    Pennsylvania
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                    Posted: October 16, 2005, 11:43 pm - IP Logged

                    ever since swearingoff of trying to create systems and adopting a strategy similar to VisionDude's (one QP... I opt for the powerplay, not sure about vision's views on powering up), I wait in long lines to play my one ticket... feeling like charlie bucket in willy wonka's chocolate factory.  "only one?"

                    yes, only one... regardless of PA's october PP special (buy 5 pp tix get one free). I am far less dissapointed throwing away one losing ticket than 5 or 10. and because it's a QP,I no longer blame myself and my questionable excel skillz for the loss.

                    Playing more than one ticket per game is betting against yourself.

                      TheGameGrl's avatar - character catafly.jpg
                      A long and winding road
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                      Posted: October 16, 2005, 11:58 pm - IP Logged

                      hypersoniq- Thanks for giving a different outlook when the computer is held accountable for the random numbers. It makes it easier now when I lose based on it being a QP.

                      Still I wish someone could formulate how many winners chose the QP option and won that way , verses those that won from picking certain numbers themselves. Or how much they spent. Ive yet to have that *moment* where I just non-chalantly go out for milk and fuel and get the *last* minute urge to plop down a few bucks on QP combos only to win a few days later! Maybe Im too methodical and like to think that my number choice will someday pay out...

                      ~~Is it true, Is it kind,Is it necessary. ~~~

                       Thanks be to the giving numbers: 1621,912,119 02014

                        Stars's avatar - basket
                        Englewood, NJ
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                        Posted: October 17, 2005, 12:16 am - IP Logged

                        The only way to loose is if the jackpot was split with another person(s).

                        Don't forget all the lower tier winnings prizes.  It would be 41 second prizes worth $8.2 million plus the bonus pool money worth many millions more (you would have about 60% (you would have 41 tickets against roughly 25 other bonus pool winners)) of the pool right now, which would be much higher than the posted $13 million (you would have added more than $145 million to their sales projection).

                        You would have over 3 million of the powerball only prize worth $3 each.  That is if they do not pari-mutual the prizes.

                        It's been many years since I had a math class in school, but maybe I'll figure the gain...

                        Yes I do realize that it would be nearly impossible to do...

                          Bradly_60's avatar - disney37
                          Atlantic Mine, Michigan
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                          Posted: October 17, 2005, 12:19 am - IP Logged

                          Yeah I agree....all the small amounts would be such a huge amount that it would probably work.  But buying that many tickets would be a huge team effort.  And a large bank roll to do it with.

                          Brad

                            RJOh's avatar - chipmunk
                            mid-Ohio
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                            Posted: October 17, 2005, 12:33 am - IP Logged

                            FYI of the 146,107,962 possible PB combinations the number of winning combinations are:
                            5/5 +1 = 1
                            5/5 +0 = 41
                            4/5 +1 = 250
                            4/5 +0 = 10,250
                            3/5 +1 = 12,250
                            3/5 +0 = 502,250
                            2/5 +1 = 196,000
                            1/5 +1 = 1,151,500
                            0/5 +1 = 2,118,760
                            Total winning combinations = 3,991,302

                             * you don't need to buy more tickets, just buy a winning ticket * 
                               
                                         Evil Looking       

                              Down's avatar - Sphere animated2.gif
                              Riverside, Ca
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                              Posted: October 17, 2005, 12:45 am - IP Logged

                              why would you try to buy all the combinations? all it takes is one to win