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2 out of 3...

Topic closed. 25 replies. Last post 11 years ago by CalifDude.

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truecritic's avatar - PirateTreasure
Michigan
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Posted: February 10, 2006, 9:44 pm - IP Logged

Tenaj

>Take the last draw (we will use 526) and substract 12 from the first 2 digits.  Do not carry.  Some people carry, if you do it is not lottery math that fit in the scheme of 000-999.

I did specifically ask Cashman that question, about how he did it.  He chose to NOT use wrap-around math.  His details are in that thread.

    Tenaj's avatar - michellea
    Charlotte NC
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    Posted: February 10, 2006, 10:45 pm - IP Logged

    Tenaj

    >Take the last draw (we will use 526) and substract 12 from the first 2 digits.  Do not carry.  Some people carry, if you do it is not lottery math that fit in the scheme of 000-999.

    I did specifically ask Cashman that question, about how he did it.  He chose to NOT use wrap-around math.  His details are in that thread.

    Yes NodR2B2Lynn said she will read the thread.

    takeemtothebank

      BobP's avatar - bobp avatar.png
      Dump Water Florida
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      Posted: February 11, 2006, 2:35 am - IP Logged

      Right, it's lotto-logix.com and it's called the 2in8 system explained in the Lotto Dojo article.  You will always have two of the winning digits when all different digits are drawn.  The system tends to work best when built around a hot number from your game, though you can work a hand exchange system swapping your best pick for one of the numbers.  The advantage is you already have two of the winning digits so the odds drop to only 1in8 on days all different digits are drawn.  To make money you'd have to have a better return then the state pays, successuffly more often then not predict when all different digits will be drawn or are due and apply a money management system of raising the wagers with winnings to make a big score which after a point you may want to move to the state game where collecting large amounts are more certain. See http://www.lotto-logix.com/games.html 

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      BobP


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        Posted: February 11, 2006, 2:17 pm - IP Logged

        You're right badger, it's just a mathematical thing.  The 8 sets idea is not really what I'm looking for.  I'll keep looking.

        You know, it's hard to find systems/strategies that have "profits" and "proofs", to prove they work.

        Then again, since a lot of ideas are free, I guess you get what you pay for.

        Despite of the ODDS, I'm still optimistic. Yes Nod

          LAVERNE MALONEY's avatar - smallgirl

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          Posted: February 11, 2006, 2:55 pm - IP Logged

          You're right badger, it's just a mathematical thing.  The 8 sets idea is not really what I'm looking for.  I'll keep looking.

          You know, it's hard to find systems/strategies that have "profits" and "proofs", to prove they work.

          Then again, since a lot of ideas are free, I guess you get what you pay for.

          Despite of the ODDS, I'm still optimistic. Yes Nod

          Hello there r2b2lynn, I have to ask you: do you play online? If you do, I truly believe that the 8 #'s listed as 039,059,069,124,178,278,356,478 would be very profitable to you just as they appear. Meaning play them straight or boxed.

          Did you see the proof that I showed earlier as to the # of hits per day that can be generated from the 8 #'s. It is just a matter of rotating them throughout the states. This way you will hit all 3 digits, not just 2.

          The 356 listed hit today as 653 in MI-midday & 903 DC-midday. The whole idea is to play from a list of #'s that will give you more than one hit per day if at all possible.   

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            Belgium
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            Posted: February 12, 2006, 8:53 am - IP Logged
            PLEASE TAKE THE EFFORT TO UNDERSTAND WHAT I AM ABOUT TO SAY. IT MAY INCREASE YOUR FUTURE WINNINGS !

             

             

            Quote from BobP
            “The advantage is you already have two of the winning digits so the odds drop to only 1in8 on days all different digits are drawn.”

             

            Obviously, that would be the case if the wheel was a 100% 2if2, which it is NOT !

             

            Analysis of the wheel posted by lotto-logix owner BobP
            First, the wheel is a split wheel…

             

            2310478569
            XXX
            XX X
            XX  X
              XXX
                XXX
                XX X
                XX  X
                  XXX

             

            If all different digits are drawn, there are 45 possible pairs of 2 numbers
            C(10,2) = (10 x 9)/2 = 45
            This wheel covers 20 of the 45 possible pairs (2if2)
            On average, when you play this wheel, matching the 1st and 2nd winning number and having a 1/8 chance to hit that 3rd number as well will occur 20 times over a period of 45 draws when all different digits are drawn.
            Of course, this wheel has some overlap (2 pairs are played three times). The overlap factor is the total amount of pairs played (24) divided by the total amount of unique pairs played (20).

             

            Which brings us to the end result. This wheel will hit all 3 digits once every ...

             

            (20/45 x 1/8 x 24/20 = 480/7200 = 1/15) ... 15 draws when all different digits are drawn.

             

             

            Conclusions :
            Hitting 3 winning numbers by playing 8 random lines from a possible 120 different outcomes (three unique digits) will occur once every 15 draws (120/8). This wheel is no different.

             

             

            How to attack the odds :
            Any draw is a sequence of events. In case of a pick-3 lottery, we can distinguish 3 events, and each event has different odds. A good lottery system allows us to attack the odds of each separate event. To prove you this, let’s imagine 3 things :
            -        We played one single pick-3 ticket (boxed).
            -        The draw takes place over 3 days (1 number each day)
            -        Three unique digits will be drawn (720 possible unique possibilities - no doubles or triples)

             

            Day 1 : the first winning number is about to be drawn...
            We have a 1/720 chance (1/10 x 1/9 x 1/8) to hit all 3 numbers over a period of 3 days. If none of our 3 numbers on our ticket matches the first winning number : Game Over

             

            Day 2 : the second winning number is about to be drawn...
            If our ticket matched yesterdays first winning number, we have a 1/72 chance (1/9 x 1/8) to hit the next 2 numbers. If none of our 2 remaining numbers matches the second winning ball :  Game Over

             

            Day 3 : the final and third winning number is about to be drawn...
            If our ticket didn’t fail to match the first and second winning number, we have a 1/8 chance to hit the final number.

             

            First conclusion : each time our ticket survives a draw, it gets better odds
            Day 1 : 1/720
            Day 2 : 1/72
            Day 3 : 1/8

             

            Second conclusion : without a lottery system (1 ticket) we need 3 times luck in a row to hit all 3 winning numbers

             

            Third conclusion : The draw is a sequence of draws. Matching all 3 winning numbers can’t be achieved if our ticket fails to survive the first 2 events.

             

             

            How to attack the odds of the first event (day 1):
            Simple : we need a 1if1 lottery system...

             

            C(10,3,1,1)=4
            123
            456
            789
            014

             

            By playing a simple 1if1 system, we are guaranteed that 1 or 2 tickets will survive Day 1
            4 random tickets do not have this guarantee (e.g. 123 – 124 – 125 – 126 won’t survive numbers 7, 8, 9 and 0)

             

            How to attack the odds of the first 2 events (day 1 and day 2) :
            Simple : we need a solid 2if2 lottery system (and not a 2if3 split-wheel like the one posted on lotto-logix)...

             

            C(10,3,2,2)=17

             

            017
            024
            038
            059
            067
            123
            145
            167
            189
            246
            259
            278
            348
            357
            369
            479
            568

             

            By playing this wheel, we are guaranteed that 1 or 2 tickets will survive Day 1 and Day 2, thus having a 1/8 chance to hit the 3rd and final number (= first prize).

             

            If the draw would take 3 days, I am sure everyone would play a 2if2 wheel. However, we don’t feel that better chance because the draw takes place at dazzling speeds. Odds don’t mix with time-related feelings : that better chance is there !

             

            This 2if2 wheel posted above covers 45 of the 45 possible pairs (100% 2if2)
            On average, when you play this wheel, matching the 1st and 2nd winning number and having a 1/8 chance to hit that 3rd number as well will occur 45 times over a period of 45 draws when all different digits are drawn.
            Of course, this wheel has some overlap. The overlap factor is the total amount of pairs played (51) divided by the total amount of unique pairs played (45).

             

            Which brings us to the end result. This wheel will hit all 3 digits once every ...

             

            (45/45 x 1/8 x 51/45 = 2295/16200 = 1/7.05) ... 7 draws when all different digits are drawn.

             

            Final conclusion :
            Hitting 3 winning numbers by playing 17 random lines from a possible 120 different outcomes (three unique digits) will occur once every 7.05 draws (120/17). This wheel is no different. However, this wheel allows us to outsmart the sequence of the draw, which as a consequence results in better averages. Better averages allow us to better predict when to play, but more importantly, when not to play. Of course, the performance of a single 2if2 system has still some deviation, which inspired me to store 7 unique 2if2 systems in a map that looks exactly like the one you see below.
             
            012 013 014 015 016 017 018 019 023 024
            025 026 027 028 029 034 035 036 037 038
            039 045 046 047 048 049 056 057 058 059
            067 068 069 078 079 089 123 124 125 126
            127 128 129 134 135 136 137 138 139 145
            146 147 148 149 156 157 158 159 167 168
            169 178 179 189 234 235 236 237 238 239
            245 246 247 248 249 256 257 258 259 267
            268 269 278 279 289 345 346 347 348 349
            356 357 358 359 367 368 369 378 379 389
            456 457 458 459 467 468 469 478 479 489
            567 568 569 578 579 589 678 679 689 789

             

             

             

            Not a single number of the one’s you see above occurs twice in any of the 7 2if2’s I created (believe me : sounds easy, but it’s not !). A quick calculation learns that I have used 119 (C(10,3,2,2)=17 x 7= 119) of the 120 possible unique combinations (no doubles or triples). This allows me to track which system nature (chaos) prefers at a certain moment in time instead of tracking just numbers. Although I am still very sceptical, I must say I have obtained some amazing results. At this very moment - I am still experimenting on paper – I am $25,000 US ahead (3 months virtual profit). I will make the switch to real money as soon as I am convinced that my strong believe that nobody can make a consistent profit on the lottery has been dead wrong after all.

             

             

            Best regards,

             

            Stefan V.

             

            P.S. Robert, you and I both know that only a few people on this globe (Adolf Muehl is definitely one of them) do understand that the odds do change while the sequence of the draw takes place. As a consequence, the only lottery wheels that do make sense are non-split wheels that implement a 2if2, 3if3, 4if4, 5if5 or 6if6. Although I believe I shouldn’t interfere with anyone’s business, I sincerely hope you will adapt your lotto dojo article in a proper way.
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              Belgium
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              Posted: February 12, 2006, 9:00 am - IP Logged

              The text format of my post mispresented the split wheel. Hope it works out this time.

              2310478569

               

              XXX.......=123

               

              XX.X......=023

               

              XX..X.....=234

               

              ..XXX.....=014

               

              .....XXX..=578

               

              .....XX.X.=678

               

              .....XX..X=789

               

              .......XXX=569

               

                truecritic's avatar - PirateTreasure
                Michigan
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                Posted: February 12, 2006, 1:37 pm - IP Logged

                stefan

                This allows me to track which system nature (chaos) prefers at a certain moment in time instead of tracking just numbers. Although I am still very sceptical, I must say I have obtained some amazing results. At this very moment - I am still experimenting on paper – I am $25,000 US ahead

                I don't see where you explained any details of how you are ahead with play money?

                  Avatar
                  Richland/Pennsylvania
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                  Posted: February 12, 2006, 2:11 pm - IP Logged

                  You can make your own 2 of of 3 sets...Take the number...say 365...36,65,35 pairs are represented...now make another number that has 3 different sets of Pairs...say 105....10,05,15...Each number cannot have repeat pairs from the others....Do this 8 or 9 times..Remember not to allow repeat pairs and you will have 2 out of 3 every time..Its fun to do with favorite,personal numbers,frequent numbers...ect...


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                    Posted: February 13, 2006, 1:24 pm - IP Logged

                    Hmmm...you know, maybe the 8 sets is more than mathematical.
                    Maybe some other 2 out of 3 systems are more than meets the eye, too.
                    Keep at it.

                    Like many of you out there, my mind is open for opportunity. Idea

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                      Poway CA (San Diego County)
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                      Posted: February 13, 2006, 1:41 pm - IP Logged

                      The 8 sets of numbers have been around a long time.  I paid for them a long time ago (before even knowing about Lottery Post!).  The claim for the 8 numbers is that you will have at least 2 correct digits 96% of the time and it is at least that from my experience.

                      Here is a 2if2 wheel:

                      012,047,068,138,148,157,234,256,278,358,367,456,903,905,916,928,947