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# Powerball.How to profit:speculation

Topic closed. 1 reply. Last post 11 years ago by pumpi76.

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Honduras
Member #20982
August 29, 2005
4715 Posts
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 Posted: May 31, 2006, 1:11 am - IP Logged

This is just a wild talk/speculation, i may be wrong. Looking at lotterywheels.com, i noticed they got a wheel named: Y6-5T620. is a size 20 wheel that guarantees 2, 5of6 if 6 in 20 and requires 2040 sets. What you need is a size 30 wheel (is a good size of the game). that guarantees 2 tickets having 5of6. If you are confident enough that you can select 30 numbers consistently, that will have the 6 winning numbers, then is possible you could make a huge profit. If you get it right the first or second time, you would have made a big profit, and depending on who you are, may not need to bet again, but again that's "if". Now judging by the increments in sets and sizes that a pick6 wheel does in lotterywheels website, i'll "SPECULATE" that a 30sized wheel that guarantees 2, 5of6 would run you about less than 8,000 sets, it could well be less than 10,000 sets. If you get the 6 numbers right in those 30 numbers, you will have made 400,000. Now, if you want to reduce that wheel, you look at powerball history and you look for the number one most predominant ratio of evens over odds, whether is 4/2, 1/5, 3/3, etc, etc. For it to be predominant a ratio will have to be present i'll say 75 percent of the time. And what you do is you filter the 30 size wheel and you let the wheel have only that 1 most predominant ratio. A wheel is like a compound; is formed by the chemical combination of two or more pure substances in a fixed, definite ratio. Same thing a wheel is formed by the grouping/weaving of several even over odds ratio in a fixed proportion/ratio. I've looked at wheels and i'll speculate that a 30 sized wheel with 2, 5of6 will have a 35% of each of the different even over odds ratios. If is true, that 1 predominant ratio will account for 35% of the entire wheel, then you can eliminate 65% of the combinations and keep 35% that carry that specific predominat ratio. And since you are confident that you can pick30 numbers and contain the 6 winning numbers, then all you have to do is wait for the most predominat ratio to appear, which should be soon since is plays 75% of the time. Even if you the 30 numbers wrong the first time, you would had spent 35% of 8,000 or 2,800..I call this approach "waiting in line", since it resembles waiting in line, you are sort of waiting for the 1 most predominant ratio to appear...If you could only get a wheel like that and import it into a software and further filter it, then you will be set. Not only you could make a profit, but who knows you could be lucky and match that extra number of the 5of6 combinations and match all 6 numbers. This tactic poses some challenges. Powerball is a pick5+pick1 (bonus ball) game. I believe it requires a pick5 wheel, and you to guess the 6th numbers or bonus ball. You see the inclusion of a bonus ball in the game presents a problem. Using a pick6 wheel for a game that has a bonus ball, the selecting of the bonus ball is what will obstruct with the flow of the wheel. But if you could circumvent that problem and still select a bonus ball, then it would be amazing. Another thing, i don't think lotterywheels.com is going to sell you such a wheel if they had it, but again is just my opinion..Guys, this is the only way i can think of approaching the problem of trying to hit powerball. For it to work you will have to predict those 30 numbers correctly consistently..Is all speculation: hypothesis, though. If it works, then i believe is a good way to hit powerball and not predicting with 10 and 20 combinations, like i see some people do. With 10 & 30 combinations is impossible. Guys, i will appreciate your input and if you tell me what's wrong with this speculation/hypothesis, i'll be glad...

"More important than winning all the states' lotteries, is the movie "Red Planet..."

Honduras
Member #20982
August 29, 2005
4715 Posts
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 Posted: June 1, 2006, 3:47 am - IP Logged

Another thing i just remember is that a wheel that guarantees 2 tickets with 5 of 6 has the following. Because of the "nature of the guarantee", if for whatever reason you miss the 2 tickets with 5 of 6 (though i doubt it), the wheel will be loaded with tickets of 4 of 6 matches. And judging by the number of sets of the wheel and by the progressive increments that pick6 size 25, with 4of 6 guaratee, carries [Y6A4T625 sets minus Y6-4T625 sets] i'll say that the 8,000 set, 30 number-sized wheel would have at least 12 tickets matching 4 of 6 [it could be more], wich for powerball pays 100 dollars, [mega million 150], giving you a refund of 1200 dollars back. And since you reduced the 8,000 set wheel to 2800, you would had actually spent 1600 dollars...Is for sure that you would have gotten several 4 of 6 tickets, but as to the exact number it remains speculation...The flaw with this argument is that you would had lost perhaps key 4 of 6 guarantees since you did a one most predominant ratio filtering, however i say that the lost would have been minimal...Whether you filter it or not, you would still profit...the challenge is then predicting those 30 numbers correctly and taking care of the bonus/mega ball which is "in the way" obstructing with the flow of the pick6 wheel...

I forgot to mention also that when searching for the one most predominant ratio, you have to view powerball/mega-millions as a pick6 game and not for what it is a pick5+pick1 bonus ball. I consider powerball a pick6 because it has higher odds than a pick6, 1-57 and since you must match 6 balls to win the jackpot..

"More important than winning all the states' lotteries is the movie "Red Planet".......i don't wish it to nobody....."

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