Welcome Guest
You last visited December 4, 2016, 3:15 pm
All times shown are
Eastern Time (GMT-5:00)

# Bet on 2 Digit Return Pick 4

Topic closed. 5 replies. Last post 10 years ago by Stack47.

 Page 1 of 1
Stone Mountain*Georgia
United States
Member #828
November 2, 2002
10491 Posts
Offline
 Posted: June 10, 2006, 1:33 pm - IP Logged

Notice 2 of the 4 digits return next draw in Pick 4.... A Lot !

OK,, then,, Gamble along with that fact

Example of the 4 drawn  0123 ......

456789 not drawn

Picking the 2 of the 4 digits digits at random to return in the next draw could give us 6 pairs

01,  02,03,  ..or..  12,13,23

Lets bet with the 01 pair to return.

Now put the returning pair with the 6 other numbers that didn't hit today. Those would be 4,5,6,7,8,9

That would give us only 15 pairs to play

45 46 47 48 49

56 57 58 59

67 68 69       + using returning pair 01

78 79

89

01..45   0146  0147  0148  0149  etc.

= only 15 numbers

Wheel 01 with the doubles if you think a    double may hit next. Only 10 more

15 x .25 cents = \$ 3.75

10 doubles x .25 = \$2.50

The only real failure .....is the failure to try.

Luck is a very rare thing....... Odds not so much.

Odds never change .....but probability does.

Win d

United States
Member #14
November 9, 2001
31343 Posts
Offline
 Posted: June 10, 2006, 1:41 pm - IP Logged

good to see you

love to nibble those micey feet.

Stone Mountain*Georgia
United States
Member #828
November 2, 2002
10491 Posts
Offline
 Posted: June 10, 2006, 1:52 pm - IP Logged

Note ...  we can make 5 pairs from each of 6 un- hit digits each day. Because of the cross over repeat pairs we only end up with 15 total.

Picking which 2 digits will return next draw is really pretty easy some days. What the heck... .......  pick 2 of the 4 digits and go with it.  For  \$3  dollars ?  Go for it .... LOL

P.S. Hey sweet EM !

The only real failure .....is the failure to try.

Luck is a very rare thing....... Odds not so much.

Odds never change .....but probability does.

Win d

Kentucky
United States
Member #32652
February 14, 2006
7297 Posts
Offline
 Posted: June 13, 2006, 6:30 pm - IP Logged

WIN D,

How about picking the key pair to play from the 15 pairs that didn't hit the previous draw; having only 6 combos or adding the 4 doubles and playing 10?

Using your example of 1234 and 56 as the key pair:

5612 5613 5614 5623 5624 5634

5611 5622 5633 5644

Two of the digits do return a lot but at least one digit returns a lot more. Tntea has been trying to first pick a key pair, and then reduce the 55 combinations. If we filter using your method and say "at least one number must return from the previous draw", it would be reduced to 34 combinations:

0156 0256 0356 0456 1156 1256 1356

1456 1556 1566 1567 1568 1569 2256

2356 2456 2556 2566 2567 2568 2569

3356 3456 3556 3566 3567 3568 3569

4456 4556 4566 4567 4568 4569

Stack

United States
Member #5344
June 30, 2004
23641 Posts
Offline
 Posted: June 13, 2006, 8:26 pm - IP Logged

Running a test on here would be a great idea.. Thanks..

OLD/Vtrac

Kentucky
United States
Member #32652
February 14, 2006
7297 Posts
Offline
 Posted: June 14, 2006, 5:37 pm - IP Logged

Tntea, I was looking at the mathematical probability suggested by WIN D; if two, one, or no digits repeat the following draw, a pair from the six digits that didn’t hit (seven digits for doubles) will hit the following draw.

As an example, Ohio’s mid Day draw on Monday was 6820 so we would have 15 pair possibilities (13 14 15 17 19 34 35 37 39 45 47 49 57 59 79). If two or less of Monday’s digits repeat, 1, 3, or 6 of the 15 pairs must hit in the following draw. Tuesday’s draw was 7815 so 15, 17, or 57 could be used as the key pair.

The only test would be to determine the percentage of draws when 3 or 4 digits repeat and that is about 4%. This means that in 96% of the draws, we have at the most 21 pairs (when a double hits) where one or more of these pairs will hit.

Even though this gives us “will hit pairs”, we still need a method to determine which pair to play.

Stack

 Page 1 of 1