Another interesting piece of info is that a combination of numbers picked within the last 45 days will repeat in ANY order about once in every 4 to 5 draws. That is, if 123 came in within the last 45 draws, there's a possibility that it could come in again but as, for example, 321. Of course, playing 45 previous numbers might be too many. Maybe you could remove those that already repeated, approximately 10 or so on average. Then maybe you could leave out doubles as non-doubles would have a better chance to repeat because of the number of combinations (6 to 3). But that's not to say that doubles don't repeat, they do. Rarely does a pick within the last 5, let's say, repeat so soon, so that's 5 more that could be removed from your list. That leaves how many? 45 - 10 previous repeaters - 10 (1 in 4) doubles - the last 5 = 20. So, 20 picks every night is $5 a night at .25 a ticket (you know where) trying to win $37.50 so you'd need to win once every 7 draws to at least break even and if it sticks to average you should be able to do that. So, what do you think of that one?
FROM THREE2001