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Powerball probability question

Topic closed. 6 replies. Last post 10 years ago by jarasan.

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United States
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December 4, 2005
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Posted: October 27, 2006, 4:27 pm - IP Logged

What is the probabilty of getting all the white balls and not the powerball when buying 5, 10, 20 quick picks for one drawing?  What is the formula?

I am sure the answer has already been posted on this forum.  I searched but I could not find it.

Lovies 

Thanks to all the experts!

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    United States
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    Posted: October 27, 2006, 5:33 pm - IP Logged

    1 in 3.5 million.  Per ticket.

      Coin Toss's avatar - shape barbed.jpg
      Zeta Reticuli Star System
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      Posted: October 27, 2006, 6:19 pm - IP Logged

      1 in 3.5 million.  Per ticket.

      Excellent way to put it!

        Thoth's avatar - binary
        Findlay, Ohio
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        May 28, 2004
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        Posted: October 28, 2006, 1:08 am - IP Logged

        What is the probabilty of getting all the white balls and not the powerball when buying 5, 10, 20 quick picks for one drawing?  What is the formula?

        I am sure the answer has already been posted on this forum.  I searched but I could not find it.

        Lovies 

        Thanks to all the experts!

        Here is the formula for finding your odds of having the first five numbers but not the powerball but not the winning powerball at the same time

         

        (55!) ÷ ((55-5)!)
                      --------------------    Χ 42 ÷ 41
        (5!))

         

        This will give you odds of 1 in 3,563,608.83.  There are 3,478,761 five number white ball combinations but the above formula takes into consideration the chance that you could actually get the powerball right.  I don't believe you can play the game without picking a powerball so you should include it in your odds.

        The probability for 20 random combinations would be 0.000005612288261 or 20 in 3,563,608.83, which is about 1 in 178,180.44 as a reduced fraction.

         

         

        ~Probability=Odds in Motion~

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          NY
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          Posted: October 28, 2006, 1:10 am - IP Logged

          The easy formula is to look at powerball.com, and click on "how to play" and then the "9 ways to win" link to find the odds. Not that it's a big difference, but it's pretty close to 1 in 3.56 million for each ticket. Your overall odds are determined by dividing the odds by the number of tickets you have, assuming each ticket has a different set of numbers. Buy 10 tickets and you've got a 1 in 356,000 chance of hitting 5+0. Buy 20 ticket and it's 1 in 178,000.  Of course your odds of winning anything at all are only about 1 in 36, so buying 20 tickets is a better strategy for losing $20 than it is for improving your chances of winning something.

            Thoth's avatar - binary
            Findlay, Ohio
            United States
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            Posted: October 28, 2006, 2:32 pm - IP Logged

            The easy formula is to look at powerball.com, and click on "how to play" and then the "9 ways to win" link to find the odds. Not that it's a big difference, but it's pretty close to 1 in 3.56 million for each ticket. Your overall odds are determined by dividing the odds by the number of tickets you have, assuming each ticket has a different set of numbers. Buy 10 tickets and you've got a 1 in 356,000 chance of hitting 5+0. Buy 20 ticket and it's 1 in 178,000.  Of course your odds of winning anything at all are only about 1 in 36, so buying 20 tickets is a better strategy for losing $20 than it is for improving your chances of winning something.

            "...buying 20 tickets is a better strategy for losing $20 than it is for improving your chances of winning something."

            Actually your chances of winning "something" goes up drastically when playing 20 different combos.  Of course this doesn't mean your chances of wining an actual profit will improve much.

            If you played the same group of 20 different combos with hopes of winning 5 of 5 without the powerball, you would have to play the same 20 combos for about 123,505 consecutive games to give yourself a real 50% probability of winning the $200,000 prize.  Playing 20 combos this long would cost $2,470,100.00—Definitely not a good stategy.

            ~Probability=Odds in Motion~

              jarasan's avatar - new patrick.gif
              Harbinger
              D.C./MD.
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              July 30, 2006
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              Posted: November 3, 2006, 8:58 pm - IP Logged

              Another formula:

              55/5 x 54/4 x 53/3 x 52/2 x 51/1 =

              11 x 13.5 x 17.6 x 26 x 51=

              3,465,633.6

              ~1 in 3.5 mil.

              There are a lot of opinions of playing 20 tix as opposed to 1 ticket, my opinion is: 20 tix gives you 20 1 in 3.5 mil. bets,   because the odds still remain the same,  each ticket is still a 1 in 3.5 million bet, making 20 different bets, doesn't change (or improve) significantly  the odds of anyone person hitting 5 of 5 in Powerball. You might hit a little one (3/5,4/5), maybe, if you are really lucky.  I know there are people out there that have spent $100's, $1000's over the years and hit nothing better than 3/5.  Theoretically if you play 1000 tix the odds would then be roughly 1 in 3500, much better than 1 in 178,000 (still not even close to staright Pick 3 odds), would you bet on these odds a thousand bucks?  LOL jarasanUS Flag