|Posted: November 21, 2006, 4:35 am - IP Logged|
However in the number 1859095435601128890252 there are the following repeated numbers
0 - 3
1 - 3
2 - 3
5 - 4
8 - 3
9 - 3
But they are not all consecutive.
1 and 8 have a consecutive repeat of 11 and 88.
Actual I wasn't referring to consecutive repeats. ??
hmm..... maybe I shouldn't use to the word "repeat" at all because technically one could say a repeat doesn't occur until the digit has already been drawn at least once.
How about "Digit Count" within total permutations? My goal was to find the exact number of times a particular digit occurred within the total amount of permuations that are possible...effectively giving the exact probability for a particular digit to occur X amount of times within X amount of games....in this case, it's 22 consecutive trials of picking a number between 0 and 9. Im still confused as to how to apply a formula for finding the total outcome patterns/basic forms.
~Probability=Odds in Motion~