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1200-year-old problem

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Posted: December 8, 2006, 9:20 pm - IP Logged

Dr James Anderson, from the University of Reading's computer science department, says his new theorem solves an extremely important problem - the problem of nothing.

4/4 = 1 3/3 = 1 2/2 = 1 1/1 = 1 0/0 = 1

Beautiful Florida

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Posted: December 8, 2006, 9:40 pm - IP Logged

That was actually solved 1199 years ago, by Dr.goodfornuttin...!

" You can not control the Wind, but you can direct the Sail "

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The Quantum Master

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Online Posted: December 10, 2006, 10:17 pm - IP Logged

I see two incorrect statements:

1. 0^{-1} = (1 / 0) = ¥ , is not correct

2. ¥ ^{-1} = (1 / ¥ ) = 0 , is not correct

Presented 'AS IS' and for Entertainment Purposes Only. Any gain or loss is your responsibility. Use at your own risk.

Order is a Subset of Chaos Knowledge is Beyond Belief Wisdom is Not Censored Douglas Paul Smallish Jehocifer

The Quantum Master

West Concord, MN

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December 7, 2001

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Online Posted: December 10, 2006, 11:03 pm - IP Logged

Quote: Originally posted by on December 10, 2006I see two incorrect statements:

1. 0^{-1} = (1 / 0) = ¥ , is not correct

2. ¥ ^{-1} = (1 / ¥ ) = 0 , is not correct

0 ^{-1} = (1 / 0) = ¥ and ¥ ^{-1} = (1 / ¥ ) = 0 are incorrect and 0 ^{-1} is a new number I, the Hyper-infinite number.

1 - Reciprocal Operation with Inequality

a > b

taking the reciprocal of both side causes the > to change to <.

reciprocal of a > b is a^{-1} < b^{-1}

a > b a^{-1} < b^{-1} a b a^{-1} b^{-1} 1 0.25 1.00000 4.00000 1 0.5 1.00000 2.00000 2 1 0.50000 1.00000 2 1.5 0.50000 0.66667 10 5 0.10000 0.20000 10 9 0.10000 0.11111 1000 500 0.00100 0.00200 1000 900 0.00100 0.00111

2 - Apply Reciprocal Operation of Inequality to the Inequality of ¥ ^{-1} > 0

¥ ^{ -1} > 0

the reciprocal of ¥ ^{ -1} > 0 is ¥ < 0^{ -1}

if the inequality ¥ < 0^{ -1} is true, then 0 ^{-1} is a new number, I, and exists outside the set of Real numbers or Hyper-infinite.

the number I is analogous to the number i = Ö -1

3 - Some other additional inequalities and equalities

0 ¹ ¥ ^{ -1}

0^{ -1} ¹ ¥

I = 0^{ -1} Hyper-infinite number

0 ´ I = 1

1 ´ I = I

n ´ I = nI

0 ´ nI = n

a is Real and bI is Hyper-infinite, then the sum of a and bI is complex and is a + bI

Presented 'AS IS' and for Entertainment Purposes Only. Any gain or loss is your responsibility. Use at your own risk.

Order is a Subset of Chaos Knowledge is Beyond Belief Wisdom is Not Censored Douglas Paul Smallish Jehocifer

The Quantum Master

West Concord, MN

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December 7, 2001

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Online Posted: December 11, 2006, 5:15 am - IP Logged

Something of a proof why ¥ ^{-1} ¹ 0 and ¥ ^{-1} > 0

1 - If ¥ ^{-1} = 0 , then 0 + ¥ ^{-1} = 0

0 + ¥ ^{-1} = 0

0 + ( 1 / ¥ ) = 0

0 ( ¥ / ¥ ) + ( 1 / ¥ ) = 0

( ( 0 * ¥ ) / ¥ ) + ( 1 / ¥ ) = 0

( 0 * ¥ + 1 ) / ¥ = 0

0 * ¥ + 1 = 0 * ¥

( 0 * ¥ ) - ( 0 * ¥ ) + 1 = ( 0 * ¥ ) - ( 0 * ¥ )

0 + 1 = 0

1 = 0

1 = 0 , is false \ ¥ ^{-1} ¹ 0

2 - If ¥ ^{-1} > 0 , then 0 + ¥ ^{-1} > 0

0 + ¥ ^{-1} > 0

0 + ( 1 / ¥ ) > 0

0 ( ¥ / ¥ ) + ( 1 / ¥ ) > 0

( ( 0 * ¥ ) / ¥ ) + ( 1 / ¥ ) > 0

( 0 * ¥ + 1 ) / ¥ > 0

0 * ¥ + 1 > 0 * ¥

( 0 * ¥ ) - ( 0 * ¥ ) + 1 > ( 0 * ¥ ) - ( 0 * ¥ )

0 + 1 > 0

1 > 0

1 > 0 , is true \ ¥ ^{-1} > 0

When dealing with 0 and ¥ it is better to treat them as if they were variables first and do normal math operations first, then work the final equation or inequality. There are times when 0^{2} ¹ 0 and ¥ ^{2} ¹ ¥ , much like X^{2} does not exactly equal X.

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Order is a Subset of Chaos Knowledge is Beyond Belief Wisdom is Not Censored Douglas Paul Smallish Jehocifer

The Quantum Master

West Concord, MN

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Online Posted: December 11, 2006, 5:39 am - IP Logged

Also, 0 * ¥ is a non-reduceable number much like 2i is a non-reduceable number, it is what it is, a number all by itself.

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Order is a Subset of Chaos Knowledge is Beyond Belief Wisdom is Not Censored Douglas Paul Smallish Jehocifer

The Quantum Master

West Concord, MN

United States

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December 7, 2001

3942 Posts

Online Posted: December 11, 2006, 5:50 am - IP Logged

In addition, ¥ ^{-1} is the infinitesimal unit and is exactly and only exactly the first number after 0.

Presented 'AS IS' and for Entertainment Purposes Only. Any gain or loss is your responsibility. Use at your own risk.

Order is a Subset of Chaos Knowledge is Beyond Belief Wisdom is Not Censored Douglas Paul Smallish Jehocifer

The Quantum Master

West Concord, MN

United States

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December 7, 2001

3942 Posts

Online Posted: December 11, 2006, 10:04 am - IP Logged

Some more:

n ¥ = ¥

( n ¥ ) / ¥ = ¥ / ¥

n ( ¥ / ¥ ) = ¥ / ¥

n ( 1 ) = 1

n = 1, \ n ¥ = ¥ true when n = 1

n ¥ ¹ ¥

( n ¥ ) / ¥ ¹ ¥ / ¥

n ( ¥ / ¥ ) ¹ ¥ / ¥

n ( 1 ) ¹ 1

n ¹ 1, \ n ¥ ¹ ¥ true when n ¹ 1

n ¥ = -¥

( n ¥ ) / ¥ = -¥ / ¥

n ( ¥ / ¥ ) = -¥ / ¥

n ( 1 ) = -1

n = -1, \ n ¥ = ¥ true when n = -1

n ¥ ¹ -¥

( n ¥ ) / ¥ ¹ -¥ / ¥

n ( ¥ / ¥ ) ¹ -¥ / ¥

n ( 1 ) ¹ -1

n ¹ -1, \ n ¥ ¹ -¥ true when n ¹ -1

Presented 'AS IS' and for Entertainment Purposes Only. Any gain or loss is your responsibility. Use at your own risk.

Order is a Subset of Chaos Knowledge is Beyond Belief Wisdom is Not Censored Douglas Paul Smallish Jehocifer

The Quantum Master

West Concord, MN

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December 7, 2001

3942 Posts

Online Posted: December 11, 2006, 10:24 am - IP Logged

And just a bit more:

0 * ¥ = n

( 0 * ¥ ) / ¥ = n / ¥

0 ( ¥ / ¥ ) = n / ¥

0 ( 1 ) = n / ¥

0 = n / ¥ , if and only if n = 0 * ¥

0 * ¥ = n

( 0 * ¥ ) / 0 = n / 0

¥ ( 0 / 0 ) = n / 0

¥ ( 1 ) = n / 0

¥ = n / 0

¥ = n / 0 , if and only if n = 0 * ¥

Presented 'AS IS' and for Entertainment Purposes Only. Any gain or loss is your responsibility. Use at your own risk.

Order is a Subset of Chaos Knowledge is Beyond Belief Wisdom is Not Censored Douglas Paul Smallish Jehocifer

The Quantum Master

West Concord, MN

United States

Member #21

December 7, 2001

3942 Posts

Online Posted: December 11, 2006, 10:39 am - IP Logged

Quote: Originally posted by on December 11, 2006Some more:

n ¥ = ¥

( n ¥ ) / ¥ = ¥ / ¥

n ( ¥ / ¥ ) = ¥ / ¥

n ( 1 ) = 1

n = 1, \ n ¥ = ¥ true when n = 1

n ¥ ¹ ¥

( n ¥ ) / ¥ ¹ ¥ / ¥

n ( ¥ / ¥ ) ¹ ¥ / ¥

n ( 1 ) ¹ 1

n ¹ 1, \ n ¥ ¹ ¥ true when n ¹ 1

n ¥ = -¥

( n ¥ ) / ¥ = -¥ / ¥

n ( ¥ / ¥ ) = -¥ / ¥

n ( 1 ) = -1

n = -1, \ n ¥ = ¥ true when n = -1

n ¥ ¹ -¥

( n ¥ ) / ¥ ¹ -¥ / ¥

n ( ¥ / ¥ ) ¹ -¥ / ¥

n ( 1 ) ¹ -1

n ¹ -1, \ n ¥ ¹ -¥ true when n ¹ -1

Some more:

n ¥ = ¥

( n ¥ ) / ¥ = ¥ / ¥

n ( ¥ / ¥ ) = ¥ / ¥

n ( 1 ) = 1

n = 1, \ n ¥ = ¥ true when n = 1

n ¥ ¹ ¥

( n ¥ ) / ¥ ¹ ¥ / ¥

n ( ¥ / ¥ ) ¹ ¥ / ¥

n ( 1 ) ¹ 1

n ¹ 1, \ n ¥ ¹ ¥ true when n ¹ 1

n ¥ = -¥

( n ¥ ) / ¥ = -¥ / ¥

n ( ¥ / ¥ ) = -¥ / ¥

n ( 1 ) = -1

n = -1, \ n ¥ = - ¥ true when n = -1 <--- correction from previous post

n ¥ ¹ -¥

( n ¥ ) / ¥ ¹ -¥ / ¥

n ( ¥ / ¥ ) ¹ -¥ / ¥

n ( 1 ) ¹ -1

n ¹ -1, \ n ¥ ¹ -¥ true when n ¹ -1

Presented 'AS IS' and for Entertainment Purposes Only. Any gain or loss is your responsibility. Use at your own risk.

Order is a Subset of Chaos Knowledge is Beyond Belief Wisdom is Not Censored Douglas Paul Smallish Jehocifer

The Quantum Master

West Concord, MN

United States

Member #21

December 7, 2001

3942 Posts

Online Posted: December 11, 2006, 5:10 pm - IP Logged

The mathematical operation of X / X = 1 must be continuous for all Real values of X; including {-¥ , 0, ¥ }.

1 - If X / X = 1, then -¥ / -¥ = 1

-¥ / -¥ = 1

-¥ = 1 * -¥

-¥ = -¥ , true \ -¥ / -¥ = 1

2 - If X / X ¹ 1, then -¥ / -¥ ¹ 1

-¥ / -¥ ¹ 1

-¥ ¹ 1 * -¥

-¥ ¹ -¥ , false \ -¥ / -¥ = 1

3 - If X / X = 1, then 0 / 0 = 1

0 / 0 = 1

0 = 1 * 0

0 = 0, true \ 0 / 0 = 1

4 - If X / X ¹ 1, then 0 / 0 ¹ 1

0 / 0 ¹ 1

0 ¹ 1 * 0

0 ¹ 0, false \ 0 / 0 = 1

5 - If X / X = 1, then ¥ / ¥ = 1

¥ / ¥ = 1

¥ = 1 * ¥

¥ = ¥ , true \ ¥ / ¥ = 1

6 - If X / X ¹ 1, then ¥ / ¥ ¹ 1

¥ / ¥ ¹ 1

¥ ¹ 1 * ¥

¥ ¹ ¥ , false \ ¥ / ¥ = 1

7 - If Y = 1 and is continuous for all Real values in the function Y = f(X) and f(X) = X / X, then Y = 1 = X / X and is continuous for all Real values

Y = 1 = X / X

Y * X = 1 * X = X

Y * X = 1 * X = X

1 * X = 1 * X = X

X = X = X, true if and only if Y = 1

-¥ = -¥ = -¥ , true if and only if Y = 1

0 = 0 = 0, true if and only if Y = 1

¥ = ¥ = ¥ , true if and only if Y = 1

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Order is a Subset of Chaos Knowledge is Beyond Belief Wisdom is Not Censored Douglas Paul Smallish Jehocifer

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WHEW

I know how to add, subtract and multiply. I think.

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Mathematics Forum :The place to discuss the strong ties between lotteries and mathematics.

Excuse me, but I think I'm missing the strong tie between lotteries and mathematics in this thread.