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1200-year-old problem

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Posted: December 8, 2006, 9:20 pm - IP Logged

Dr James Anderson, from the University of Reading's computer science department, says his new theorem solves an extremely important problem - the problem of nothing.

4/4 = 1 3/3 = 1 2/2 = 1 1/1 = 1 0/0 = 1

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Posted: December 8, 2006, 9:40 pm - IP Logged

That was actually solved 1199 years ago, by Dr.goodfornuttin...!

" When Injustice Becomes Law, Resistance Becomes Duty "

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Posted: December 8, 2006, 10:22 pm - IP Logged

The Quantum Master

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Posted: December 10, 2006, 10:17 pm - IP Logged

I see two incorrect statements:

1. 0^{-1} = (1 / 0) = ¥ , is not correct

2. ¥ ^{-1} = (1 / ¥ ) = 0 , is not correct

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Order is a Subset of Chaos Knowledge is Beyond Belief Wisdom is Not Censored Douglas Paul Smallish Jehocifer

The Quantum Master

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Posted: December 10, 2006, 11:03 pm - IP Logged

Quote: Originally posted by on December 10, 2006I see two incorrect statements:

1. 0^{-1} = (1 / 0) = ¥ , is not correct

2. ¥ ^{-1} = (1 / ¥ ) = 0 , is not correct

0 ^{-1} = (1 / 0) = ¥ and ¥ ^{-1} = (1 / ¥ ) = 0 are incorrect and 0 ^{-1} is a new number I, the Hyper-infinite number.

1 - Reciprocal Operation with Inequality

a > b

taking the reciprocal of both side causes the > to change to <.

reciprocal of a > b is a^{-1} < b^{-1}

a > b a^{-1} < b^{-1} a b a^{-1} b^{-1} 1 0.25 1.00000 4.00000 1 0.5 1.00000 2.00000 2 1 0.50000 1.00000 2 1.5 0.50000 0.66667 10 5 0.10000 0.20000 10 9 0.10000 0.11111 1000 500 0.00100 0.00200 1000 900 0.00100 0.00111

2 - Apply Reciprocal Operation of Inequality to the Inequality of ¥ ^{-1} > 0

¥ ^{ -1} > 0

the reciprocal of ¥ ^{ -1} > 0 is ¥ < 0^{ -1}

if the inequality ¥ < 0^{ -1} is true, then 0 ^{-1} is a new number, I, and exists outside the set of Real numbers or Hyper-infinite.

the number I is analogous to the number i = Ö -1

3 - Some other additional inequalities and equalities

0 ¹ ¥ ^{ -1}

0^{ -1} ¹ ¥

I = 0^{ -1} Hyper-infinite number

0 ´ I = 1

1 ´ I = I

n ´ I = nI

0 ´ nI = n

a is Real and bI is Hyper-infinite, then the sum of a and bI is complex and is a + bI

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Order is a Subset of Chaos Knowledge is Beyond Belief Wisdom is Not Censored Douglas Paul Smallish Jehocifer

The Quantum Master

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Posted: December 11, 2006, 5:15 am - IP Logged

Something of a proof why ¥ ^{-1} ¹ 0 and ¥ ^{-1} > 0

1 - If ¥ ^{-1} = 0 , then 0 + ¥ ^{-1} = 0

0 + ¥ ^{-1} = 0

0 + ( 1 / ¥ ) = 0

0 ( ¥ / ¥ ) + ( 1 / ¥ ) = 0

( ( 0 * ¥ ) / ¥ ) + ( 1 / ¥ ) = 0

( 0 * ¥ + 1 ) / ¥ = 0

0 * ¥ + 1 = 0 * ¥

( 0 * ¥ ) - ( 0 * ¥ ) + 1 = ( 0 * ¥ ) - ( 0 * ¥ )

0 + 1 = 0

1 = 0

1 = 0 , is false \ ¥ ^{-1} ¹ 0

2 - If ¥ ^{-1} > 0 , then 0 + ¥ ^{-1} > 0

0 + ¥ ^{-1} > 0

0 + ( 1 / ¥ ) > 0

0 ( ¥ / ¥ ) + ( 1 / ¥ ) > 0

( ( 0 * ¥ ) / ¥ ) + ( 1 / ¥ ) > 0

( 0 * ¥ + 1 ) / ¥ > 0

0 * ¥ + 1 > 0 * ¥

( 0 * ¥ ) - ( 0 * ¥ ) + 1 > ( 0 * ¥ ) - ( 0 * ¥ )

0 + 1 > 0

1 > 0

1 > 0 , is true \ ¥ ^{-1} > 0

When dealing with 0 and ¥ it is better to treat them as if they were variables first and do normal math operations first, then work the final equation or inequality. There are times when 0^{2} ¹ 0 and ¥ ^{2} ¹ ¥ , much like X^{2} does not exactly equal X.

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Order is a Subset of Chaos Knowledge is Beyond Belief Wisdom is Not Censored Douglas Paul Smallish Jehocifer

The Quantum Master

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Posted: December 11, 2006, 5:39 am - IP Logged

Also, 0 * ¥ is a non-reduceable number much like 2i is a non-reduceable number, it is what it is, a number all by itself.

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The Quantum Master

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Posted: December 11, 2006, 5:50 am - IP Logged

In addition, ¥ ^{-1} is the infinitesimal unit and is exactly and only exactly the first number after 0.

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Order is a Subset of Chaos Knowledge is Beyond Belief Wisdom is Not Censored Douglas Paul Smallish Jehocifer

The Quantum Master

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Posted: December 11, 2006, 10:04 am - IP Logged

Some more:

n ¥ = ¥

( n ¥ ) / ¥ = ¥ / ¥

n ( ¥ / ¥ ) = ¥ / ¥

n ( 1 ) = 1

n = 1, \ n ¥ = ¥ true when n = 1

n ¥ ¹ ¥

( n ¥ ) / ¥ ¹ ¥ / ¥

n ( ¥ / ¥ ) ¹ ¥ / ¥

n ( 1 ) ¹ 1

n ¹ 1, \ n ¥ ¹ ¥ true when n ¹ 1

n ¥ = -¥

( n ¥ ) / ¥ = -¥ / ¥

n ( ¥ / ¥ ) = -¥ / ¥

n ( 1 ) = -1

n = -1, \ n ¥ = ¥ true when n = -1

n ¥ ¹ -¥

( n ¥ ) / ¥ ¹ -¥ / ¥

n ( ¥ / ¥ ) ¹ -¥ / ¥

n ( 1 ) ¹ -1

n ¹ -1, \ n ¥ ¹ -¥ true when n ¹ -1

Presented 'AS IS' and for Entertainment Purposes Only. Any gain or loss is your responsibility. Use at your own risk.

Order is a Subset of Chaos Knowledge is Beyond Belief Wisdom is Not Censored Douglas Paul Smallish Jehocifer

The Quantum Master

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Posted: December 11, 2006, 10:24 am - IP Logged

And just a bit more:

0 * ¥ = n

( 0 * ¥ ) / ¥ = n / ¥

0 ( ¥ / ¥ ) = n / ¥

0 ( 1 ) = n / ¥

0 = n / ¥ , if and only if n = 0 * ¥

0 * ¥ = n

( 0 * ¥ ) / 0 = n / 0

¥ ( 0 / 0 ) = n / 0

¥ ( 1 ) = n / 0

¥ = n / 0

¥ = n / 0 , if and only if n = 0 * ¥

Presented 'AS IS' and for Entertainment Purposes Only. Any gain or loss is your responsibility. Use at your own risk.

Order is a Subset of Chaos Knowledge is Beyond Belief Wisdom is Not Censored Douglas Paul Smallish Jehocifer

The Quantum Master

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Posted: December 11, 2006, 10:39 am - IP Logged

Quote: Originally posted by on December 11, 2006Some more:

n ¥ = ¥

( n ¥ ) / ¥ = ¥ / ¥

n ( ¥ / ¥ ) = ¥ / ¥

n ( 1 ) = 1

n = 1, \ n ¥ = ¥ true when n = 1

n ¥ ¹ ¥

( n ¥ ) / ¥ ¹ ¥ / ¥

n ( ¥ / ¥ ) ¹ ¥ / ¥

n ( 1 ) ¹ 1

n ¹ 1, \ n ¥ ¹ ¥ true when n ¹ 1

n ¥ = -¥

( n ¥ ) / ¥ = -¥ / ¥

n ( ¥ / ¥ ) = -¥ / ¥

n ( 1 ) = -1

n = -1, \ n ¥ = ¥ true when n = -1

n ¥ ¹ -¥

( n ¥ ) / ¥ ¹ -¥ / ¥

n ( ¥ / ¥ ) ¹ -¥ / ¥

n ( 1 ) ¹ -1

n ¹ -1, \ n ¥ ¹ -¥ true when n ¹ -1

Some more:

n ¥ = ¥

( n ¥ ) / ¥ = ¥ / ¥

n ( ¥ / ¥ ) = ¥ / ¥

n ( 1 ) = 1

n = 1, \ n ¥ = ¥ true when n = 1

n ¥ ¹ ¥

( n ¥ ) / ¥ ¹ ¥ / ¥

n ( ¥ / ¥ ) ¹ ¥ / ¥

n ( 1 ) ¹ 1

n ¹ 1, \ n ¥ ¹ ¥ true when n ¹ 1

n ¥ = -¥

( n ¥ ) / ¥ = -¥ / ¥

n ( ¥ / ¥ ) = -¥ / ¥

n ( 1 ) = -1

n = -1, \ n ¥ = - ¥ true when n = -1 <--- correction from previous post

n ¥ ¹ -¥

( n ¥ ) / ¥ ¹ -¥ / ¥

n ( ¥ / ¥ ) ¹ -¥ / ¥

n ( 1 ) ¹ -1

n ¹ -1, \ n ¥ ¹ -¥ true when n ¹ -1

Presented 'AS IS' and for Entertainment Purposes Only. Any gain or loss is your responsibility. Use at your own risk.

Order is a Subset of Chaos Knowledge is Beyond Belief Wisdom is Not Censored Douglas Paul Smallish Jehocifer

The Quantum Master

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Posted: December 11, 2006, 5:10 pm - IP Logged

The mathematical operation of X / X = 1 must be continuous for all Real values of X; including {-¥ , 0, ¥ }.

1 - If X / X = 1, then -¥ / -¥ = 1

-¥ / -¥ = 1

-¥ = 1 * -¥

-¥ = -¥ , true \ -¥ / -¥ = 1

2 - If X / X ¹ 1, then -¥ / -¥ ¹ 1

-¥ / -¥ ¹ 1

-¥ ¹ 1 * -¥

-¥ ¹ -¥ , false \ -¥ / -¥ = 1

3 - If X / X = 1, then 0 / 0 = 1

0 / 0 = 1

0 = 1 * 0

0 = 0, true \ 0 / 0 = 1

4 - If X / X ¹ 1, then 0 / 0 ¹ 1

0 / 0 ¹ 1

0 ¹ 1 * 0

0 ¹ 0, false \ 0 / 0 = 1

5 - If X / X = 1, then ¥ / ¥ = 1

¥ / ¥ = 1

¥ = 1 * ¥

¥ = ¥ , true \ ¥ / ¥ = 1

6 - If X / X ¹ 1, then ¥ / ¥ ¹ 1

¥ / ¥ ¹ 1

¥ ¹ 1 * ¥

¥ ¹ ¥ , false \ ¥ / ¥ = 1

7 - If Y = 1 and is continuous for all Real values in the function Y = f(X) and f(X) = X / X, then Y = 1 = X / X and is continuous for all Real values

Y = 1 = X / X

Y * X = 1 * X = X

Y * X = 1 * X = X

1 * X = 1 * X = X

X = X = X, true if and only if Y = 1

-¥ = -¥ = -¥ , true if and only if Y = 1

0 = 0 = 0, true if and only if Y = 1

¥ = ¥ = ¥ , true if and only if Y = 1

Presented 'AS IS' and for Entertainment Purposes Only. Any gain or loss is your responsibility. Use at your own risk.

Order is a Subset of Chaos Knowledge is Beyond Belief Wisdom is Not Censored Douglas Paul Smallish Jehocifer

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Posted: December 16, 2006, 8:45 am - IP Logged

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WHEW

I know how to add, subtract and multiply. I think.

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Posted: December 16, 2006, 9:22 am - IP Logged

Mathematics Forum :The place to discuss the strong ties between lotteries and mathematics.

Excuse me, but I think I'm missing the strong tie between lotteries and mathematics in this thread.