math problem worth a million can you answer itPrev Topic Next Topic

New Topic New Poll

lotteryman99

United States
Member #48,599
January 2, 2007
22 Posts
Offline

Jan 22, 2007, 12:26 pm

i have this problem i worked a math system out and and i am down to the finial part and can not get the answer. it involves a numbers system of math, it all lays together and i need to know one thing there is the problem example and i need one digit in any correct spot of each 4 sets if i could do that i could hit any number in any lottery. can you help
set1    set2    set3   set4
7654    1593   4062 3951
7159    7359   4062 9258
9357    1098 8260   3951
each one of these sets represents the first second third and forth digit of a number i know the second digit of the last row always lands in the second spot of the middle row i need a way to find the proper spot of any digit in each row this is worth millions if it could be broke. each number of the lottery has a diffrent four sets i will share this with anyone who breaks it.
winsumloosesum

Philadelpia/Pennsylvania
United States
Member #2,218
September 1, 2003
6,803 Posts
Offline

Jan 22, 2007, 1:25 pm

Quote: Originally posted by lotteryman99 on Jan 22, 2007
i have this problem i worked a math system out and and i am down to the finial part and can not get the answer. it involves a numbers system of math, it all lays together and i need to know one thing there is the problem example and i need one digit in any correct spot of each 4 sets if i could do that i could hit any number in any lottery. can you help
set1    set2    set3   set4
7654    1593   4062 3951
7159    7359   4062 9258
9357    1098 8260   3951
each one of these sets represents the first second third and forth digit of a number i know the second digit of the last row always lands in the second spot of the middle row i need a way to find the proper spot of any digit in each row this is worth millions if it could be broke. each number of the lottery has a diffrent four sets i will share this with anyone who breaks it.

LM99,
Can you explain "The second digit of the last row always lands in the second spot of the middle row"?
Thanks!!
truecritic

Michigan
United States
Member #22,394
September 24, 2005
1,583 Posts
Offline

Jan 22, 2007, 2:01 pm

Yes, if you could explain by way of an example that would help.
lotteryman99

United States
Member #48,599
January 2, 2007
22 Posts
Offline

Jan 22, 2007, 2:07 pm

look in the last row in each set of numbers (set 1 for example)bottom set of numbers, the second digit of the four digits in that row will be in the second spot of the middle set
7654 1593 4062 3951
7159 7395 4062 9258
9357 1098 8260 3951
four4me

MD
United States
Member #1,701
June 18, 2003
10,731 Posts
Offline

Jan 22, 2007, 2:14 pm

if you are using an even number of digits in your wheel/system try using and odd number of digits.
many times i had this problem wheeling even amounts of digits i continuously get repeat
numbers. Using an odd amount solved it for me.
lotteryman99

United States
Member #48,599
January 2, 2007
22 Posts
Offline

Jan 22, 2007, 2:15 pm

i could tell you what all this means but if i did that i would be putting you on the same course of thought that i am at what i need is a new look at it and a new approch i have been toying with this for years and i understand what ever digit means.. it all leads to stright 3 digit and stright 4 digits, lotto numbers keno and the works.
winsumloosesum

Philadelpia/Pennsylvania
United States
Member #2,218
September 1, 2003
6,803 Posts
Offline

Jan 22, 2007, 2:16 pm

Quote: Originally posted by lotteryman99 on Jan 22, 2007
look in the last row in each set of numbers (set 1 for example)bottom set of numbers, the second digit of the four digits in that row will be in the second spot of the middle set
7654 1593 4062 3951
7159 7395 4062 9258
9357 1098 8260 3951

Ok that's what I thought.
Does each 4 digit number in each set represent something?
4062 is listed twice in set 3
3951 is listed twice in set4
"5"s constant in the 3rd position of each combination in set 1
"9"'s " "                                                                            set 2
"6"s " "                                                                            set 3
"5"s " "                                                                               set 4
lotteryman99

United States
Member #48,599
January 2, 2007
22 Posts
Offline

Jan 22, 2007, 2:18 pm

four4me
the odd and even are the mirror to each other this doubles the amount of numbers that one would have to play odd and even on each one would go from 1 number to 16 and ect.
lotteryman99

United States
Member #48,599
January 2, 2007
22 Posts
Offline

Jan 22, 2007, 2:48 pm

the constant digits that you are seeing are the added total of the three digit number in that case
more info.
in this number the three digit number was 294 added total is 15
the five is the total
7654
7159
9357
winsumloosesum

Philadelpia/Pennsylvania
United States
Member #2,218
September 1, 2003
6,803 Posts
Offline

Jan 22, 2007, 3:05 pm

Quote: Originally posted by lotteryman99 on Jan 22, 2007
the constant digits that you are seeing are the added total of the three digit number in that case
more info.
in this number the three digit number was 294 added total is 15
the five is the total
7654
7159
9357

The 3rd digit of each four number combination is always the root sum??
What do the rest of the numbers represent?
Thanks!!
lotteryman99

United States
Member #48,599
January 2, 2007
22 Posts
Offline

Jan 23, 2007, 1:56 pm

is this a question or a fact that the third digit of each set is the root sum??
lotteryman99

United States
Member #48,599
January 2, 2007
22 Posts
Offline

Jan 23, 2007, 2:02 pm

is this a question or a fact that the third digit is always the root sum
winsumloosesum

Philadelpia/Pennsylvania
United States
Member #2,218
September 1, 2003
6,803 Posts
Offline

Jan 23, 2007, 4:14 pm

Quote: Originally posted by lotteryman99 on Jan 22, 2007
the constant digits that you are seeing are the added total of the three digit number in that case
more info.
in this number the three digit number was 294 added total is 15
the five is the total
7654
7159
9357

LM99,
This was your post 294 = 15
I just asked the question.
Could you explain how you get the 4 sets of 4 digit numbers??
winsum
retxx

BOSTON
United States
Member #48
September 9, 2001
3,954 Posts
Offline

Jan 23, 2007, 11:08 pm

my question is how it relates to keno peaked my interest greatly if you could explain that. thanks hope someone solves your problem. looks quite interesting.
lotteryman99

United States
Member #48,599
January 2, 2007
22 Posts
Offline

Jan 28, 2007, 8:46 pm

thanks everyone but i believe the answer is no answer because all systems and numbers are randon

New Topic New Poll

Subscribe to this topic

math problem worth a million can you answer itPrev TopicNext Topic

math problem worth a million can you answer itPrev Topic Next Topic