So if all RS have same amout of combos by playing one RS that would lower your odds to 1 in 144444 approx if that RS hits.
Given that the draw is in its infancy, a few numbers have not been drawn and there is a chance that 4 of those numbers will come together.
Right now 2 of the O/E combos have not hit being.
OEEE
and EEEE
so a all E would be the easies play as is a all odd,
How often will they happen, which happens most?
Cant answer that yet,
so best bet for now all E and use number that have not hit.
Also note that we have not had a repeat number yet.
Rs that hit, 5,9,6,9,7,( all high RS) 5 being (Med)
My guess is RS 3 next.
so sums 12 being 1,2,3,6 at the low end and sums,21,30,39,48,57,66,75,84,93,102,111,
120,129, 138,147,156,165,174,183,192,201,210,219,228,237,246,255,264,273,282,291
300.
302 is the highest sum which would be 74,75,76,77
so sum 300 would bee 72,75,76,77
so 32 sums for RS 3 Know we know as we proceed down the sum list as we get to the middle we have more possible combos per sum with the middle most likely the highes so
we could say the most likely place the hits will come from for RS 3 would be the sums 156 and each side but if we have 32 sums per RS then we could say 144444/32 we could say some sums will have 4513 combos . some less. Now also those combos can be broken down further, to O/E and H/L