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# Pairs Probabilities and Entry Points

Topic closed. 4 replies. Last post 9 years ago by Thoth.

 Page 1 of 1
Pennsylvania
United States
Member #2218
September 1, 2003
5396 Posts
Offline
 Posted: July 18, 2007, 8:37 am - IP Logged

Ok, math geniuses out there in LP Land I know your out there!!

Here is my question:

In a Pick 3 game there are 3 Pairs

1. Front Pair

2. Back Pair

3. Side Pair

There are a total of 100 Pairs (00 through 99)

In boxed form there are a total of 55.

So, in any Pick 3 drawing you have 3 chances of picking 1 correct "boxed" pair from a bag of 55 balls.

What is the percentage or probability of picking 1 boxed pair from one Pick 3 drawing?

What would be an "Entry Point" to play a boxed pair when that pair reached a certain skip?

What if you had a "sector" of Pairs in which each Pair had a skip of 30 or more.

For example:  suppose Pairs 14, 15, and 16 skipped a minimum of 30 drawings.  (Pair 14 = 30 skips, Pair 15=30 skips, Pair 16=30 skips)

What if you had consecutive "sectors" of 4, 5, or 6 Pairs that where equal to or above 30 or more skips?  What would be the "Entry Point" to start playing these Pairs? 50, 60, 70 Skips??

1. 00

2. 01

3. 02

4. 03

5. 04

6. 05

7. 06

8. 07

9. 08

10. 09

11. 11

12. 12

13. 13

14. 14

15. 15

16. 16

17. 17

18. 18

19. 19

20. 22

21. 23

22. 24

23. 25

24. 26

25. 27

26. 28

27. 29

28. 33

29. 34

30. 35

31. 36

32. 37

33. 38

34. 39

35. 44

36. 45

37. 46

38. 47

39. 48

40. 49

41. 55

42. 56

43. 57

44. 58

45. 59

46. 66

47. 67

48. 68

49. 69

50. 77

51. 78

52. 79

53. 88

54. 89

55. 99

Thanks!!

wsls

ORLANDO, FLORIDA
United States
Member #4924
June 3, 2004
5976 Posts
Offline
 Posted: July 18, 2007, 3:20 pm - IP Logged

Ok, math geniuses out there in LP Land I know your out there!!

Here is my question:

In a Pick 3 game there are 3 Pairs

1. Front Pair

2. Back Pair

3. Side Pair

There are a total of 100 Pairs (00 through 99)

In boxed form there are a total of 55.

So, in any Pick 3 drawing you have 3 chances of picking 1 correct "boxed" pair from a bag of 55 balls.

What is the percentage or probability of picking 1 boxed pair from one Pick 3 drawing?

What would be an "Entry Point" to play a boxed pair when that pair reached a certain skip?

What if you had a "sector" of Pairs in which each Pair had a skip of 30 or more.

For example:  suppose Pairs 14, 15, and 16 skipped a minimum of 30 drawings.  (Pair 14 = 30 skips, Pair 15=30 skips, Pair 16=30 skips)

What if you had consecutive "sectors" of 4, 5, or 6 Pairs that where equal to or above 30 or more skips?  What would be the "Entry Point" to start playing these Pairs? 50, 60, 70 Skips??

1. 00

2. 01

3. 02

4. 03

5. 04

6. 05

7. 06

8. 07

9. 08

10. 09

11. 11

12. 12

13. 13

14. 14

15. 15

16. 16

17. 17

18. 18

19. 19

20. 22

21. 23

22. 24

23. 25

24. 26

25. 27

26. 28

27. 29

28. 33

29. 34

30. 35

31. 36

32. 37

33. 38

34. 39

35. 44

36. 45

37. 46

38. 47

39. 48

40. 49

41. 55

42. 56

43. 57

44. 58

45. 59

46. 66

47. 67

48. 68

49. 69

50. 77

51. 78

52. 79

53. 88

54. 89

55. 99

Thanks!!

wsls

Steve, I found this post about pairs made by Thoth. Maybe it's a start.

United States
Member #16612
June 2, 2005
3493 Posts
Offline
 Posted: July 19, 2007, 1:56 pm - IP Logged

Are you talking about Pick 3, Pick 4, or both?

New York, NY
United States
Member #39471
May 16, 2006
2698 Posts
Offline
 Posted: July 19, 2007, 2:26 pm - IP Logged

Ok, math geniuses out there in LP Land I know your out there!!

Here is my question:

In a Pick 3 game there are 3 Pairs

1. Front Pair

2. Back Pair

3. Side Pair

There are a total of 100 Pairs (00 through 99)

In boxed form there are a total of 55.

So, in any Pick 3 drawing you have 3 chances of picking 1 correct "boxed" pair from a bag of 55 balls.

What is the percentage or probability of picking 1 boxed pair from one Pick 3 drawing?

What would be an "Entry Point" to play a boxed pair when that pair reached a certain skip?

What if you had a "sector" of Pairs in which each Pair had a skip of 30 or more.

For example:  suppose Pairs 14, 15, and 16 skipped a minimum of 30 drawings.  (Pair 14 = 30 skips, Pair 15=30 skips, Pair 16=30 skips)

What if you had consecutive "sectors" of 4, 5, or 6 Pairs that where equal to or above 30 or more skips?  What would be the "Entry Point" to start playing these Pairs? 50, 60, 70 Skips??

1. 00

2. 01

3. 02

4. 03

5. 04

6. 05

7. 06

8. 07

9. 08

10. 09

11. 11

12. 12

13. 13

14. 14

15. 15

16. 16

17. 17

18. 18

19. 19

20. 22

21. 23

22. 24

23. 25

24. 26

25. 27

26. 28

27. 29

28. 33

29. 34

30. 35

31. 36

32. 37

33. 38

34. 39

35. 44

36. 45

37. 46

38. 47

39. 48

40. 49

41. 55

42. 56

43. 57

44. 58

45. 59

46. 66

47. 67

48. 68

49. 69

50. 77

51. 78

52. 79

53. 88

54. 89

55. 99

Thanks!!

wsls

No math genius but here goes:

"What is the percentage or probability of picking 1 boxed pair from one Pick 3 drawing?"

Do you mean the P of picking a correct --ie drawn --pair?

1. It's still 1/55!

2.  Good question about skips--Remember any one draw utilizes 3 pairs. In 19 draws the full universe of pairs could be potentially drawn! I would start on the 20th game.

3. At this point pairs skips should be compared to digit skips for more effective tracking.

Interesting observation: the prob of selecting 2 correct pairs in any P3 draw is the same as selecting a winning boxed combination. IOone cannot choose 2 pairs without choosing 3. the third one is derivative.

\$\$\$

Findlay, Ohio
United States
Member #4855
May 28, 2004
400 Posts
Offline
 Posted: August 4, 2007, 3:04 am - IP Logged

This an old post but I just now came across it.  The probability of guessing one boxed pair is 56 in 1,000 or 5.6%.  The 50% median is 12.02773 games...meaning that theres a lilttle better than a 50% chance that when you see that boxed pair hit, it will hit again within 13 games.  Of course, that probability is for a "no-match" boxed pair (two different digits).

A double digit boxed pair has a probability of 28 in 1,000 or 2.8%, which gives it a median of about 25 games.

You can "DC" groups of boxed pairs (like your sectoring idea), just remember to take out possible duplicates or overlap when you calculate their amounts.

~Probability=Odds in Motion~

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