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# consecutive numb odds?

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Israel
Member #48063
December 8, 2006
5 Posts
Offline
 Posted: October 7, 2007, 11:45 am - IP Logged

lottery 6/34

on 02.oct  lottery draw was:

1,2,3,5,33,34

so we have: 1 triplets (1,2,3) + 1 double 33,34 & one or more  1 prize winner (and many people think -lottery fixed*)

i want to know how to calculate the odds for in one draw was 1,2,3 and 33,34 (triplets &double).

and what the odds to have 1 triple  in draw

and 1 double in draw. i knew it is not  same like the odds to have 2/6/34 =1:4? or not?

The Quantum Master
West Concord, MN
United States
Member #21
December 7, 2001
3675 Posts
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 Posted: October 7, 2007, 4:23 pm - IP Logged

I actually worked this out for Pick 5 and Pick 6 lotteries last year sometime for any pool size.

 Total Count of Consecutive Numbers in a draw for 6 of 34 6 5 4 3 2 0 29 2030 36540 237510 593775 475020

 Percent Probability of having the given quantity of Consecutive Numbers in a draw for 6 of 34 6 5 4 3 2 0 0.00216% 0.15094% 2.71692% 17.66000% 44.14999% 35.31999%

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