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consecutive numb odds?

Topic closed. 1 reply. Last post 9 years ago by JADELottery.

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Israel
Member #48063
December 8, 2006
5 Posts
Offline
Posted: October 7, 2007, 11:45 am - IP Logged

lottery 6/34 

on 02.oct  lottery draw was:

1,2,3,5,33,34

 so we have: 1 triplets (1,2,3) + 1 double 33,34 & one or more  1 prize winner (and many people think -lottery fixed*No Pity!)

i want to know how to calculate the odds for in one draw was 1,2,3 and 33,34 (triplets &double).

and what the odds to have 1 triple  in draw

and 1 double in draw. i knew it is not  same like the odds to have 2/6/34 =1:4? or not?

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    JADELottery's avatar - MeAtWork 03.PNG
    The Quantum Master
    West Concord, MN
    United States
    Member #21
    December 7, 2001
    3675 Posts
    Offline
    Posted: October 7, 2007, 4:23 pm - IP Logged

    I actually worked this out for Pick 5 and Pick 6 lotteries last year sometime for any pool size.

     

    Total Count of Consecutive Numbers in a draw for 6 of 34
    654320
    29203036540237510593775475020

     

    Percent Probability of having the given quantity of Consecutive Numbers in a draw for 6 of 34
    654320
    0.00216%0.15094%2.71692%17.66000%44.14999%35.31999%

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