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filter system to reduce numbers

Topic closed. 10 replies. Last post 8 years ago by GetdaLotto.

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Alexandria, Virginia
United States
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January 4, 2008
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 Posted: August 13, 2008, 4:51 pm - IP Logged

I read the post that explains a way of reducing numbers to be played that was:

If you use just the Single numbers each draw you can end up with only 527 numbers to look at.

Most of the time digits do not repeat on top of them-self !

For example ....  say the draw today was 123 in that order.

If we filter out all the numbers that contain digit 1 in first position.....2 in 2nd position and ......3 in the 3rd position then it leaves us with only 527 straight numbers to consider instead of 1000 or 720 if we don't use doubles.

Now can anybody help me with a filter system that can do the work easily.  A filter system that can filter out the numbers.  any help will be apreciated.  THanks

ORLANDO, FLORIDA
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June 3, 2004
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 Posted: August 13, 2008, 5:24 pm - IP Logged

I read the post that explains a way of reducing numbers to be played that was:

If you use just the Single numbers each draw you can end up with only 527 numbers to look at.

Most of the time digits do not repeat on top of them-self !

For example ....  say the draw today was 123 in that order.

If we filter out all the numbers that contain digit 1 in first position.....2 in 2nd position and ......3 in the 3rd position then it leaves us with only 527 straight numbers to consider instead of 1000 or 720 if we don't use doubles.

Now can anybody help me with a filter system that can do the work easily.  A filter system that can filter out the numbers.  any help will be apreciated.  THanks

United States
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June 22, 2005
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 Posted: August 13, 2008, 7:10 pm - IP Logged

You can reduce those 527  numbers down to 81.

Using your example of eliminating 123 from the list, we would end up with the following:

For 9 bucks, you will have a 1 in 81 chance of winning straight if you get the last 2 numbers correct in that order. First make a list vertically from 0-9, without the number 1 in the first position:

0

2

3

4

5

6

7

8

9

Then just add the next 2 numbers you think will come out in the second and third positions. Let's say I think the numbers 38 will come out. Remember to leave out 2 and 3 in the last 2 positions:

038

238

338

438

538

638

738

838

938

If we assume that 1,2,and 3 will not repeat in their respective positions, then the first column which has 0-2-3-4-5-6-7-8-9, will have one of those numbers come out, so we don't count it in our computation.

We now only have to contend with the second and third positions which have 9 numbers each. 9x9=81.

NASHVILLE, TENN
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February 20, 2006
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 Posted: August 13, 2008, 8:38 pm - IP Logged

If you took another digit, say 9 in the second position, and removed all the combinations that contained that 9 in that position, how many combinations would you have remaining?

United States
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June 22, 2005
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 Posted: August 13, 2008, 9:50 pm - IP Logged

If you took another digit, say 9 in the second position, and removed all the combinations that contained that 9 in that position, how many combinations would you have remaining?

So that would be 2 numbers taken out in the second position leaving you only with eight combos left. It just keeps getting better...lol

United States
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June 22, 2005
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 Posted: August 13, 2008, 9:51 pm - IP Logged

One in seventy-two. I hope that helped..lol

joplin
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August 17, 2006
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 Posted: August 13, 2008, 10:10 pm - IP Logged

What if you were to eliminate the last 6 months of singles, since they seldom repeat, wouldn't that

cut the odds even more?

United States
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June 22, 2005
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 Posted: August 13, 2008, 11:23 pm - IP Logged

What if you were to eliminate the last 6 months of singles, since they seldom repeat, wouldn't that

cut the odds even more?

Yes, it would reduce the odds that much more. Have fun !.....LOL

Just joking....

There is a plethora of filters available, but too many might block out the needeed number or desired outcome, thus negating any beneficial qualities. Discernment is key.

Alexandria, Virginia
United States
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January 4, 2008
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 Posted: August 14, 2008, 9:55 am - IP Logged

Hey carbob, thanks for posting.  I did browse through but I did not see a link for downloading a tool that could help.  I did not see anything to download anywhere.  It contains lots of useful information but nothing to download.  It talks about free positional wheel to creat numbers but I do not know where to get it.  So please a little more help will be very kind.  thankx amillion

ORLANDO, FLORIDA
United States
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June 3, 2004
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 Posted: August 14, 2008, 9:59 am - IP Logged

Hey carbob, thanks for posting.  I did browse through but I did not see a link for downloading a tool that could help.  I did not see anything to download anywhere.  It contains lots of useful information but nothing to download.  It talks about free positional wheel to creat numbers but I do not know where to get it.  So please a little more help will be very kind.  thankx amillion

On page 1 of that thread, click the image!!!!

Alexandria, Virginia
United States
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January 4, 2008
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 Posted: August 14, 2008, 10:20 am - IP Logged

Thanks a gazillion!!  Yes I got.  I was actualy looking at first page all that time.  Did not look at the previous page.  Thanks for all the help.  Yu Roc.

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