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Topic closed. 6 replies. Last post 8 years ago by anonimos777.

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New Member
Athens
Greece
Member #61355
May 20, 2008
4 Posts
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 Posted: September 24, 2008, 12:15 pm - IP Logged

Hello to eveyone,

this is my first post, but I am "watching" this forum for a year now, and I trully believe that is one of the best.

I usally watch & play pick 3, but I have found something strange and I would like to ask 2 questions.

Here in Greece (forgive me for my english also) we have a 5/35 lottery that called extra 5

I have a prediction method (let's say) that gives me 20 numbers which in the next 10 to 12 draws will produce a 5/5 win

So my questions are:

1.) Is this something common? (Meaning that if someone pick 20 random numbers out of 35 can produce 5/5 easily?)

2.) If you knew that 20 numbers what would you do? (I know about wheeling systems but something like 20,5,5 would be very expensive..)

Basicly I have't got any deep knowledge about this game and I don't know if what I have found is good enough, or what...

Thanks

United States
Member #13130
March 30, 2005
2171 Posts
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 Posted: September 24, 2008, 1:15 pm - IP Logged

Xerete,

There are 3,247,943,160 ways to pull 20 numbers out of a pool of 35 numbers.

If you pull out the 5 correct numbers, then you are left with pulling out 15 more numbers from a pool of the 30 numbers that remain. There are 155,117,520 ways to do so.

This leaves you with:

155,117,520 ways to have all 5 winners among your 20 numbers
---------------- divided by
3,247,943,160 ways to pull any 20 numbers out of a pool of 35 numbers

equals 4.775% of all possible '35 choose 20' groups will contain all 5 winners.

In neo-conned Amerika, bank robs you.
Alcohol, Tobacco, and Firearms should be the name of a convenience store, not a govnoment agency.

Dallas, TX
United States
Member #60284
April 12, 2008
3856 Posts
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 Posted: September 24, 2008, 9:31 pm - IP Logged

Yes, it is possible to have 5 out of 35 correct with the odds being 1 in 324,632. If you knew that 5 within the 20 numbers that hit, that's leaving you 1 in 15,504. Wheeling is the best way, however you must narrow down your numbers even further to say 10 (1 in 252) - 12 (1 in 792) numbers for better odds. In lottorey odds are agaisnt you, so having good odds on your side is the first logic way to play. You can wheel the 10 - 12 numbers and select the best from the wheel based upon your play budget per draw.

United States
Member #13130
March 30, 2005
2171 Posts
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 Posted: September 25, 2008, 4:58 am - IP Logged
 right of 5 ways times wrong of 30 ways gives in total gives in % 0 1 x 20 30,045,015 30,045,015 00.93% 1 5 x 19 54,627,300 273,136,500 08.41% 2 10 x 18 86,493,225 864,932,250 26.63% 3 10 x 17 119,759,850 1,197,598,500 36.87% 4 5 x 16 145,422,675 727,113,375 22.39% 5 1 x 15 155,117,520 155,117,520 04.78% total 3,247,943,160 100.00%

In neo-conned Amerika, bank robs you.
Alcohol, Tobacco, and Firearms should be the name of a convenience store, not a govnoment agency.

New Member
Athens
Greece
Member #61355
May 20, 2008
4 Posts
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 Posted: October 1, 2008, 12:57 am - IP Logged

Thank you both for your answers - what I see is that I have to reduce my numbers at least to 15 -

Chesapeake, VA
United States
Member #65042
September 15, 2008
63 Posts
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 Posted: October 1, 2008, 3:54 pm - IP Logged

To help you out a bit, check the last 10 draws, average out the width of line and the sum of all numbers. Also make sure to have 2/3 odd/even, high/low and vice versa. Use the averages to base your combinations. Good luck.

Its like poker: you can play your best but you gotta know when to fold your cards and take a rest. Hold your cards, take a breath, and hope that nobody else is stacking the deck.

New Member
Athens
Greece
Member #61355
May 20, 2008
4 Posts
Offline
 Posted: October 2, 2008, 3:31 am - IP Logged

To help you out a bit, check the last 10 draws, average out the width of line and the sum of all numbers. Also make sure to have 2/3 odd/even, high/low and vice versa. Use the averages to base your combinations. Good luck.

Thanks!

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