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Numbers question

Topic closed. 6 replies. Last post 10 years ago by JKING.

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United States
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June 22, 2005
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 Posted: November 11, 2008, 12:56 pm - IP Logged

The odds in Floroda Fantasy Five, are about 1 in 376,000. The game is 1-36. What I'd like to know is, if I eliminate the first two numbers in the selection of five total, what would the new odds be?

For example. You have to pick 5 numbers correct to win. What if the game was only 3 numbers to win, but still had 1-36. So let's say, I would pick 3-8-30. What would the odds of winning be now?

I ask this because I'm testing a strategy that costs only 25 bucks to cover the first 2 numbers and I'm wondering if it would be worth the money spent, if the odds were greatly reduced by only having to contend with the last 3 remaining numbers.

Thanx.

P.S. I could probably figure it out myself, but would take too long. I'm sure there's a math wiz here somewhere..

Norway
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December 10, 2004
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 Posted: November 11, 2008, 4:43 pm - IP Logged

Something like this: (34/3)*(33/2)*(32/1)= 5984:1

South Carolina
United States
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November 4, 2001
8847 Posts
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 Posted: November 11, 2008, 4:46 pm - IP Logged

It usualy tells on the back of the card you make out what the odds are.

0*1*2*3*4*5*6*7*8*9

EEE EEO EOE OEE OOE OEO EOO OOO

Kentucky
United States
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February 14, 2006
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 Posted: November 11, 2008, 5:05 pm - IP Logged

The odds in Floroda Fantasy Five, are about 1 in 376,000. The game is 1-36. What I'd like to know is, if I eliminate the first two numbers in the selection of five total, what would the new odds be?

For example. You have to pick 5 numbers correct to win. What if the game was only 3 numbers to win, but still had 1-36. So let's say, I would pick 3-8-30. What would the odds of winning be now?

I ask this because I'm testing a strategy that costs only 25 bucks to cover the first 2 numbers and I'm wondering if it would be worth the money spent, if the odds were greatly reduced by only having to contend with the last 3 remaining numbers.

Thanx.

P.S. I could probably figure it out myself, but would take too long. I'm sure there's a math wiz here somewhere..

There are 7140 combinations in a 3/36 game. [(36x35x34)/(3x2x1)]

United States
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October 22, 2005
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 Posted: November 11, 2008, 5:24 pm - IP Logged

It is never a good stratergy when you play the lottery to try and cover all the numbers - That is were the challenge is. Pick a corner and stay there. Good luck

United States
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June 22, 2005
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 Posted: November 11, 2008, 6:02 pm - IP Logged

I appreciate the responses..thanx.

So there's about 7,000. Good deal. Now I can work on reducing it even further down to about a thousand to 1.

United States
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July 13, 2004
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 Posted: November 11, 2008, 7:35 pm - IP Logged
 NUM COMB 5 1 6 6 7 21 8 56 9 126 10 252 11 462 12 792 13 1287 14 2002 15 3003 16 4368 17 6188 18 8568 19 11628 20 15504 21 20349 22 26334 23 33649 24 42504 25 53130 26 65780 27 80730 28 98280 29 118755 30 142506 31 169911 32 201376 33 237336 34 278256 35 324632 36 376992 37 435897 38 501942 39 575757 40 658008 41 749398 42 850668 43 962598 44 1086008 45 1221759 46 1370754 47 1533939 48 1712304 49 1906884 50 2118760 51 2349060 52 2598960 53 2869685 54 3162510 55 3478761 56 3819816 57 4187106 58 4582116 59 5006386 60 5461512

You are a slave to the choices you have made.  jk

Even a blind squirrel will occasionally find an acorn.

There is no elevator to success, you will have to take the stairs.

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