In Pick 3 ...... each of the 10 digits should average a hit about 10% of the time. Sometimes digits go missing for long times ...... sometimes more than one digit is absent....... sometimes 3 digits go missing all at the same time.
In the three examples below ....each State is missing 3 digits at the same time.......some more than others.
1. MO MIDDAy ......missing 3 digits digits 1,,, 6,,,,and 8 14 draws ...10 ...and 5
2. GA. Midday .......missing 3 digits digits 4,,,1,,,and 3 14 draws....7...and 2
3. ILL midday........missing digits 8,,,1,,,and 4 8 draws ...6 ....and 6
The question is ...... how do we figure the most due group .....(group of 3 digits) ?
If 1 digit is missing thats 271 absent straight numbers.
If 2 digits are missing together at the same time its 488 numbers.
If 3 digits are missing at the same time .....its 657 absent numbers.
It's hard to hide 657 numbers for very long in the pick 3 .... Right ?
So.... here's the question.
Which of the 3 State's is most due a hit from at least one of the 3 missing digits groups?
ILL is missng more Straights (657) for the longest time ...... 6 draws total .... but ..... is it the most due?
or.....is it MO Midday ?